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Posted to log4j-user@logging.apache.org by Philippe Waltregny <ph...@nrb.be> on 2004/07/26 14:24:14 UTC
log4j - XMLLayout - output.
Hello,
I'm trying to use log4j's XMLLayout as documented.
Here are my source codes:
1) File log4j-events
<log4j:event logger="java.logging.log4j.Test" timestamp="1089795669140"
level="DEBUG" thread="main">
<log4j:message><![CDATA[Hello World!]]></log4j:message>
<log4j:locationInfo class="java.logging.log4j.Test" method="execute"
file="Test.java" line="36"/>
</log4j:event>
<log4j:event logger="java.logging.log4j.Test" timestamp="1089795697406"
level="DEBUG" thread="main">
<log4j:message><![CDATA[Hello World!]]></log4j:message>
<log4j:locationInfo class="java.logging.log4j.Test" method="execute"
file="Test.java" line="36"/>
</log4j:event>
2) File log4j.xml
<?xml version="1.0" encoding="ISO-8859-1" ?>
<!DOCTYPE log4j:eventSet SYSTEM "log4j.dtd"
[
<!ENTITY logEntity SYSTEM "log4j-events">
]>
<log4j:eventSet
version="1.2"
xmlns:log4j="http://jakarta.apache.org/log4j/">
&logEntity;
</log4j:eventSet>
Here is the result when I open the log4j.xml file in Microsoft Internet Explorer
6.0:
The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then
click the Refresh button, or try again later.
--------------------------------------------------------------------------------
Reference to undeclared namespace prefix: 'log4j'. Error processing resource
'file:///C:/java/logging/log4j/log/log4j-events.xml'. Line 1, Position 108
<log4j:event logger="java.logging.log4j.Test" timestamp="1089795669140"
level="DEBUG" thread="main">
Would you please tell me what's wrong?
Thank you.
Philippe Waltregny-Dengis
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