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Posted to dev@spark.apache.org by 163 <he...@163.com> on 2017/11/23 03:09:52 UTC

SparkSQL not support CharType

Hi,
     when I use Dataframe with table schema, It goes wrong:

val test_schema = StructType(Array(
  StructField("id", IntegerType, false),
  StructField("flag", CharType(1), false),
  StructField("time", DateType, false)));

val df = spark.read.format("com.databricks.spark.csv")
  .schema(test_schema)
  .option("header", "false")
  .option("inferSchema", "false")
  .option("delimiter", ",")
  .load("file:///Users/name/b")

The log is below:
Exception in thread "main" scala.MatchError: CharType(1) (of class org.apache.spark.sql.types.CharType)
	at org.apache.spark.sql.catalyst.encoders.RowEncoder$.org$apache$spark$sql$catalyst$encoders$RowEncoder$$serializerFor(RowEncoder.scala:73)
	at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$2.apply(RowEncoder.scala:158)
	at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$2.apply(RowEncoder.scala:157)

Why? Is this a bug?

	But I found spark will translate char type to string when using create table command:

     			 create table test(flag char(1));
      			desc test:            flag string;

    


Regards
Wendy He

Re: SparkSQL not support CharType

Posted by Jörn Franke <jo...@gmail.com>.
Or bytetype depending on the use case 

> On 23. Nov 2017, at 10:18, Herman van Hövell tot Westerflier <hv...@databricks.com> wrote:
> 
> You need to use a StringType. The CharType and VarCharType are there to ensure compatibility with Hive and ORC; they should not be used anywhere else.
> 
>> On Thu, Nov 23, 2017 at 4:09 AM, 163 <he...@163.com> wrote:
>> Hi,
>>      when I use Dataframe with table schema, It goes wrong:
>> 
>> val test_schema = StructType(Array(
>>   StructField("id", IntegerType, false),
>>   StructField("flag", CharType(1), false),
>>   StructField("time", DateType, false)));
>> 
>> val df = spark.read.format("com.databricks.spark.csv")
>>   .schema(test_schema)
>>   .option("header", "false")
>>   .option("inferSchema", "false")
>>   .option("delimiter", ",")
>>   .load("file:///Users/name/b")
>> 
>> The log is below:
>> Exception in thread "main" scala.MatchError: CharType(1) (of class org.apache.spark.sql.types.CharType)
>> 	at org.apache.spark.sql.catalyst.encoders.RowEncoder$.org$apache$spark$sql$catalyst$encoders$RowEncoder$$serializerFor(RowEncoder.scala:73)
>> 	at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$2.apply(RowEncoder.scala:158)
>> 	at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$2.apply(RowEncoder.scala:157)
>> 
>> Why? Is this a bug?
>> 
>> 	But I found spark will translate char type to string when using create table command:
>> 
>>      			 create table test(flag char(1));
>>       			desc test:            flag string;
>> 
>>     
>> 
>> 
>> Regards
>> Wendy He
> 
> 
> 
> -- 
> Herman van Hövell
> Software Engineer
> Databricks Inc.
> hvanhovell@databricks.com
> +31 6 420 590 27
> databricks.com
> 
> 
> 
> 

Re: SparkSQL not support CharType

Posted by Jörn Franke <jo...@gmail.com>.
Or bytetype depending on the use case 

> On 23. Nov 2017, at 10:18, Herman van Hövell tot Westerflier <hv...@databricks.com> wrote:
> 
> You need to use a StringType. The CharType and VarCharType are there to ensure compatibility with Hive and ORC; they should not be used anywhere else.
> 
>> On Thu, Nov 23, 2017 at 4:09 AM, 163 <he...@163.com> wrote:
>> Hi,
>>      when I use Dataframe with table schema, It goes wrong:
>> 
>> val test_schema = StructType(Array(
>>   StructField("id", IntegerType, false),
>>   StructField("flag", CharType(1), false),
>>   StructField("time", DateType, false)));
>> 
>> val df = spark.read.format("com.databricks.spark.csv")
>>   .schema(test_schema)
>>   .option("header", "false")
>>   .option("inferSchema", "false")
>>   .option("delimiter", ",")
>>   .load("file:///Users/name/b")
>> 
>> The log is below:
>> Exception in thread "main" scala.MatchError: CharType(1) (of class org.apache.spark.sql.types.CharType)
>> 	at org.apache.spark.sql.catalyst.encoders.RowEncoder$.org$apache$spark$sql$catalyst$encoders$RowEncoder$$serializerFor(RowEncoder.scala:73)
>> 	at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$2.apply(RowEncoder.scala:158)
>> 	at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$2.apply(RowEncoder.scala:157)
>> 
>> Why? Is this a bug?
>> 
>> 	But I found spark will translate char type to string when using create table command:
>> 
>>      			 create table test(flag char(1));
>>       			desc test:            flag string;
>> 
>>     
>> 
>> 
>> Regards
>> Wendy He
> 
> 
> 
> -- 
> Herman van Hövell
> Software Engineer
> Databricks Inc.
> hvanhovell@databricks.com
> +31 6 420 590 27
> databricks.com
> 
> 
> 
> 

Re: SparkSQL not support CharType

Posted by Herman van Hövell tot Westerflier <hv...@databricks.com>.
You need to use a StringType. The CharType and VarCharType are there to
ensure compatibility with Hive and ORC; they should not be used anywhere
else.

On Thu, Nov 23, 2017 at 4:09 AM, 163 <he...@163.com> wrote:

> Hi,
>      when I use Dataframe with table schema, It goes wrong:
>
> val test_schema = StructType(Array(
>
>   StructField("id", IntegerType, false),
>   StructField("flag", CharType(1), false),
>   StructField("time", DateType, false)));
>
> val df = spark.read.format("com.databricks.spark.csv")
>   .schema(test_schema)
>   .option("header", "false")
>   .option("inferSchema", "false")
>   .option("delimiter", ",")
>   .load("file:///Users/name/b")
>
>
> The log is below:
> Exception in thread "main" scala.MatchError: CharType(1) (of class
> org.apache.spark.sql.types.CharType)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$.org$
> apache$spark$sql$catalyst$encoders$RowEncoder$$serializerFor(RowEncoder.
> scala:73)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$
> 2.apply(RowEncoder.scala:158)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$
> 2.apply(RowEncoder.scala:157)
>
> Why? Is this a bug?
>
> But I found spark will translate char type to string when using create
> table command:
>
>       create table test(flag char(1));
>       desc test:            flag string;
>
>
>
>
> Regards
> Wendy He
>



-- 

Herman van Hövell

Software Engineer

Databricks Inc.

hvanhovell@databricks.com

+31 6 420 590 27

databricks.com

[image: http://databricks.com] <http://databricks.com/>


<https://databricks.com/product/unified-analytics-platform>

Re: SparkSQL not support CharType

Posted by Herman van Hövell tot Westerflier <hv...@databricks.com>.
You need to use a StringType. The CharType and VarCharType are there to
ensure compatibility with Hive and ORC; they should not be used anywhere
else.

On Thu, Nov 23, 2017 at 4:09 AM, 163 <he...@163.com> wrote:

> Hi,
>      when I use Dataframe with table schema, It goes wrong:
>
> val test_schema = StructType(Array(
>
>   StructField("id", IntegerType, false),
>   StructField("flag", CharType(1), false),
>   StructField("time", DateType, false)));
>
> val df = spark.read.format("com.databricks.spark.csv")
>   .schema(test_schema)
>   .option("header", "false")
>   .option("inferSchema", "false")
>   .option("delimiter", ",")
>   .load("file:///Users/name/b")
>
>
> The log is below:
> Exception in thread "main" scala.MatchError: CharType(1) (of class
> org.apache.spark.sql.types.CharType)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$.org$
> apache$spark$sql$catalyst$encoders$RowEncoder$$serializerFor(RowEncoder.
> scala:73)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$
> 2.apply(RowEncoder.scala:158)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$
> 2.apply(RowEncoder.scala:157)
>
> Why? Is this a bug?
>
> But I found spark will translate char type to string when using create
> table command:
>
>       create table test(flag char(1));
>       desc test:            flag string;
>
>
>
>
> Regards
> Wendy He
>



-- 

Herman van Hövell

Software Engineer

Databricks Inc.

hvanhovell@databricks.com

+31 6 420 590 27

databricks.com

[image: http://databricks.com] <http://databricks.com/>


<https://databricks.com/product/unified-analytics-platform>