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Posted to users@wicket.apache.org by Reinout van Schouwen <re...@gmail.com> on 2008/10/08 11:49:04 UTC

AjaxPagingNavigator and IndicatingAjaxLink

Hi all,

I tried extending the AjaxPagingNavigator class to provide some feedback
while loading the next page using IndicatingAjaxLink. The
(not-compiling) code I wrote is below. I couldn't make it work because
the protected methods in AjaxPagingNavigator return a Link, as AjaxLink
is a sibling of Link instead of a subclass.

Why doesn't the AjaxPagingNavigator use an AjaxLink in the first place?

Suggestions welcome.


/* this doesn't work because IndicatingAjaxLink is not a subclass of Link
     class IndicatingAjaxPagingNavigator extends AjaxPagingNavigator {

        public IndicatingAjaxPagingNavigator(String id, IPageable pageable) {
            super(id, pageable);
        }
        
        @Override
        protected Link newPagingNavigationLink(String id, IPageable pageable, int pageNumber) {
            final Link result = super.newPagingNavigationIncrementLink(id, pageable, pageNumber);
            
            return new IndicatingAjaxLink(id) {

                @Override
                public void onClick(AjaxRequestTarget target) {
                    result.onClick();
                }
            };
        }
    } 
*/

regards,

-- 
Reinout van Schouwen



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Re: AjaxPagingNavigator and IndicatingAjaxLink

Posted by Michael Sparer <mi...@gmx.at>.
alright, but that's more CSS fiddling than wicket related
have fun tweaking your styles ;-)

regards,
Michael

Reinout van Schouwen-4 wrote:
> 
> Op woensdag 08-10-2008 om 02:56 uur [tijdzone -0700], schreef Michael
> Sparer:
>> why not just let your IndicatingPagingNavigator implement
>> IAjaxIndicatorAware
>> - then you got your feedback and also have it at one place (only one
>> indicator) instead of multiple indicators as each ajaxlink would have its
>> own ...
> 
> Thanks, that worked. However I'm now trying to figure out how to make
> the indicator be displayed next to the navigator, instead of below. In
> other words, how to make the indicator's  tag appear inside of the
> div instead of outside it. 
> 
> regards,
> 
> -- 
> Reinout van Schouwen
> 
> 
> 
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: users-unsubscribe@wicket.apache.org
> For additional commands, e-mail: users-help@wicket.apache.org
> 
> 
> 


-----
Michael Sparer
http://talk-on-tech.blogspot.com
-- 
View this message in context: http://www.nabble.com/AjaxPagingNavigator-and-IndicatingAjaxLink-tp19875656p19876572.html
Sent from the Wicket - User mailing list archive at Nabble.com.


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Re: AjaxPagingNavigator and IndicatingAjaxLink

Posted by Reinout van Schouwen <re...@gmail.com>.
Op woensdag 08-10-2008 om 02:56 uur [tijdzone -0700], schreef Michael
Sparer:
> why not just let your IndicatingPagingNavigator implement IAjaxIndicatorAware
> - then you got your feedback and also have it at one place (only one
> indicator) instead of multiple indicators as each ajaxlink would have its
> own ...

Thanks, that worked. However I'm now trying to figure out how to make
the indicator be displayed next to the navigator, instead of below. In
other words, how to make the indicator's <span> tag appear inside of the
div instead of outside it. 

regards,

-- 
Reinout van Schouwen



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Re: AjaxPagingNavigator and IndicatingAjaxLink

Posted by Michael Sparer <mi...@gmx.at>.
why not just let your IndicatingPagingNavigator implement IAjaxIndicatorAware
- then you got your feedback and also have it at one place (only one
indicator) instead of multiple indicators as each ajaxlink would have its
own ...

e.g.
public class IndicatingAjaxPagingNavigator extends AjaxPagingNavigator
implements IAjaxIndicatorAware {
    private final WicketAjaxIndicatorAppender _indicatorAppender = new
WicketAjaxIndicatorAppender();

    public IndicatingAjaxPagingNavigator(String id, /* snip */) {
       super(id, /* snip */);
       add(_indicatorAppender);
       // snip
    }

    	public String getAjaxIndicatorMarkupId() {
		return _indicatorAppender.getMarkupId();
	}
}

regards,
Michael

Reinout van Schouwen-4 wrote:
> 
> Hi all,
> 
> I tried extending the AjaxPagingNavigator class to provide some feedback
> while loading the next page using IndicatingAjaxLink. The
> (not-compiling) code I wrote is below. I couldn't make it work because
> the protected methods in AjaxPagingNavigator return a Link, as AjaxLink
> is a sibling of Link instead of a subclass.
> 
> Why doesn't the AjaxPagingNavigator use an AjaxLink in the first place?
> 
> Suggestions welcome.
> 
> 
> /* this doesn't work because IndicatingAjaxLink is not a subclass of Link
>      class IndicatingAjaxPagingNavigator extends AjaxPagingNavigator {
> 
>         public IndicatingAjaxPagingNavigator(String id, IPageable
> pageable) {
>             super(id, pageable);
>         }
>         
>         @Override
>         protected Link newPagingNavigationLink(String id, IPageable
> pageable, int pageNumber) {
>             final Link result = super.newPagingNavigationIncrementLink(id,
> pageable, pageNumber);
>             
>             return new IndicatingAjaxLink(id) {
> 
>                 @Override
>                 public void onClick(AjaxRequestTarget target) {
>                     result.onClick();
>                 }
>             };
>         }
>     } 
> */
> 
> regards,
> 
> -- 
> Reinout van Schouwen
> 
> 
> 
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: users-unsubscribe@wicket.apache.org
> For additional commands, e-mail: users-help@wicket.apache.org
> 
> 
> 


-----
Michael Sparer
http://talk-on-tech.blogspot.com
-- 
View this message in context: http://www.nabble.com/AjaxPagingNavigator-and-IndicatingAjaxLink-tp19875656p19875773.html
Sent from the Wicket - User mailing list archive at Nabble.com.


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