[GitHub] [age] WendelLana commented on issue #951: How to use WHERE caluse after a (WITH .. AS ...)

["WendelLana (via GitHub)" <gi...@apache.org>]

WendelLana commented on issue #951:
URL: https://github.com/apache/age/issues/951#issuecomment-1567203145

   In your particular case, you don't need to use a WHERE clause, it's simply replaced with a MATCH clause, like this:
   ```
   SELECT * from cypher('munmud', $$
   MATCH (u:User {id: 'user1'})-[:WATCHED]->(m:Movie)
   WITH DISTINCT m as watchedMovies
   	MATCH (g:Genre)<-[]-(watchedMovies)
   	WITH DISTINCT g as genre
   		MATCH (genre)<-[:BELONGS_TO]-(am)
   		WITH DISTINCT am as allMovie
   			MATCH (u:User {id: 'user1'})-[:WATCHED]->(allMovie)
   			RETURN allMovie
   $$) as (V agtype);
   ```
   
   However, I didn't get why you need all this MATCH clauses if your query would return the same result with a simple query like this:
   ```
   SELECT * from cypher('munmud', $$
   MATCH (u:User {id: 'user1'})-[:WATCHED]->(m:Movie)
   RETURN m
   $$) as (V agtype);
   ```
   If you want to get all movies genres watched by a particular person than return all movies that another person watched from those same genres using a WHERE clause, you could do this:
   ```
   SELECT * from cypher('munmud', $$
   MATCH (u:User {id: 'user1'})-[:WATCHED]->(m:Movie)
   WITH DISTINCT m as watchedMovies
   	MATCH (g:Genre)<-[]-(watchedMovies)
   	WITH DISTINCT g as genre
   		MATCH (genre)<-[:BELONGS_TO]-(am)
   		WITH DISTINCT am as allMovies
   			MATCH (u:User)-[:WATCHED]->(allMovies)
   			WITH u as user, allMovies as movie
   				WHERE user.id = 'user2'
   				RETURN movie
   $$) as (V agtype);
   ```


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