You are viewing a plain text version of this content. The canonical link for it is here.
Posted to dev@tomcat.apache.org by ma...@apache.org on 2006/12/31 03:19:08 UTC

svn commit: r491365 - /tomcat/tc6.0.x/trunk/webapps/docs/jasper-howto.xml

Author: markt
Date: Sat Dec 30 18:19:07 2006
New Revision: 491365

URL: http://svn.apache.org/viewvc?view=rev&rev=491365
Log:
Port doc update for 41182 from TC5

Modified:
    tomcat/tc6.0.x/trunk/webapps/docs/jasper-howto.xml

Modified: tomcat/tc6.0.x/trunk/webapps/docs/jasper-howto.xml
URL: http://svn.apache.org/viewvc/tomcat/tc6.0.x/trunk/webapps/docs/jasper-howto.xml?view=diff&rev=491365&r1=491364&r2=491365
==============================================================================
--- tomcat/tc6.0.x/trunk/webapps/docs/jasper-howto.xml (original)
+++ tomcat/tc6.0.x/trunk/webapps/docs/jasper-howto.xml Sat Dec 30 18:19:07 2006
@@ -84,9 +84,11 @@
 <code>true</code>.
 </li>
 
-<li><strong>classpath</strong> - What class path should I use while compiling
-generated servlets?  By default the classpath is created dynamically based on
-the current web application.</li>
+<li><strong>classpath</strong> - Defines the class path to be used to compile
+the generated servlets. This parameter only has an effect if the ServletContext
+attribute org.apache.jasper.Constants.SERVLET_CLASSPATH is not set. This
+attribute is always set when Jasper is used within Tomcat. By default the
+classpath is created dynamically based on the current web application.</li>
 
 <li><strong>compilerSourceVM</strong> - What JDK version are the source files compatible with? (Default JDK 1.4)</li>
 



---------------------------------------------------------------------
To unsubscribe, e-mail: dev-unsubscribe@tomcat.apache.org
For additional commands, e-mail: dev-help@tomcat.apache.org