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Posted to users@cocoon.apache.org by jo...@duploclique.com on 2003/05/10 17:09:42 UTC

XSL problem...again :(

I've tried to sent this email to the XSL list (XSL-List@lists.mulberrytech.com) but with no sucess...The mail does not appears in the list, I've sucessufly registered at that list :|

If anyone here could help that would be much appreciated 

Thanks everyone 

_____________________________

First of all I would like to the creators of this mailing list :)

I have this XSL code and I would like to parse an authors tag of a XML document. The source file is like this:

<DocSum>
     <Id>12673722</Id>
     (...)
     <Item Name="Authors" Type="String">Kahle B, Hoffend J, Wacker J, Hartschuh W</Item>
     (...)
</DocSum>

I want to parse the Athors parameter, and get something like that:

<authors>
    <name>Kahle B</name>
    <name>Hoffend J</name>
    <name>Wacker J</name>
    (...)
</authors>

For that I'm doing this: to each ID from the a list of ID's we're getting the ID value and that grab the parameter that contains  "Kahle B, Hoffend J, Wacker J, Hartschuh W" 
like the above example.

<authors>
   <xsl:for-each select="idlist/id">
            <xsl:variable name="aux"><xsl:value-of select="."/></xsl:variable>
                    <name><xsl:value-of select="/DocSum[Id=$aux]/Item[@Name='Authors']"/></name>
    <xsl:for-each/>
</authors>

The problem is that the $aux variable isn't working inside the XPath expression :|

Can anyone tell me why?

After we grab the variable containing all the author's name, is it possible to parse the variable using just XSL? 

Many Thanks

Joao Cesar
joaocesar@duploclique.com

Computer Science Student @ Universidade de Lisboa, PORTUGAL

Re: XSL problem...again :(

Posted by João César <jo...@duploclique.com>.
It's everything working :)

It was our problem because we weren't giving the right source data to have
the wanted results :| So the use of $aux was ok. We changed the constructor
althought... :)

Many thanks again :)

Joao Cesar
joaocesar@duploclique.com

Computer Science Student @ Universidade de Lisboa, PORTUGAL


----- Original Message ----- 
From: <jo...@duploclique.com>
To: <co...@xml.apache.org>
Sent: Saturday, May 10, 2003 5:30 PM
Subject: Re: XSL problem...again :(


> Many many many thanks :)
>
> The code you supllied worked just fine, without any changes!
>
> > I don't understand your logic behind this code. What says you that $aux
> > is not working? In general don't use the variable construct as above,
> > but use <xsl:variable name="aux" select=."/>.
>
> Yes that's the problem we're not getting the $aux value, we will try that
> constructor althought.
>
> >Otherwise you create a
> > Result Tree Fragment, which can't be handled like a node-set
> > (http://www.w3.org/TR/xslt#section-Result-Tree-Fragments). Maybe this or
> > an explicit string conversion ( [string(Id) = string($aux)] ) already
> > solves your problem.
>
> We're trying to fix that, and we're reviewing our XML source data because
> it's a little bit confusing...
>
> I'll do some testing and I'll report it here
>
> thanks again!
>
> Joao Cesar
> joaocesar@duploclique.com
>
> Computer Science Student @ Universidade de Lisboa, PORTUGAL
>
>
>
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> To unsubscribe, e-mail: cocoon-users-unsubscribe@xml.apache.org
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>


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Re: XSL problem...again :(

Posted by jo...@duploclique.com.
Many many many thanks :)

The code you supllied worked just fine, without any changes!

> I don't understand your logic behind this code. What says you that $aux
> is not working? In general don't use the variable construct as above,
> but use <xsl:variable name="aux" select=."/>.

Yes that's the problem we're not getting the $aux value, we will try that
constructor althought.

>Otherwise you create a
> Result Tree Fragment, which can't be handled like a node-set
> (http://www.w3.org/TR/xslt#section-Result-Tree-Fragments). Maybe this or
> an explicit string conversion ( [string(Id) = string($aux)] ) already
> solves your problem.

We're trying to fix that, and we're reviewing our XML source data because
it's a little bit confusing...

I'll do some testing and I'll report it here

thanks again!

Joao Cesar
joaocesar@duploclique.com

Computer Science Student @ Universidade de Lisboa, PORTUGAL



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Re: XSL problem...again :(

Posted by Joerg Heinicke <jo...@gmx.de>.
joaocesar@duploclique.com wrote:
> I've tried to sent this email to the XSL list 
> (XSL-List@lists.mulberrytech.com 
> <ma...@lists.mulberrytech.com>) but with no sucess...The mail 
> does not appears in the list, I've sucessufly registered at that list :|

http://www.mulberrytech.com/xsl/xsl-list/, at the end of the page.

> I have this XSL code and I would like to parse an authors tag of a XML 
> document. The source file is like this:
>  
> <DocSum>
>      <Id>12673722</Id>
>      (...)
>      <Item Name="Authors" Type="String">Kahle B, Hoffend J, Wacker J, 
> Hartschuh W</Item>
>      (...)
> </DocSum>
>  
> I want to parse the Athors parameter, and get something like that:
>  
> <authors>
>     <name>Kahle B</name>
>     <name>Hoffend J</name>
>     <name>Wacker J</name>
>     (...)
> </authors>

<xsl:template match="Item[@Name='Authors']">
   <authors>
     <xsl:call-template name="getAuthors">
       <xsl:with-param name="AuthorString" select="normalize-space()"/>
     </xsl:call-template>
   </authors>
</xsl:template>

<xsl:template name="getAuthors">
   <xsl:param name="AuthorString" select="''"/>
   <xsl:choose>
     <xsl:when test="contains($AuthorString, ',')">
       <name>
         <xsl:value-of select="substring-before($AuthorString, ',')"/>
       </name>
       <xsl:call-template name="getAuthors">
         <xsl:with-param name="AuthorString"
                         select="substring-after($AuthorString, ',')"/>
       </xsl:call-template>
     </xsl:when>
     <xsl:otherwise>
       <name>
         <xsl:value-of select="$AuthorString"/>
       </name>
     </xsl:otherwise>
   </xsl:choose>
</xsl:template>

> For that I'm doing this: to each ID from the a list of ID's we're 
> getting the ID value and that grab the parameter that contains  "Kahle 
> B, Hoffend J, Wacker J, Hartschuh W"
> like the above example.
>  
> <authors>
>    <xsl:for-each select="idlist/id">
>             <xsl:variable name="aux"><xsl:value-of 
> select="."/></xsl:variable>
>                     <name><xsl:value-of 
> select="/DocSum[Id=$aux]/Item[@Name='Authors']"/></name>
>     <xsl:for-each/>
> </authors>
>  
> The problem is that the $aux variable isn't working inside the XPath 
> expression :|

I don't understand your logic behind this code. What says you that $aux 
is not working? In general don't use the variable construct as above, 
but use <xsl:variable name="aux" select=."/>. Otherwise you create a 
Result Tree Fragment, which can't be handled like a node-set 
(http://www.w3.org/TR/xslt#section-Result-Tree-Fragments). Maybe this or 
an explicit string conversion ( [string(Id) = string($aux)] ) already 
solves your problem.

Joerg



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