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Posted to solr-user@lucene.apache.org by 刘健 <li...@duokan.com> on 2013/08/20 03:50:35 UTC
Custom Sort(0.2*relervanceScore + 0.8*numberic_field_value)
Hello:
I want to get final search result sorted by (0.2*relervance score + 0.8* specified_numberic_field) .
I have known that if I use “bf”in edismax (e.g. bf=field(value)), I can get a result sorted by(relervance sore + field(value)) ,but I don`t know how to Implement the result sorted by (0.2*relervance score + 0.8*specified_numberic_field) .
Thanks!
Leo
Re: Custom Sort(0.2*relervanceScore + 0.8*numberic_field_value)
Posted by 刘健 <li...@duokan.com>.
Thank you very much!
Then could you tell me how to implement relervance_score*numberic_field/(relervance_score + numberic_field) ? I think it's better to sort by harmmean
------------------ Original ------------------
From: "Jack Krupansky"<ja...@basetechnology.com>;
Date: Tue, Aug 20, 2013 10:47 AM
To: "solr-user"<so...@lucene.apache.org>;
Subject: Re: Custom Sort(0.2*relervanceScore + 0.8*numberic_field_value)
Edismax applies the multiplicative boost ("boost") after applying the
additive boost functions ("bf").
I think (0.2*relervance score + 0.8* specified_numberic_field) should be
equivalent to:
0.2*(relevance score + (0.8/0.2)* specified_numeric_field)
or
0.2*(relevance score + 4.0* specified_numeric_field)
Unless the actual numeric range of the scores matters, just use:
relevance score + 4.0* specified_numeric_field
or
bf=mul(4.0, specified_numeric_field)
-- Jack Krupansky
-----Original Message-----
From: 刘健
Sent: Monday, August 19, 2013 9:50 PM
To: solr-user
Subject: Custom Sort(0.2*relervanceScore + 0.8*numberic_field_value)
Hello:
I want to get final search result sorted by (0.2*relervance score +
0.8* specified_numberic_field) .
I have known that if I use “bf”in edismax (e.g. bf=field(value)), I can get
a result sorted by(relervance sore + field(value)) ,but I don`t know how to
Implement the result sorted by (0.2*relervance score +
0.8*specified_numberic_field) .
Thanks!
Leo
Re: Custom Sort(0.2*relervanceScore + 0.8*numberic_field_value)
Posted by Jack Krupansky <ja...@basetechnology.com>.
Edismax applies the multiplicative boost ("boost") after applying the
additive boost functions ("bf").
I think (0.2*relervance score + 0.8* specified_numberic_field) should be
equivalent to:
0.2*(relevance score + (0.8/0.2)* specified_numeric_field)
or
0.2*(relevance score + 4.0* specified_numeric_field)
Unless the actual numeric range of the scores matters, just use:
relevance score + 4.0* specified_numeric_field
or
bf=mul(4.0, specified_numeric_field)
-- Jack Krupansky
-----Original Message-----
From: 刘健
Sent: Monday, August 19, 2013 9:50 PM
To: solr-user
Subject: Custom Sort(0.2*relervanceScore + 0.8*numberic_field_value)
Hello:
I want to get final search result sorted by (0.2*relervance score +
0.8* specified_numberic_field) .
I have known that if I use “bf”in edismax (e.g. bf=field(value)), I can get
a result sorted by(relervance sore + field(value)) ,but I don`t know how to
Implement the result sorted by (0.2*relervance score +
0.8*specified_numberic_field) .
Thanks!
Leo