You are viewing a plain text version of this content. The canonical link for it is here.

Posted to dev@xalan.apache.org by "Kumar, Ritesh (GEP, Contractor)" <Ri...@gepex.ge.com> on 2000/08/30 17:45:48 UTC

Not able to provide link...

Hi 
     I tried to provide a link to yahoo website from a point in my xml
page.Following are my xml and xsl files, but I donot know why it is not
working.

Please help...

XML File

<?xml version="1.0"?>

<page>
    <pagename>Introduction</pagename>
    
    <title>
        <title_name   xmlns:xlink="http://www.w3.org/1999/xlink" 
		 xlink:type="simple" xlink:href="http://www.yahoo.com">
            Engineered Blow Molding Part Design
        </title_name>
    </title>        
</page>
        

XSL File

<?xml version="1.0"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
  <xsl:output method="html" indent="yes"/>
  
    <xsl:template match="/">
        <xsl:apply-templates select="page"/>
    </xsl:template>
    
    <xsl:template match="page">
        <html>
        <head>
            <title> <xsl:value-of select="pagename"/>
            </title>
        </head>
        <body topmargin="0" vlink="#34699E" alink="#34699E" link="#34699E">


            <table border="0" cellpadding="0" cellspacing="0" width="716">
                <tr>
                    <td height="20" valign="top"
align="left"><xsl:apply-templates select="title"/>
                    </td>
                </tr>                
            </table>                                        
        </body>
        </html>
    </xsl:template>

	<xsl:template match="title" >
        <xsl:value-of select="title_name"/>
        <xsl:value-of select="title_decoration"/>
    </xsl:template>
 
</xsl:stylesheet>

Regards,
Ritesh kumar