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Posted to modperl@perl.apache.org by Henrik S <he...@tomatoservers.com> on 2022/04/21 03:21:48 UTC
path recognition question
given the sample url:
/api/user/id
the part of "/api/user" is fixed. and there is a handler setup for this
path.
how to get the id part in mod_perl?
in other framework I could get it with the similar format:
/api/user/:id
puts "hallo #{id}"
Thank you.
Re: path recognition question
Posted by Mithun Bhattacharya <mi...@gmail.com>.
You still have $r->path just pull the id from it ?
On Thu, May 5, 2022, 4:20 PM Michael A. Capone <mc...@cablewholesale.com>
wrote:
> (Sorry for the late reply, been out of town)
>
> Recognizing that I've never gone as indepth with mod_perl as other users,
> but it seems to me that accessing "id" here would just be a matter of
> grabbing the PATH_INFO environment variable, wouldn't it?
>
> if the url is www.example.com/app/user/12345, then the program is
> /app/user, and $ENV{'PATH_INFO'} would contain /12345. Chop off the
> leading forward slash and you've got your ID.
>
> Note that you'd have to have PerlSetupEnv on (the default, although I
> think many may turn it off).
>
> Or am I completely missing something?
>
> Michael
>
> On 4/21/22 6:40 AM, John Dunlap wrote:
>
> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S <he...@tomatoservers.com>
> wrote:
>
>> given the sample url:
>>
>> /api/user/id
>>
>> the part of "/api/user" is fixed. and there is a handler setup for this
>> path.
>>
>> how to get the id part in mod_perl?
>>
>> in other framework I could get it with the similar format:
>>
>> /api/user/:id
>>
>> puts "hallo #{id}"
>>
>>
>> Thank you.
>>
>
>
> --
> John Dunlap
> *CTO | Lariat *
>
> *Direct:*
> *john@lariat.co <jo...@lariat.co>*
>
> * Customer Service:*
> 877.268.6667
> support@lariat.co
>
>
>
Re: path recognition question
Posted by "Michael A. Capone" <mc...@cablewholesale.com>.
(Sorry for the late reply, been out of town)
Recognizing that I've never gone as indepth with mod_perl as other
users, but it seems to me that accessing "id" here would just be a
matter of grabbing the PATH_INFO environment variable, wouldn't it?
if the url is www.example.com/app/user/12345, then the program is
/app/user, and $ENV{'PATH_INFO'} would contain /12345. Chop off the
leading forward slash and you've got your ID.
Note that you'd have to have PerlSetupEnv on (the default, although I
think many may turn it off).
Or am I completely missing something?
Michael
On 4/21/22 6:40 AM, John Dunlap wrote:
> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S <henrik@tomatoservers.com
> <ma...@tomatoservers.com>> wrote:
>
> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed. and there is a handler setup
> for this
> path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.
>
>
>
> --
> John Dunlap
> /CTO | Lariat/
> /
> /
> /*Direct:*/
> /john@lariat.co <ma...@lariat.co>/
> /
> *Customer Service:*/
> 877.268.6667
> support@lariat.co <ma...@lariat.co>
Re: path recognition question
Posted by Jacques Deguest <ja...@deguest.jp>.
If you are looking to build a REST api with Apache mod_perl, you might
be interested in Net::API::REST (https://metacpan.org/pod/Net::API::REST)
Jacques
On 2022/04/21 23:27, John Dunlap wrote:
> I sent this 8 years ago but, at the time, no one was interested.
> image.png
>
>
> On Thu, Apr 21, 2022 at 9:40 AM John Dunlap <Jo...@lariat.co> wrote:
>
> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S
> <he...@tomatoservers.com> wrote:
>
> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed. and there is a handler
> setup for this
> path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.
>
>
>
> --
> John Dunlap
> /CTO | Lariat/
> /
> /
> /*Direct:*/
> /john@lariat.co/
> /
> *Customer Service:*/
> 877.268.6667
> support@lariat.co
>
>
>
> --
> John Dunlap
> /CTO | Lariat/
> /
> /
> /*Direct:*/
> /john@lariat.co/
> /
> *Customer Service:*/
> 877.268.6667
> support@lariat.co
Re: path recognition question
Posted by John Dunlap <Jo...@lariat.co>.
I sent this 8 years ago but, at the time, no one was interested.
[image: image.png]
On Thu, Apr 21, 2022 at 9:40 AM John Dunlap <Jo...@lariat.co> wrote:
> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S <he...@tomatoservers.com>
> wrote:
>
>> given the sample url:
>>
>> /api/user/id
>>
>> the part of "/api/user" is fixed. and there is a handler setup for this
>> path.
>>
>> how to get the id part in mod_perl?
>>
>> in other framework I could get it with the similar format:
>>
>> /api/user/:id
>>
>> puts "hallo #{id}"
>>
>>
>> Thank you.
>>
>
>
> --
> John Dunlap
> *CTO | Lariat *
>
> *Direct:*
> *john@lariat.co <jo...@lariat.co>*
>
> *Customer Service:*
> 877.268.6667
> support@lariat.co
>
--
John Dunlap
*CTO | Lariat *
*Direct:*
*john@lariat.co <jo...@lariat.co>*
*Customer Service:*
877.268.6667
support@lariat.co
Re: path recognition question
Posted by John Dunlap <Jo...@lariat.co>.
I ended up writing something custom to do that.
On Wed, Apr 20, 2022 at 11:22 PM Henrik S <he...@tomatoservers.com> wrote:
> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed. and there is a handler setup for this
> path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.
>
--
John Dunlap
*CTO | Lariat *
*Direct:*
*john@lariat.co <jo...@lariat.co>*
*Customer Service:*
877.268.6667
support@lariat.co
Re: path recognition question
Posted by Jacques Deguest <ja...@deguest.jp>.
I would use path_info.
See Apache2::RequestRec manual page.
Regards,
Jacques
On 2022/04/21 12:21, Henrik S wrote:
> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed. and there is a handler setup for
> this path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.