[jira] [Created] (CASSANDRA-12621) How to query '%' character using LIKE operator in Cassandra 3.7?

["Mikhail Krupitskiy (JIRA)" <ji...@apache.org>]

Mikhail Krupitskiy created CASSANDRA-12621:
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             Summary: How to query '%' character using LIKE operator in Cassandra 3.7?
                 Key: CASSANDRA-12621
                 URL: https://issues.apache.org/jira/browse/CASSANDRA-12621
             Project: Cassandra
          Issue Type: Bug
            Reporter: Mikhail Krupitskiy
            Priority: Critical


I use Cassandra 3.7 and have a text column with SASI index. Let's assume that I want to find column values that contain '%' character somewhere in the middle. The problem is that '%' is a command char for LIKE clauses. How to escape '%' char in a query like LIKE '%%%'?

Here is a test script:

DROP keyspace if exists kmv;
CREATE keyspace if not exists kmv WITH REPLICATION = { 'class' : 'SimpleStrategy', 'replication_factor':'1'} ;
USE kmv;
CREATE TABLE if not exists kmv (id int, c1 text, c2 text, PRIMARY KEY(id, c1));
CREATE CUSTOM INDEX ON kmv.kmv  ( c2 ) USING 'org.apache.cassandra.index.sasi.SASIIndex' WITH OPTIONS = {
'analyzed' : 'true',
'analyzer_class' : 'org.apache.cassandra.index.sasi.analyzer.NonTokenizingAnalyzer',
'case_sensitive' : 'false', 
'mode' : 'CONTAINS'
};

INSERT into kmv (id, c1, c2) values (1, 'f22', 'qwe%asd');

SELECT c2 from kmv.kmv where c2 like '%$$%$$%';

The select query returns nothing.



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