RE: XSLTOutInterceptor xsl file path

[Andrei Shakirin <as...@talend.com>]

Hi,

It is enough to put your xsl script on the classpath and specify script name in feature or in interceptor constructor.
Do you have an exception or your transformation wasn't applied?

See following system test for details: org.apache.cxf.systest.transform.feature.TransformFeatureTest
XSLT feature is also documented here: http://cxf.apache.org/docs/xslt-feature.html .

Regards,
Andrei.


> -----Original Message-----
> From: ivnguru [mailto:ivan.vaskevych@gmail.com]
> Sent: Dienstag, 30. September 2014 16:56
> To: users@cxf.apache.org
> Subject: XSLTOutInterceptor xsl file path
> 
> Hi,
> 
> I'm trying to use XSLTOutInterceptor. How the path to xsl file should look like in
> a constructor?
> I'm using it from Jboss AS. Simply using "filename.xsl" and copying it to
> classpath (war/WEB-INF/classes) doesn't seem to work.
> 
> Thanks!
> 
> 
> 
> --
> View this message in context:
> http://cxf.547215.n5.nabble.com/XSLTOutInterceptor-xsl-file-path-
> tp5749355.html
> Sent from the cxf-user mailing list archive at Nabble.com.