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Posted to github@arrow.apache.org by GitBox <gi...@apache.org> on 2021/04/04 09:59:05 UTC

[GitHub] [arrow] alamb commented on a change in pull request #9806: ARROW-11991: [Rust][DataFusion] Maintain partition information in Union

alamb commented on a change in pull request #9806:
URL: https://github.com/apache/arrow/pull/9806#discussion_r606777115



##########
File path: rust/datafusion/src/physical_plan/union.rs
##########
@@ -60,15 +60,31 @@ impl ExecutionPlan for UnionExec {
 
     /// Output of the union is the combination of all output partitions of the inputs
     fn output_partitioning(&self) -> Partitioning {
-        // Sums all the output partitions
-        let num_partitions = self
-            .inputs
+        let intial: Option<Partitioning> = None;
+        self.inputs
             .iter()
-            .map(|plan| plan.output_partitioning().partition_count())
-            .sum();
-        // TODO: this loses partitioning info in case of same partitioning scheme (for example `Partitioning::Hash`)
-        // https://issues.apache.org/jira/browse/ARROW-11991
-        Partitioning::UnknownPartitioning(num_partitions)
+            .fold(intial, |acc, input| {
+                match (acc, input.output_partitioning()) {
+                    (None, partition) => Some(partition),
+                    (
+                        Some(Partitioning::Hash(mut vector_acc, size_acc)),
+                        Partitioning::Hash(vector, size),
+                    ) => {
+                        vector_acc.append(&mut vector.clone());

Review comment:
       I am not sure this is correct -- of the input is hash partitioned by some expression across `size_acc` partitions, the output will only be hash partitioned if the hash expressions are the same and the number of output partitions is the same, right?

##########
File path: rust/datafusion/src/physical_plan/union.rs
##########
@@ -60,15 +60,31 @@ impl ExecutionPlan for UnionExec {
 
     /// Output of the union is the combination of all output partitions of the inputs
     fn output_partitioning(&self) -> Partitioning {
-        // Sums all the output partitions
-        let num_partitions = self
-            .inputs
+        let intial: Option<Partitioning> = None;
+        self.inputs
             .iter()
-            .map(|plan| plan.output_partitioning().partition_count())
-            .sum();
-        // TODO: this loses partitioning info in case of same partitioning scheme (for example `Partitioning::Hash`)
-        // https://issues.apache.org/jira/browse/ARROW-11991
-        Partitioning::UnknownPartitioning(num_partitions)
+            .fold(intial, |acc, input| {
+                match (acc, input.output_partitioning()) {
+                    (None, partition) => Some(partition),
+                    (
+                        Some(Partitioning::Hash(mut vector_acc, size_acc)),
+                        Partitioning::Hash(vector, size),
+                    ) => {
+                        vector_acc.append(&mut vector.clone());
+                        Some(Partitioning::Hash(vector_acc, size_acc + size))
+                    }
+                    (
+                        Some(Partitioning::RoundRobinBatch(size_acc)),
+                        Partitioning::RoundRobinBatch(size),
+                    ) => Some(Partitioning::RoundRobinBatch(size_acc + size)),

Review comment:
       I think the output batch size might be more precisely described as  `max(size_acc, size)` 
   
   though I am unsure of the requirements on a operator that produces `RoundRobinBatch(1000)` -- does that mean all batches must be 1000? The docs on [`Partitioning`](https://github.com/apache/arrow/blob/8e43f23dcc6a9e630516228f110c48b64d13cec6/rust/datafusion/src/physical_plan/mod.rs#L131) are not super clear




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