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Posted to issues@spark.apache.org by "Apache Spark (JIRA)" <ji...@apache.org> on 2017/11/14 17:06:00 UTC
[jira] [Assigned] (SPARK-22431) Creating Permanent view with
illegal type
[ https://issues.apache.org/jira/browse/SPARK-22431?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Apache Spark reassigned SPARK-22431:
------------------------------------
Assignee: (was: Apache Spark)
> Creating Permanent view with illegal type
> -----------------------------------------
>
> Key: SPARK-22431
> URL: https://issues.apache.org/jira/browse/SPARK-22431
> Project: Spark
> Issue Type: Bug
> Components: SQL
> Affects Versions: 2.2.0
> Reporter: Herman van Hovell
>
> It is possible in Spark SQL to create a permanent view that uses an nested field with an illegal name.
> For example if we create the following view:
> {noformat}
> create view x as select struct('a' as `$q`, 1 as b) q
> {noformat}
> A simple select fails with the following exception:
> {noformat}
> select * from x;
> org.apache.spark.SparkException: Cannot recognize hive type string: struct<$q:string,b:int>
> at org.apache.spark.sql.hive.client.HiveClientImpl$.fromHiveColumn(HiveClientImpl.scala:812)
> at org.apache.spark.sql.hive.client.HiveClientImpl$$anonfun$getTableOption$1$$anonfun$apply$11$$anonfun$7.apply(HiveClientImpl.scala:378)
> at org.apache.spark.sql.hive.client.HiveClientImpl$$anonfun$getTableOption$1$$anonfun$apply$11$$anonfun$7.apply(HiveClientImpl.scala:378)
> ...
> {noformat}
> Dropping the view isn't possible either:
> {noformat}
> drop view x;
> org.apache.spark.SparkException: Cannot recognize hive type string: struct<$q:string,b:int>
> at org.apache.spark.sql.hive.client.HiveClientImpl$.fromHiveColumn(HiveClientImpl.scala:812)
> at org.apache.spark.sql.hive.client.HiveClientImpl$$anonfun$getTableOption$1$$anonfun$apply$11$$anonfun$7.apply(HiveClientImpl.scala:378)
> at org.apache.spark.sql.hive.client.HiveClientImpl$$anonfun$getTableOption$1$$anonfun$apply$11$$anonfun$7.apply(HiveClientImpl.scala:378)
> ...
> {noformat}
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