How to find location of a .page without the RequestCycle

["Waluk, Michael" <Mi...@workscape.com>]

In my ServiceEncoder I'd like to assign a servletPath that mimics the actual page location under WEB-INF.  For example, a link to the page located in 
    /WEB-INF/comp/Home.page 
would get the servletPath
    /comp/Home.page (or whatever extension is assigned).

Since the RequestCycle is not available (can't currently be injected) to the ServiceEncoders, I don't see how in Tapestry 4 (beta-8) I can determine the page location.  If I could somehow get the IPage instance it would be easy with 
    page.getLocation().getResource().getPath();
but I don't see how I can get the IPage or location without a RequestCycle.

The goal is to organize our site into applications and have the friendly URLs reflect this structure.  We're going to use this URL path in Filters for various permission-setting.  Tapestry 4 allows us to store the page and html in organized folders but we need a ServiceEncoder based upon the PageServiceEncoder(I think) to get the URLs to mimic this.

Any ideas?

Thanks,
Michael

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Re: How to find location of a .page without the RequestCycle

[Kent Tong <ke...@cpttm.org.mo>]

Waluk, Michael <Michael.Waluk <at> workscape.com> writes:

> In my ServiceEncoder I'd like to assign a servletPath that mimics the actual 
> page location under WEB-INF. 
> For example, a link to the page located in 
>     /WEB-INF/comp/Home.page 
> would get the servletPath
>     /comp/Home.page (or whatever extension is assigned).

I may not be understanding your question. The full page path is availabe
in the "page" parameter:

  http://localhost/myapp/app?service=page&page=comp/Home

So, your service encoder can easily convert it to:

  http://localhost/myapp/comp/Home.page

However, this is already provided by the page-service-encoder coming
with Tapestry. So you probably don't need to write your own.

--
Author of a book for learning Tapestry (http://www.agileskills2.org/EWDT)


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