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Posted to user@struts.apache.org by otsuka <t-...@ijk.com> on 2003/05/09 10:11:01 UTC
How to get the file path of uploaded temporary file
Hi,
In order to check the width and height of an image,
I need to get a File object of uploaded image file.
But org.apache.struts.upload.FormFile interface
does not provide any method that tells me the
temporary file's path on a server.
How can I get to know the file path of an uploaded file?
DiskFile class has a method "getFilePath()".
Therefore, if DiskFile class is always used as an
implementing class of FormFile interface, I will
use the class instead of FormFile interface. But
I don't know whether is used as the implementing
class, DiskFile or CommonsMultipartRequestHandler.CommonsFormFile.
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Re: How to get the file path of uploaded temporary file
Posted by Martin Cooper <ma...@apache.org>.
"otsuka" <t-...@ijk.com> wrote in message
news:007b01c31602$8f9fdc30$0600a8c0@yoda...
> Hi,
>
> In order to check the width and height of an image,
> I need to get a File object of uploaded image file.
> But org.apache.struts.upload.FormFile interface
> does not provide any method that tells me the
> temporary file's path on a server.
You are assuming that there *is* a file on the server. Whether that is true
or not depends on the underlying multipart handler implementation. In Struts
1.1, the default implementation is based on Commons FileUpload, which
retains smaller files in memory, and writes larger ones to disk. That being
the case, the only reliable way of accessing the data is to use code similar
to that suggested by Harm de Laat in a previous reply.
--
Martin Cooper
>
> How can I get to know the file path of an uploaded file?
>
> DiskFile class has a method "getFilePath()".
> Therefore, if DiskFile class is always used as an
> implementing class of FormFile interface, I will
> use the class instead of FormFile interface. But
> I don't know whether is used as the implementing
> class, DiskFile or CommonsMultipartRequestHandler.CommonsFormFile.
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Re: How to get the file path of uploaded temporary file
Posted by ha...@informatiefabriek.nl.
Hi,
I use something like this:
if (form instanceof UploadForm) {
UploadForm theForm = (UploadForm) form;
//retrieve the file representation
FormFile file = theForm.getFile();
//retrieve the file name
String fileName= file.getFileName();
//retrieve the content type
String contentType = file.getContentType();
//retrieve the file size
String size = ("" + file.getFileSize());
try {
//retrieve the file data
ByteArrayOutputStream baos = new ByteArrayOutputStream();
InputStream stream = file.getInputStream();
//write the file to the file specified
OutputStream bos = new FileOutputStream("/tmp/" +
fileName);
int bytesRead = 0;
byte[] buffer = new byte[8192];
while ((bytesRead = stream.read(buffer, 0, 8192)) != -1) {
bos.write(buffer, 0, bytesRead);
}
bos.close();
// data = "The file has been written to \"" +
theForm.getFilePath() + "\"";
//close the stream
stream.close();
}
catch (FileNotFoundException fnfe) {
return null;
}
catch (IOException ioe) {
return null;
}
}
This may help you.
Cheers,
Harm de Laat
Informatiefabriek
The Netherlands
"otsuka" <t-...@ijk.com>
05/09/2003 10:11 AM
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How to get the file path of uploaded temporary file
Hi,
In order to check the width and height of an image,
I need to get a File object of uploaded image file.
But org.apache.struts.upload.FormFile interface
does not provide any method that tells me the
temporary file's path on a server.
How can I get to know the file path of an uploaded file?
DiskFile class has a method "getFilePath()".
Therefore, if DiskFile class is always used as an
implementing class of FormFile interface, I will
use the class instead of FormFile interface. But
I don't know whether is used as the implementing
class, DiskFile or CommonsMultipartRequestHandler.CommonsFormFile.
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