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Posted to users@jackrabbit.apache.org by Saminda Wijeratne <sa...@gmail.com> on 2011/09/25 00:48:00 UTC
Creating user manager instance in order to create users
Hi,
I'm new to using JackRabbit repository. I couldn't find a similar question
on the archives. I just want to programatically create a user for JackRabbit
registry.
I was attempting to use the JackRabbit API.
HashMap<String, String> map = new HashMap<String, String>();
map.put("org.apache.jackrabbit.repository.uri", "
http://localhost:8080/rmi");
Repository repository = new
RmiRepositoryFactory().getRepository(map);
Credentials credentials=new SimpleCredentials("admin", new
String("admin").toCharArray());
Session session = repository.login(credentials);
Tried to initialize the SimpleSecurityManager to get the UserManager object.
SimpleSecurityManager simpleSecurityManager = new
SimpleSecurityManager();
simpleSecurityManager.init(repository, session);
But calling init method throws the following,
javax.jcr.RepositoryException: RepositoryImpl expected
at
org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.init(SimpleSecurityManager.java:127)
at FirstHop.main(FirstHop.java:38)
Looking at the impl of the init method showed that the repository parameter
expected in the init method looks for a specific implementation of
RepositoryImpl class. From where can this object be derived from the
existing repository object? Or is the way I'm doing this is all wrong?
Thanks in advance,
Saminda
Re: Creating user manager instance in order to create users
Posted by Saminda Wijeratne <sa...@gmail.com>.
Hi Francisco,
I got the error mentioned at [1]. I'm going to build the trunk & try the
SNAPSHOT. Will keep the thread updated.
1. https://issues.apache.org/jira/browse/JCR-3076
On Sun, Sep 25, 2011 at 5:56 PM, Francisco Carriedo Scher <
fcarriedos@gmail.com> wrote:
> User management is currently not supported when you get the repository
> object through RMI. Try the same code getting the repository through Webdav:
>
> Repository repository =
> JcrUtils.getRepository("http://localhost:8080/server<http://localhost/jackrabbit/server>
> ");
>
> (check the parameter "http..." in Jackrabbit's documentation since did not
> check it, but it should work like that).
>
> Greetings!
>
>
>
>
> 2011/9/25 Saminda Wijeratne <sa...@gmail.com>
>
>> Hi,
>>
>> Thanks for the insight. I've updated the repository.xml as mentioned &
>> executed the code. When getUserManager() is called an exception was
>> thrown,
>> Exception in thread "main"
>> javax.jcr.UnsupportedRepositoryOperationException: UserManager not
>> supported.
>> at
>> org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.getUserManager(SimpleSecurityManager.java:254)
>> at
>> org.apache.jackrabbit.core.SessionImpl.getUserManager(SessionImpl.java:652)
>> at FirstHop.main(FirstHop.java:32)
>>
>> When I debugged the session object it had a null for the userManager
>> variable. Do I need to change anything else in the repository.xml
>>
>> Thanks,
>> Saminda
>>
>>
>> On Sun, Sep 25, 2011 at 7:18 AM, Francisco Carriedo Scher <
>> fcarriedos@gmail.com> wrote:
>>
>>> Hi there,
>>>
>>> you were on the right path, anyway i paste here a code snipet to
>>> correctly create users. Since you mentioned the simple security manager i
>>> will specify a little bit more what "correct" means: users who later will be
>>> managed for access control by Jackrabbit.
>>>
>>>
>>> The code for creating users:
>>>
>>> Repository repository = new TransientRepository();
>>> BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
>>> Session session = repository.login(new SimpleCredentials("admin",
>>> "admin".toCharArray()));
>>>
>>> if (session instanceof JackrabbitSession) {
>>> umgr = ((JackrabbitSession) session).getUserManager();
>>> }
>>>
>>> System.out.println("Input username and password: ");
>>> umgr.createUser(br.readLine(), br.readLine());
>>> // Reaching this point with no exception means that the user was
>>> successfully created
>>>
>>>
>>> Prior to run the code above, the configuration for access management in
>>> repository.xml file must be completed. You need to specify the following
>>> classes (but no need to instantiate them in your code, it is used internally
>>> by Jackrabbit through JAAS (have a look
>>> http://download.oracle.com/javase/6/docs/technotes/guides/security/jaas/JAASRefGuide.html).
>>> Basically Jackrabbit uses JAAS for authentication (know if you are who you
>>> claim to be through username and password) and it's own ACLs for
>>> authentication (know if you are allowed to perform an action) :
>>>
>>> <SecurityManager
>>> class="org.apache.jackrabbit.core.DefaultSecurityManager"
>>> workspaceName="security">
>>> ...
>>> <AccessManager
>>> class="org.apache.jackrabbit.core.security.DefaultAccessManager">
>>> ...
>>> <LoginModule
>>> class="org.apache.jackrabbit.core.security.authentication.DefaultLoginModule">
>>>
>>>
>>>
>>> For setting ACLs details check
>>> http://wiki.apache.org/jackrabbit/AccessControl
>>>
>>> Hope that helps!
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>> 2011/9/25 Saminda Wijeratne <sa...@gmail.com>
>>>
>>>> Hi,
>>>>
>>>> I'm new to using JackRabbit repository. I couldn't find a similar
>>>> question
>>>> on the archives. I just want to programatically create a user for
>>>> JackRabbit
>>>> registry.
>>>>
>>>> I was attempting to use the JackRabbit API.
>>>>
>>>> HashMap<String, String> map = new HashMap<String, String>();
>>>> map.put("org.apache.jackrabbit.repository.uri", "
>>>> http://localhost:8080/rmi");
>>>> Repository repository = new
>>>> RmiRepositoryFactory().getRepository(map);
>>>> Credentials credentials=new SimpleCredentials("admin", new
>>>> String("admin").toCharArray());
>>>> Session session = repository.login(credentials);
>>>>
>>>>
>>>> Tried to initialize the SimpleSecurityManager to get the UserManager
>>>> object.
>>>>
>>>> SimpleSecurityManager simpleSecurityManager = new
>>>> SimpleSecurityManager();
>>>> simpleSecurityManager.init(repository, session);
>>>>
>>>> But calling init method throws the following,
>>>> javax.jcr.RepositoryException: RepositoryImpl expected
>>>> at
>>>>
>>>> org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.init(SimpleSecurityManager.java:127)
>>>> at FirstHop.main(FirstHop.java:38)
>>>>
>>>> Looking at the impl of the init method showed that the repository
>>>> parameter
>>>> expected in the init method looks for a specific implementation of
>>>> RepositoryImpl class. From where can this object be derived from the
>>>> existing repository object? Or is the way I'm doing this is all wrong?
>>>>
>>>> Thanks in advance,
>>>> Saminda
>>>>
>>>
>>>
>>
>
Re: Creating user manager instance in order to create users
Posted by Francisco Carriedo Scher <fc...@gmail.com>.
User management is currently not supported when you get the repository
object through RMI. Try the same code getting the repository through Webdav:
Repository repository =
JcrUtils.getRepository("http://localhost:8080/server<http://localhost/jackrabbit/server>
");
(check the parameter "http..." in Jackrabbit's documentation since did not
check it, but it should work like that).
Greetings!
2011/9/25 Saminda Wijeratne <sa...@gmail.com>
> Hi,
>
> Thanks for the insight. I've updated the repository.xml as mentioned &
> executed the code. When getUserManager() is called an exception was
> thrown,
> Exception in thread "main"
> javax.jcr.UnsupportedRepositoryOperationException: UserManager not
> supported.
> at
> org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.getUserManager(SimpleSecurityManager.java:254)
> at
> org.apache.jackrabbit.core.SessionImpl.getUserManager(SessionImpl.java:652)
> at FirstHop.main(FirstHop.java:32)
>
> When I debugged the session object it had a null for the userManager
> variable. Do I need to change anything else in the repository.xml
>
> Thanks,
> Saminda
>
>
> On Sun, Sep 25, 2011 at 7:18 AM, Francisco Carriedo Scher <
> fcarriedos@gmail.com> wrote:
>
>> Hi there,
>>
>> you were on the right path, anyway i paste here a code snipet to correctly
>> create users. Since you mentioned the simple security manager i will specify
>> a little bit more what "correct" means: users who later will be managed for
>> access control by Jackrabbit.
>>
>>
>> The code for creating users:
>>
>> Repository repository = new TransientRepository();
>> BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
>> Session session = repository.login(new SimpleCredentials("admin",
>> "admin".toCharArray()));
>>
>> if (session instanceof JackrabbitSession) {
>> umgr = ((JackrabbitSession) session).getUserManager();
>> }
>>
>> System.out.println("Input username and password: ");
>> umgr.createUser(br.readLine(), br.readLine());
>> // Reaching this point with no exception means that the user was
>> successfully created
>>
>>
>> Prior to run the code above, the configuration for access management in
>> repository.xml file must be completed. You need to specify the following
>> classes (but no need to instantiate them in your code, it is used internally
>> by Jackrabbit through JAAS (have a look
>> http://download.oracle.com/javase/6/docs/technotes/guides/security/jaas/JAASRefGuide.html).
>> Basically Jackrabbit uses JAAS for authentication (know if you are who you
>> claim to be through username and password) and it's own ACLs for
>> authentication (know if you are allowed to perform an action) :
>>
>> <SecurityManager class="org.apache.jackrabbit.core.DefaultSecurityManager"
>> workspaceName="security">
>> ...
>> <AccessManager
>> class="org.apache.jackrabbit.core.security.DefaultAccessManager">
>> ...
>> <LoginModule
>> class="org.apache.jackrabbit.core.security.authentication.DefaultLoginModule">
>>
>>
>>
>> For setting ACLs details check
>> http://wiki.apache.org/jackrabbit/AccessControl
>>
>> Hope that helps!
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> 2011/9/25 Saminda Wijeratne <sa...@gmail.com>
>>
>>> Hi,
>>>
>>> I'm new to using JackRabbit repository. I couldn't find a similar
>>> question
>>> on the archives. I just want to programatically create a user for
>>> JackRabbit
>>> registry.
>>>
>>> I was attempting to use the JackRabbit API.
>>>
>>> HashMap<String, String> map = new HashMap<String, String>();
>>> map.put("org.apache.jackrabbit.repository.uri", "
>>> http://localhost:8080/rmi");
>>> Repository repository = new
>>> RmiRepositoryFactory().getRepository(map);
>>> Credentials credentials=new SimpleCredentials("admin", new
>>> String("admin").toCharArray());
>>> Session session = repository.login(credentials);
>>>
>>>
>>> Tried to initialize the SimpleSecurityManager to get the UserManager
>>> object.
>>>
>>> SimpleSecurityManager simpleSecurityManager = new
>>> SimpleSecurityManager();
>>> simpleSecurityManager.init(repository, session);
>>>
>>> But calling init method throws the following,
>>> javax.jcr.RepositoryException: RepositoryImpl expected
>>> at
>>>
>>> org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.init(SimpleSecurityManager.java:127)
>>> at FirstHop.main(FirstHop.java:38)
>>>
>>> Looking at the impl of the init method showed that the repository
>>> parameter
>>> expected in the init method looks for a specific implementation of
>>> RepositoryImpl class. From where can this object be derived from the
>>> existing repository object? Or is the way I'm doing this is all wrong?
>>>
>>> Thanks in advance,
>>> Saminda
>>>
>>
>>
>
Re: Creating user manager instance in order to create users
Posted by Saminda Wijeratne <sa...@gmail.com>.
Hi,
Thanks for the insight. I've updated the repository.xml as mentioned &
executed the code. When getUserManager() is called an exception was thrown,
Exception in thread "main"
javax.jcr.UnsupportedRepositoryOperationException: UserManager not
supported.
at
org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.getUserManager(SimpleSecurityManager.java:254)
at
org.apache.jackrabbit.core.SessionImpl.getUserManager(SessionImpl.java:652)
at FirstHop.main(FirstHop.java:32)
When I debugged the session object it had a null for the userManager
variable. Do I need to change anything else in the repository.xml
Thanks,
Saminda
On Sun, Sep 25, 2011 at 7:18 AM, Francisco Carriedo Scher <
fcarriedos@gmail.com> wrote:
> Hi there,
>
> you were on the right path, anyway i paste here a code snipet to correctly
> create users. Since you mentioned the simple security manager i will specify
> a little bit more what "correct" means: users who later will be managed for
> access control by Jackrabbit.
>
>
> The code for creating users:
>
> Repository repository = new TransientRepository();
> BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
> Session session = repository.login(new SimpleCredentials("admin",
> "admin".toCharArray()));
>
> if (session instanceof JackrabbitSession) {
> umgr = ((JackrabbitSession) session).getUserManager();
> }
>
> System.out.println("Input username and password: ");
> umgr.createUser(br.readLine(), br.readLine());
> // Reaching this point with no exception means that the user was
> successfully created
>
>
> Prior to run the code above, the configuration for access management in
> repository.xml file must be completed. You need to specify the following
> classes (but no need to instantiate them in your code, it is used internally
> by Jackrabbit through JAAS (have a look
> http://download.oracle.com/javase/6/docs/technotes/guides/security/jaas/JAASRefGuide.html).
> Basically Jackrabbit uses JAAS for authentication (know if you are who you
> claim to be through username and password) and it's own ACLs for
> authentication (know if you are allowed to perform an action) :
>
> <SecurityManager class="org.apache.jackrabbit.core.DefaultSecurityManager"
> workspaceName="security">
> ...
> <AccessManager
> class="org.apache.jackrabbit.core.security.DefaultAccessManager">
> ...
> <LoginModule
> class="org.apache.jackrabbit.core.security.authentication.DefaultLoginModule">
>
>
>
> For setting ACLs details check
> http://wiki.apache.org/jackrabbit/AccessControl
>
> Hope that helps!
>
>
>
>
>
>
>
>
>
>
>
>
>
> 2011/9/25 Saminda Wijeratne <sa...@gmail.com>
>
>> Hi,
>>
>> I'm new to using JackRabbit repository. I couldn't find a similar question
>> on the archives. I just want to programatically create a user for
>> JackRabbit
>> registry.
>>
>> I was attempting to use the JackRabbit API.
>>
>> HashMap<String, String> map = new HashMap<String, String>();
>> map.put("org.apache.jackrabbit.repository.uri", "
>> http://localhost:8080/rmi");
>> Repository repository = new
>> RmiRepositoryFactory().getRepository(map);
>> Credentials credentials=new SimpleCredentials("admin", new
>> String("admin").toCharArray());
>> Session session = repository.login(credentials);
>>
>>
>> Tried to initialize the SimpleSecurityManager to get the UserManager
>> object.
>>
>> SimpleSecurityManager simpleSecurityManager = new
>> SimpleSecurityManager();
>> simpleSecurityManager.init(repository, session);
>>
>> But calling init method throws the following,
>> javax.jcr.RepositoryException: RepositoryImpl expected
>> at
>>
>> org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.init(SimpleSecurityManager.java:127)
>> at FirstHop.main(FirstHop.java:38)
>>
>> Looking at the impl of the init method showed that the repository
>> parameter
>> expected in the init method looks for a specific implementation of
>> RepositoryImpl class. From where can this object be derived from the
>> existing repository object? Or is the way I'm doing this is all wrong?
>>
>> Thanks in advance,
>> Saminda
>>
>
>
Re: Creating user manager instance in order to create users
Posted by Francisco Carriedo Scher <fc...@gmail.com>.
Hi there,
you were on the right path, anyway i paste here a code snipet to correctly
create users. Since you mentioned the simple security manager i will specify
a little bit more what "correct" means: users who later will be managed for
access control by Jackrabbit.
The code for creating users:
Repository repository = new TransientRepository();
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
Session session = repository.login(new SimpleCredentials("admin",
"admin".toCharArray()));
if (session instanceof JackrabbitSession) {
umgr = ((JackrabbitSession) session).getUserManager();
}
System.out.println("Input username and password: ");
umgr.createUser(br.readLine(), br.readLine());
// Reaching this point with no exception means that the user was
successfully created
Prior to run the code above, the configuration for access management in
repository.xml file must be completed. You need to specify the following
classes (but no need to instantiate them in your code, it is used internally
by Jackrabbit through JAAS (have a look
http://download.oracle.com/javase/6/docs/technotes/guides/security/jaas/JAASRefGuide.html).
Basically Jackrabbit uses JAAS for authentication (know if you are who you
claim to be through username and password) and it's own ACLs for
authentication (know if you are allowed to perform an action) :
<SecurityManager class="org.apache.jackrabbit.core.DefaultSecurityManager"
workspaceName="security">
...
<AccessManager
class="org.apache.jackrabbit.core.security.DefaultAccessManager">
...
<LoginModule
class="org.apache.jackrabbit.core.security.authentication.DefaultLoginModule">
For setting ACLs details check
http://wiki.apache.org/jackrabbit/AccessControl
Hope that helps!
2011/9/25 Saminda Wijeratne <sa...@gmail.com>
> Hi,
>
> I'm new to using JackRabbit repository. I couldn't find a similar question
> on the archives. I just want to programatically create a user for
> JackRabbit
> registry.
>
> I was attempting to use the JackRabbit API.
>
> HashMap<String, String> map = new HashMap<String, String>();
> map.put("org.apache.jackrabbit.repository.uri", "
> http://localhost:8080/rmi");
> Repository repository = new
> RmiRepositoryFactory().getRepository(map);
> Credentials credentials=new SimpleCredentials("admin", new
> String("admin").toCharArray());
> Session session = repository.login(credentials);
>
>
> Tried to initialize the SimpleSecurityManager to get the UserManager
> object.
>
> SimpleSecurityManager simpleSecurityManager = new
> SimpleSecurityManager();
> simpleSecurityManager.init(repository, session);
>
> But calling init method throws the following,
> javax.jcr.RepositoryException: RepositoryImpl expected
> at
>
> org.apache.jackrabbit.core.security.simple.SimpleSecurityManager.init(SimpleSecurityManager.java:127)
> at FirstHop.main(FirstHop.java:38)
>
> Looking at the impl of the init method showed that the repository parameter
> expected in the init method looks for a specific implementation of
> RepositoryImpl class. From where can this object be derived from the
> existing repository object? Or is the way I'm doing this is all wrong?
>
> Thanks in advance,
> Saminda
>