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Posted to users@tomcat.apache.org by "Henrique, Manuel" <Ma...@logicacmg.com> on 2005/04/21 15:52:45 UTC
digester understanding again...
Hello all,
Here I come again with my digester :))
So, I have my xml file, I have created my digester and all the needed
classes for my xml tags, and do a digester.parse(). Still here all is ok.
I start Tomcat 5.0 and look to the log file. All seems ok, my xml file is
consumed, all the classes are instancied etc...etc...
My question:
If I have an xml file like this
<computer>
<brand name="compcool">
<model>faster_than_all</model>
<serialnumber>1248965<serialnumber>
</brand>
<brand name="pcassociated">
<model>very_expensive</model>
<serialnumber>34564<serialnumber>
</brand>
<brand name="pcassociated">
<model>expensive_too</model>
<serialnumber>9999999999<serialnumber>
</brand>
</computer>
how can I get after in my Java code the serial number of the model "expen
sive_too" for example??? How can I be sure to get the good data as I have
two identical brand names?
Thank you for your help.
Regards,
Manuel
ps: I know that for someones the question seems to be very basic but
remember when you were beginner and be kind to me
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Re: digester understanding again...
Posted by Rahul Akolkar <ra...@gmail.com>.
Depends how you designed your classes that the XML is digested into ;-)
If you're looking for specific kinds of queries, then the class(es)
should be geared to supporting those [aggregation, composition and
keying constructs associated with the semantics of the data need to be
reflected in the digested output].
If you don't do that, you might as well use a DOMParser and XPath / XQuery.
-Rahul
On 4/21/05, Henrique, Manuel <Ma...@logicacmg.com> wrote:
> Hello all,
>
> Here I come again with my digester :))
>
> So, I have my xml file, I have created my digester and all the needed
> classes for my xml tags, and do a digester.parse(). Still here all is ok.
>
> I start Tomcat 5.0 and look to the log file. All seems ok, my xml file is
> consumed, all the classes are instancied etc...etc...
>
> My question:
>
> If I have an xml file like this
>
> <computer>
> <brand name="compcool">
> <model>faster_than_all</model>
> <serialnumber>1248965<serialnumber>
> </brand>
> <brand name="pcassociated">
> <model>very_expensive</model>
> <serialnumber>34564<serialnumber>
> </brand>
> <brand name="pcassociated">
> <model>expensive_too</model>
> <serialnumber>9999999999<serialnumber>
> </brand>
> </computer>
>
> how can I get after in my Java code the serial number of the model "expen
> sive_too" for example??? How can I be sure to get the good data as I have
> two identical brand names?
>
> Thank you for your help.
>
> Regards,
>
> Manuel
>
> ps: I know that for someones the question seems to be very basic but
> remember when you were beginner and be kind to me
>
> This e-mail and any attachment is for authorised use by the intended recipient(s) only. It may contain proprietary material, confidential information and/or be subject to legal privilege. It should not be copied, disclosed to, retained or used by, any other party. If you are not an intended recipient then please promptly delete this e-mail and any attachment and all copies and inform the sender. Thank you.
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: tomcat-user-unsubscribe@jakarta.apache.org
> For additional commands, e-mail: tomcat-user-help@jakarta.apache.org
>
>
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