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Posted to issues-all@impala.apache.org by "Csaba Ringhofer (JIRA)" <ji...@apache.org> on 2019/04/04 15:39:00 UTC

[jira] [Commented] (IMPALA-8386) Incorrect predicate in a left outer join query

    [ https://issues.apache.org/jira/browse/IMPALA-8386?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=16809987#comment-16809987 ] 

Csaba Ringhofer commented on IMPALA-8386:
-----------------------------------------

I could slightly simplify the query, the aggregates + group by are actually not needed, a single field with two aliases is enough:

select count(1) from (
    select t2.a_id,t2.amount1,t2.amount2
    from( select a_id from a) t1
    left outer join (
        select c.a_id, amount as amount1, amount as amount2
        from b join c  on b.b_id = c.b_id) t2
    on t1.a_id = t2.a_id
) t;
-- returns 1

> Incorrect predicate in a left outer join query
> ----------------------------------------------
>
>                 Key: IMPALA-8386
>                 URL: https://issues.apache.org/jira/browse/IMPALA-8386
>             Project: IMPALA
>          Issue Type: Bug
>            Reporter: Quanlong Huang
>            Assignee: Quanlong Huang
>            Priority: Critical
>
> skyyws <sk...@163.com> reported a bug [in the mailing list|https://lists.apache.org/thread.html/0bdbbaa6bb35b552f050ae30587b7d75b78a72ec60007a8bc0a4a8a9@%3Cdev.impala.apache.org%3E] on the following data set:
> {code:java}
> table A
> +------+
> | a_id |
> +------+
> | 1    |
> | 2    |
> +------+
> table B
> +------+--------+
> | b_id | amount |
> +------+--------+
> | 1    | 10     |
> | 1    | 20     |
> | 2    | NULL   |
> +------+--------+
> table C
> +------+------+
> | a_id | b_id |
> +------+------+
> | 1    | 1    |
> | 2    | 2    |
> +------+------+{code}
> The following query returns a wrong result "1":
> {code:java}
> select count(1) from (
>     select t2.a_id,t2.amount1,t2.amount2
>     from( select a_id from a) t1
>     left outer join (
>         select c.a_id,sum(amount) as amount1,sum(amount) as amount2
>         from b join c  on b.b_id = c.b_id group by c.a_id) t2
>     on t1.a_id = t2.a_id
> ) t;
> {code}
> Removing "t2.amount2" can get the right result "2":
> {code:java}
> select count(1) from (
>     select t2.a_id,t2.amount1
>     from( select a_id from a) t1
>     left outer join (
>         select c.a_id,sum(amount) as amount1,sum(amount) as amount2
>         from b join c  on b.b_id = c.b_id group by c.a_id) t2
>     on t1.a_id = t2.a_id
> ) t;
> {code}



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