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Posted to commits@cassandra.apache.org by "Alex Petrov (JIRA)" <ji...@apache.org> on 2016/09/13 12:38:20 UTC

[jira] [Updated] (CASSANDRA-12621) How to query '%' character using LIKE operator in Cassandra 3.7?

     [ https://issues.apache.org/jira/browse/CASSANDRA-12621?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Alex Petrov updated CASSANDRA-12621:
------------------------------------
    Labels: sasi  (was: )

> How to query '%' character using LIKE operator in Cassandra 3.7?
> ----------------------------------------------------------------
>
>                 Key: CASSANDRA-12621
>                 URL: https://issues.apache.org/jira/browse/CASSANDRA-12621
>             Project: Cassandra
>          Issue Type: Bug
>            Reporter: Mikhail Krupitskiy
>            Priority: Critical
>              Labels: sasi
>
> I use Cassandra 3.7 and have a text column with SASI index. Let's assume that I want to find column values that contain '%' character somewhere in the middle. The problem is that '%' is a command char for LIKE clauses. How to escape '%' char in a query like LIKE '%%%'?
> Here is a test script:
> DROP keyspace if exists kmv;
> CREATE keyspace if not exists kmv WITH REPLICATION = { 'class' : 'SimpleStrategy', 'replication_factor':'1'} ;
> USE kmv;
> CREATE TABLE if not exists kmv (id int, c1 text, c2 text, PRIMARY KEY(id, c1));
> CREATE CUSTOM INDEX ON kmv.kmv  ( c2 ) USING 'org.apache.cassandra.index.sasi.SASIIndex' WITH OPTIONS = {
> 'analyzed' : 'true',
> 'analyzer_class' : 'org.apache.cassandra.index.sasi.analyzer.NonTokenizingAnalyzer',
> 'case_sensitive' : 'false', 
> 'mode' : 'CONTAINS'
> };
> INSERT into kmv (id, c1, c2) values (1, 'f22', 'qwe%asd');
> SELECT c2 from kmv.kmv where c2 like '%$$%$$%';
> The select query returns nothing.



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