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Posted to users@jena.apache.org by "Martin G. Skjæveland" <m....@gmail.com> on 2020/03/03 11:55:39 UTC
Introduce Model.createTypedResource ?
Hi,
ModelCom has the following createResource methods:
Resource createResource()
Create a new anonymous resource whose model is this model.
Resource createResource(AnonId id)
Create a blank node resource with a specified identifier.
Resource createResource(Resource type)
Create a new anonymous resource with a given type.
Resource createResource(String uri)
Create a new resource associated with this model.
Resource createResource(String uri, Resource type)
Create a new resource with a given type.
I incorrectly used createResource(Resource) to create a resource in my
model. No big deal this, but may I suggest to rename
Resource createResource(Resource type)
Resource createResource(String uri, Resource type)
to createTypedResource to avoid confusion?
The reason I use createResource(Resource) to create the Resource "in my"
model is that I need to as(Property.class) cast it, which this gives me
a UnsupportedPolymorphismException if the resource exists without a
model. Now I use createResource(Resource.toURI())
Martin
Re: Introduce Model.createTypedResource ?
Posted by "Martin G. Skjæveland" <m....@gmail.com>.
It is! Thanks!
Martin
On 03/03/2020 13:26, Martynas Jusevičius wrote:
> Maybe Resource.inModel() is what you need?
> https://jena.apache.org/documentation/javadoc/jena/org/apache/jena/rdf/model/Resource.html#inModel-org.apache.jena.rdf.model.Model-
>
> On Tue, Mar 3, 2020 at 12:55 PM Martin G. Skjæveland
> <m....@gmail.com> wrote:
>>
>> Hi,
>>
>> ModelCom has the following createResource methods:
>>
>> Resource createResource()
>> Create a new anonymous resource whose model is this model.
>>
>> Resource createResource(AnonId id)
>> Create a blank node resource with a specified identifier.
>>
>> Resource createResource(Resource type)
>> Create a new anonymous resource with a given type.
>>
>> Resource createResource(String uri)
>> Create a new resource associated with this model.
>>
>> Resource createResource(String uri, Resource type)
>> Create a new resource with a given type.
>>
>>
>> I incorrectly used createResource(Resource) to create a resource in my
>> model. No big deal this, but may I suggest to rename
>>
>> Resource createResource(Resource type)
>> Resource createResource(String uri, Resource type)
>>
>> to createTypedResource to avoid confusion?
>>
>>
>> The reason I use createResource(Resource) to create the Resource "in my"
>> model is that I need to as(Property.class) cast it, which this gives me
>> a UnsupportedPolymorphismException if the resource exists without a
>> model. Now I use createResource(Resource.toURI())
>>
>> Martin
>>
Re: Introduce Model.createTypedResource ?
Posted by Martynas Jusevičius <ma...@atomgraph.com>.
Maybe Resource.inModel() is what you need?
https://jena.apache.org/documentation/javadoc/jena/org/apache/jena/rdf/model/Resource.html#inModel-org.apache.jena.rdf.model.Model-
On Tue, Mar 3, 2020 at 12:55 PM Martin G. Skjæveland
<m....@gmail.com> wrote:
>
> Hi,
>
> ModelCom has the following createResource methods:
>
> Resource createResource()
> Create a new anonymous resource whose model is this model.
>
> Resource createResource(AnonId id)
> Create a blank node resource with a specified identifier.
>
> Resource createResource(Resource type)
> Create a new anonymous resource with a given type.
>
> Resource createResource(String uri)
> Create a new resource associated with this model.
>
> Resource createResource(String uri, Resource type)
> Create a new resource with a given type.
>
>
> I incorrectly used createResource(Resource) to create a resource in my
> model. No big deal this, but may I suggest to rename
>
> Resource createResource(Resource type)
> Resource createResource(String uri, Resource type)
>
> to createTypedResource to avoid confusion?
>
>
> The reason I use createResource(Resource) to create the Resource "in my"
> model is that I need to as(Property.class) cast it, which this gives me
> a UnsupportedPolymorphismException if the resource exists without a
> model. Now I use createResource(Resource.toURI())
>
> Martin
>