pulling .jars from a path?

[tek1 <te...@pobox.com>]

hello.

is it possible to pull all the .jars listed in a path as a fileset (for 
inclusion in the "lib" nested element of the "war" task)?

the reason why is because i'm using a build.properties to make references 
to .jars on the filesystem as follows:


build.properties
------------
velocity.lib=${velocity.home}/velocity-dep-1.3.1-rc2.jar
commons-lang.lib=${commons-lang.home}/commons-lang-1.0.1.jar

build.classpath=${velocity.lib}:${commons-lang.lib}



the .jars listed above (in ${build.classpath}) are needed in the /lib 
directory of the webapp, so looking for a way to reference the .jars as a 
fileset, instead of listing each xxx.lib entry as a "lib" nested element in 
the war task.

thank you. 


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Re: pulling .jars from a path?

[tek1 <te...@pobox.com>]

hi stefan.

i will give your suggestion a try.  thanks.



At 09:42 03/01/15 +0100, you wrote:
>On Tue, 14 Jan 2003, <te...@pobox.com> wrote:
>
> > is it possible to pull all the .jars listed in a path as a fileset
> > (for inclusion in the "lib" nested element of the "war" task)?
>
><fileset>s in Ant (currently) have to be rooted in a common base
>directory.  This is generally not true for an arbitrary collection of
>files, at least on OSes with multiple file system roots (read
>drives).
>
>If you are on a system with a single file system root - assuming "/"
>for the rest here - you could (1) <pathconvert> your path to a comma
>separated list and (2) use that as the includes attribute in a
><fileset> with dir="/".
>
>Stefan
>
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>To unsubscribe, e-mail:   <ma...@jakarta.apache.org>
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Re: pulling .jars from a path?

[Stefan Bodewig <bo...@apache.org>]

On Tue, 14 Jan 2003, <te...@pobox.com> wrote:

> is it possible to pull all the .jars listed in a path as a fileset
> (for inclusion in the "lib" nested element of the "war" task)?

<fileset>s in Ant (currently) have to be rooted in a common base
directory.  This is generally not true for an arbitrary collection of
files, at least on OSes with multiple file system roots (read
drives).

If you are on a system with a single file system root - assuming "/"
for the rest here - you could (1) <pathconvert> your path to a comma
separated list and (2) use that as the includes attribute in a
<fileset> with dir="/".

Stefan

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