Re: WebClient request to HTTPS URL

[Sergey Beryozkin <sb...@gmail.com>]

On 27/06/12 18:50, Ganesan, Chandru wrote:
> Hi
>
> I could successfully use WebClient to make plain HTTP requests to the server. Now I'd like to change the request URL to HTTPS. Is there any special handling needed for this in the client code.
>
> I'm getting following error when accessing an HTTPS URL:
>
> [No Trust Decider for Conduit '{https://<suppressing the url in email>:443} WebClient.http-conduit'. An afirmative Trust Decision is assumed.]
> [Interceptor for {https:// ://<suppressing the url in email>:443}WebClient has thrown exception, unwinding now]
> org.apache.cxf.interceptor.Fault: Could not send Message.
>                  at org.apache.cxf.interceptor.MessageSenderInterceptor$MessageSenderEndingInterceptor.handleMessage(MessageSenderInterceptor.java:64)
>                  at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:243)
>                  at org.apache.cxf.jaxrs.client.WebClient.doChainedInvocation(WebClient.java:595)
>                  at org.apache.cxf.jaxrs.client.WebClient.doInvoke(WebClient.java:576)
>                  at org.apache.cxf.jaxrs.client.WebClient.invoke(WebClient.java:323)
>                  at org.apache.cxf.jaxrs.client.WebClient.get(WebClient.java:390)
>
> Appreciate the help

Please see
http://cxf.apache.org/docs/secure-jax-rs-services.html#SecureJAX-RSServices-Configuringclients
http://cxf.apache.org/docs/jax-rs-client-api.html#JAX-RSClientAPI-ConfiguringanHTTPConduitfromSpring

You can also experiment with setting the conduit from the code, example,
HTTPConduit conduit = WebClient.getConfig(client).getHTTPConduit();
// set TLS properties

This blog from Arul shows the example:
http://aruld.info/programming-ssl-for-jetty-based-cxf-services/

Sergey

>
> Thanks
> Chandru
>


-- 
Sergey Beryozkin

Talend Community Coders
http://coders.talend.com/

Blog: http://sberyozkin.blogspot.com