You are viewing a plain text version of this content. The canonical link for it is here.
Posted to dev@openjpa.apache.org by "Ravi P Palacherla (JIRA)" <ji...@apache.org> on 2009/12/07 06:12:18 UTC

[jira] Updated: (OPENJPA-681) Subquery generates SQL with syntax error

     [ https://issues.apache.org/jira/browse/OPENJPA-681?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Ravi P Palacherla updated OPENJPA-681:
--------------------------------------

    Attachment: openJPA-681_1.1.x.patch

This patch includes test case changes plus changes attached by Hiroki Tateno.

> Subquery generates SQL with syntax error
> ----------------------------------------
>
>                 Key: OPENJPA-681
>                 URL: https://issues.apache.org/jira/browse/OPENJPA-681
>             Project: OpenJPA
>          Issue Type: Sub-task
>            Reporter: Catalina Wei
>             Fix For: 1.0.4, 1.2.1, 1.3.0
>
>         Attachments: openJPA-681_1.1.x.patch, OPENJPA-681_1_1_x.patch
>
>
> This is another kind of subquery that is not handled correctly in resolving table aliases, the failed JPQL:
>         "select o1.oid, c.name from Order o1, Customer c where o1.amount = " +
>             " any(select o2.amount from in(c.orders) o2)",
> The incorrect SQL contains  t4.name where t4  is not defined in FROM clause:
> SELECT t0.oid, t4.name FROM Order t0 JOIN Customer t1 ON (1 = 1) WHERE (t0.amount = ANY (SELECT t3.amount FROM Customer t1, Order t2, Order t3 WHERE (t2.oid = t3.oid) AND t1.countryCode = t2.CUSTOMER_COUNTRYCODE AND t1.id = t2.CUSTOMER_ID )) 
> The correct SQL should be:
> SELECT t0.oid, t1.name FROM Order t0 JOIN Customer t1 ON (1 = 1) WHERE (t0.amount = ANY (SELECT t3.amount FROM Order t2, Order t3 WHERE (t2.oid = t3.oid) AND t1.countryCode = t2.CUSTOMER_COUNTRYCODE AND t1.id = t2.CUSTOMER_ID )) 

-- 
This message is automatically generated by JIRA.
-
You can reply to this email to add a comment to the issue online.