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Posted to user@xmlbeans.apache.org by imorales <im...@ignos.com> on 2007/11/06 10:29:28 UTC
xmlbeans beginner - help
Hi is my first time using xmlbeans and I hava a couple of question, I explain
my scenario and I would like someone to resolve my ignorance about xmlbeans.
Well I hava a pojo class:
------------------------------------------
public class A{
private String b;
public A(){}
public String getB(){ return b;}
public void setB(String b){this.b = b;}
}
------------------------------------------
I´m using a web service that takes one parameter (String), this parameter is
the XML associated to the class A. My question is how I can using xmlbeans
conver one object A to a XML and then to String. I have no schema to do this
and I don´t know if is necessary.
Thanks in advance.
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RE: xmlbeans beginner - help
Posted by imorales <im...@ignos.com>.
Well finally I had to get de schema and generate de pojos with the schema.
And now the pojo´'s have methos innerits from XmlObject and more...
Thanks all for the help.
imorales wrote:
>
> Well my scenario is:
>
> I have a web service that take a String parameter, this String represents
> a XML and this a pojo class (A). I need parse this XML parameter in the
> server side parse it and add/remove/modify elements if I need:
>
> webServiceMethod(String xml){
> A a = convertStringXmlToPojo(xml) / or / XmlObject xobj =
> convertStringXmlToXmlObject(xml)
> parse a / or / parse xobj (check add/modify/remove...)
> String res = converPojoToString(a) / or / res =
> convertXmlObjectToString(xobj)
> return res
> }
>
>
>
>
> Vinh Nguyen (vinguye2) wrote:
>>
>> Imorales,
>> I think what you want is to automatically convert a POJO into an XML
>> string, right? That way, you can convert the XML string into an
>> XmlObject?
>>
>> Not sure why you need to do that if you can already work with the POJO
>> directly.
>>
>> Other than that, as Paul pointed out, you can use XStream to
>> automatically deserialize your POJO to XML. Then, you should be able to
>> convert the XML into an untyped XmlObject. But, you probably would only
>> use the XmlObject for traversing the XML tree. You won't have methods
>> like getB() and setB() since you aren't generating the XmlObject from a
>> predefined schema.
>>
>>
>>
>> -----Original Message-----
>> From: Paul French [mailto:paul.french@frenchiesystems.com]
>> Sent: Tuesday, November 06, 2007 11:53 AM
>> To: user@xmlbeans.apache.org
>> Subject: RE: xmlbeans beginner - help
>>
>> XStream does exactly what you want.
>>
>> Paul
>>
>> -----Original Message-----
>> From: Wing Yew Poon [mailto:wpoon@bea.com]
>> Sent: 06 November 2007 19:34
>> To: user@xmlbeans.apache.org
>> Subject: RE: xmlbeans beginner - help
>>
>> imorales,
>> I think you're looking for something that XMLBeans is not designed for.
>> It sounds like you want to start with a POJO class and somehow
>> automagically get something like an XmlObject out of it. There is no
>> mechanism to do that.
>> What Cezar wrote about is the capability of XMLBeans to parse xml without
>> a schema to get an untyped XmlObject. So if you are getting xml from
>> somewhere, you can turn that xml into an XmlObject. But it sounds like
>> you're looking for something else.
>> - Wing Yew
>>
>> -----Original Message-----
>> From: imorales [mailto:imorales@ignos.com]
>> Sent: Tuesday, November 06, 2007 7:41 AM
>> To: user@xmlbeans.apache.org
>> Subject: RE: xmlbeans beginner - help
>>
>>
>> Yes I know but, can I convert a simple java class A to a XmlObject
>> without
>> schema ?
>>
>> Albert Bupp wrote:
>>>
>>> He means the XmlObject class which you'll find in the XmlBeans
>> library.
>>>
>>> -Albert
>>>
>>> At 10:27 AM 11/6/2007, you wrote:
>>>
>>>>That sounds good but, I don´t have a XmlObject, I have a simple pojo
>> (class
>>>>A) and i want to convert it to XmlObject, my class A have to
>> implements
>>>>XmlObject ? How can I do this ??
>>>>
>>>>Cezar Andrei wrote:
>>>> >
>>>> > It is possible, but a little less forward that using schema. Just
>> use
>>>> > XmlObject, it handles all un-typed XML in XMLBeans.
>>>> >
>>>> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
>>>> into
>>>> > XmlObject.
>>>> > And String xmlText = xo.xmlText() to get back to xml.
>>>> >
>>>> > To navigate/read/modify the XmlObject without a schema, you have to
>> use
>>>> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
>>>> >
>>>> > Cezar
>>>> >
>>>> >> -----Original Message-----
>>>> >> From: imorales [mailto:imorales@ignos.com]
>>>> >> Sent: Tuesday, November 06, 2007 8:50 AM
>>>> >> To: user@xmlbeans.apache.org
>>>> >> Subject: RE: xmlbeans beginner - help
>>>> >>
>>>> >>
>>>> >> Is there any way to get from Java classes without XML schema and
>> vice
>>>> >> versa?
>>>> >>
>>>> >> Thanks.
>>>> >>
>>>> >> Schalk Neethling-4 wrote:
>>>> >> >
>>>> >> > You will more then likely have to start with a schema. So define
>>>> your
>>>> >> > schema and the from this generate your XMLBean which will give
>> you
>>>> >> object
>>>> >> > A, you can then populate object A using the set methods that
>> will be
>>>> >> > generated and once you have the completed object you can invert
>> it
>>>> into
>>>> >> a
>>>> >> > XML string with one step by calling A.xmlText();
>>>> >> >
>>>> >> > HTH!
>>>> >> >
>>>> >> > Regards,
>>>> >> > Schalk Neethling
>>>> >> >
>>>> >> > -----Original Message-----
>>>> >> > From: imorales [mailto:imorales@ignos.com]
>>>> >> > Sent: 06 November 2007 11:29 AM
>>>> >> > To: user@xmlbeans.apache.org
>>>> >> > Subject: xmlbeans beginner - help
>>>> >> >
>>>> >> >
>>>> >> > Hi is my first time using xmlbeans and I hava a couple of
>> question,
>>>> I
>>>> >> > explain
>>>> >> > my scenario and I would like someone to resolve my ignorance
>> about
>>>> >> > xmlbeans.
>>>> >> >
>>>> >> > Well I hava a pojo class:
>>>> >> >
>>>> >> > ------------------------------------------
>>>> >> > public class A{
>>>> >> > private String b;
>>>> >> >
>>>> >> > public A(){}
>>>> >> >
>>>> >> > public String getB(){ return b;}
>>>> >> > public void setB(String b){this.b = b;}
>>>> >> > }
>>>> >> > ------------------------------------------
>>>> >> >
>>>> >> > I´m using a web service that takes one parameter (String), this
>>>> >> parameter
>>>> >> > is
>>>> >> > the XML associated to the class A. My question is how I can
>> using
>>>> >> xmlbeans
>>>> >> > conver one object A to a XML and then to String. I have no
>> schema to
>>>> do
>>>> >> > this
>>>> >> > and I don´t know if is necessary.
>>>> >> >
>>>> >> > Thanks in advance.
>>>> >> >
>>>> >> > --
>>>> >> > View this message in context:
>>>> >> >
>>>>
>> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>>>> >> > Sent from the Xml Beans - User mailing list archive at
>> Nabble.com.
>>>> >> >
>>>> >> >
>>>> >> >
>>>> ---------------------------------------------------------------------
>>>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>>>> >> >
>>>> >> >
>>>> >> > This email and all content are subject to the following
>> disclaimer:
>>>> >> >
>>>> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
>>>> >> >
>>>> >> >
>>>> >> >
>>>> >> >
>>>> ---------------------------------------------------------------------
>>>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>>>> >> >
>>>> >> >
>>>> >> >
>>>> >>
>>>> >> --
>>>> >> View this message in context:
>>>> http://www.nabble.com/xmlbeans-beginner---
>>>> >> help-tf4756991.html#a13608035
>>>> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>>> >>
>>>> >>
>>>> >>
>> ---------------------------------------------------------------------
>>>> >> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>>> >> For additional commands, e-mail: user-help@xmlbeans.apache.org
>>>> >
>>>> >
>>>> > Notice: This email message, together with any attachments, may
>> contain
>>>> > information of BEA Systems, Inc., its subsidiaries and
>> affiliated
>>>> > entities, that may be confidential, proprietary, copyrighted
>> and/or
>>>> > legally privileged, and is intended solely for the use of the
>>>> individual
>>>> > or entity named in this message. If you are not the intended
>> recipient,
>>>> > and have received this message in error, please immediately return
>> this
>>>> by
>>>> > email and then delete it.
>>>> >
>>>> >
>> ---------------------------------------------------------------------
>>>> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>>> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>>>> >
>>>> >
>>>> >
>>>>
>>>>--
>>>>View this message in context:
>>>>http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a1360887
>> 5
>>>>Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>>>
>>>>
>>>>---------------------------------------------------------------------
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>>>>For additional commands, e-mail: user-help@xmlbeans.apache.org
>>>
>>>
>>>
>>> ---------------------------------------------------------------------
>>> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>> For additional commands, e-mail: user-help@xmlbeans.apache.org
>>>
>>>
>>>
>>
>> --
>> View this message in context:
>> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13609293
>> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> For additional commands, e-mail: user-help@xmlbeans.apache.org
>>
>>
>> Notice: This email message, together with any attachments, may contain
>> information of BEA Systems, Inc., its subsidiaries and affiliated
>> entities, that may be confidential, proprietary, copyrighted and/or
>> legally privileged, and is intended solely for the use of the individual
>> or entity named in this message. If you are not the intended recipient,
>> and have received this message in error, please immediately return this
>> by email and then delete it.
>>
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>>
>>
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> For additional commands, e-mail: user-help@xmlbeans.apache.org
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> For additional commands, e-mail: user-help@xmlbeans.apache.org
>>
>>
>>
>
>
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RE: xmlbeans beginner - help
Posted by imorales <im...@ignos.com>.
Well my scenario is:
I have a web service that take a String parameter, this String represents a
XML and this a pojo class (A). I need parse this XML parameter in the server
side parse it and add/remove/modify elements if I need:
webServiceMethod(String xml){
A a = convertStringXmlToPojo(xml) / or / XmlObject xobj =
convertStringXmlToXmlObject(xml)
parse a / or / parse xobj (check add/modify/remove...)
String res = converPojoToString(a) / or / res =
convertXmlObjectToString(xobj)
return res
}
Vinh Nguyen (vinguye2) wrote:
>
> Imorales,
> I think what you want is to automatically convert a POJO into an XML
> string, right? That way, you can convert the XML string into an
> XmlObject?
>
> Not sure why you need to do that if you can already work with the POJO
> directly.
>
> Other than that, as Paul pointed out, you can use XStream to automatically
> deserialize your POJO to XML. Then, you should be able to convert the XML
> into an untyped XmlObject. But, you probably would only use the XmlObject
> for traversing the XML tree. You won't have methods like getB() and
> setB() since you aren't generating the XmlObject from a predefined schema.
>
>
>
> -----Original Message-----
> From: Paul French [mailto:paul.french@frenchiesystems.com]
> Sent: Tuesday, November 06, 2007 11:53 AM
> To: user@xmlbeans.apache.org
> Subject: RE: xmlbeans beginner - help
>
> XStream does exactly what you want.
>
> Paul
>
> -----Original Message-----
> From: Wing Yew Poon [mailto:wpoon@bea.com]
> Sent: 06 November 2007 19:34
> To: user@xmlbeans.apache.org
> Subject: RE: xmlbeans beginner - help
>
> imorales,
> I think you're looking for something that XMLBeans is not designed for.
> It sounds like you want to start with a POJO class and somehow
> automagically get something like an XmlObject out of it. There is no
> mechanism to do that.
> What Cezar wrote about is the capability of XMLBeans to parse xml without
> a schema to get an untyped XmlObject. So if you are getting xml from
> somewhere, you can turn that xml into an XmlObject. But it sounds like
> you're looking for something else.
> - Wing Yew
>
> -----Original Message-----
> From: imorales [mailto:imorales@ignos.com]
> Sent: Tuesday, November 06, 2007 7:41 AM
> To: user@xmlbeans.apache.org
> Subject: RE: xmlbeans beginner - help
>
>
> Yes I know but, can I convert a simple java class A to a XmlObject
> without
> schema ?
>
> Albert Bupp wrote:
>>
>> He means the XmlObject class which you'll find in the XmlBeans
> library.
>>
>> -Albert
>>
>> At 10:27 AM 11/6/2007, you wrote:
>>
>>>That sounds good but, I don´t have a XmlObject, I have a simple pojo
> (class
>>>A) and i want to convert it to XmlObject, my class A have to
> implements
>>>XmlObject ? How can I do this ??
>>>
>>>Cezar Andrei wrote:
>>> >
>>> > It is possible, but a little less forward that using schema. Just
> use
>>> > XmlObject, it handles all un-typed XML in XMLBeans.
>>> >
>>> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
>>> into
>>> > XmlObject.
>>> > And String xmlText = xo.xmlText() to get back to xml.
>>> >
>>> > To navigate/read/modify the XmlObject without a schema, you have to
> use
>>> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
>>> >
>>> > Cezar
>>> >
>>> >> -----Original Message-----
>>> >> From: imorales [mailto:imorales@ignos.com]
>>> >> Sent: Tuesday, November 06, 2007 8:50 AM
>>> >> To: user@xmlbeans.apache.org
>>> >> Subject: RE: xmlbeans beginner - help
>>> >>
>>> >>
>>> >> Is there any way to get from Java classes without XML schema and
> vice
>>> >> versa?
>>> >>
>>> >> Thanks.
>>> >>
>>> >> Schalk Neethling-4 wrote:
>>> >> >
>>> >> > You will more then likely have to start with a schema. So define
>>> your
>>> >> > schema and the from this generate your XMLBean which will give
> you
>>> >> object
>>> >> > A, you can then populate object A using the set methods that
> will be
>>> >> > generated and once you have the completed object you can invert
> it
>>> into
>>> >> a
>>> >> > XML string with one step by calling A.xmlText();
>>> >> >
>>> >> > HTH!
>>> >> >
>>> >> > Regards,
>>> >> > Schalk Neethling
>>> >> >
>>> >> > -----Original Message-----
>>> >> > From: imorales [mailto:imorales@ignos.com]
>>> >> > Sent: 06 November 2007 11:29 AM
>>> >> > To: user@xmlbeans.apache.org
>>> >> > Subject: xmlbeans beginner - help
>>> >> >
>>> >> >
>>> >> > Hi is my first time using xmlbeans and I hava a couple of
> question,
>>> I
>>> >> > explain
>>> >> > my scenario and I would like someone to resolve my ignorance
> about
>>> >> > xmlbeans.
>>> >> >
>>> >> > Well I hava a pojo class:
>>> >> >
>>> >> > ------------------------------------------
>>> >> > public class A{
>>> >> > private String b;
>>> >> >
>>> >> > public A(){}
>>> >> >
>>> >> > public String getB(){ return b;}
>>> >> > public void setB(String b){this.b = b;}
>>> >> > }
>>> >> > ------------------------------------------
>>> >> >
>>> >> > I´m using a web service that takes one parameter (String), this
>>> >> parameter
>>> >> > is
>>> >> > the XML associated to the class A. My question is how I can
> using
>>> >> xmlbeans
>>> >> > conver one object A to a XML and then to String. I have no
> schema to
>>> do
>>> >> > this
>>> >> > and I don´t know if is necessary.
>>> >> >
>>> >> > Thanks in advance.
>>> >> >
>>> >> > --
>>> >> > View this message in context:
>>> >> >
>>>
> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>>> >> > Sent from the Xml Beans - User mailing list archive at
> Nabble.com.
>>> >> >
>>> >> >
>>> >> >
>>> ---------------------------------------------------------------------
>>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>>> >> >
>>> >> >
>>> >> > This email and all content are subject to the following
> disclaimer:
>>> >> >
>>> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
>>> >> >
>>> >> >
>>> >> >
>>> >> >
>>> ---------------------------------------------------------------------
>>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>>> >> >
>>> >> >
>>> >> >
>>> >>
>>> >> --
>>> >> View this message in context:
>>> http://www.nabble.com/xmlbeans-beginner---
>>> >> help-tf4756991.html#a13608035
>>> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>> >>
>>> >>
>>> >>
> ---------------------------------------------------------------------
>>> >> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>> >> For additional commands, e-mail: user-help@xmlbeans.apache.org
>>> >
>>> >
>>> > Notice: This email message, together with any attachments, may
> contain
>>> > information of BEA Systems, Inc., its subsidiaries and
> affiliated
>>> > entities, that may be confidential, proprietary, copyrighted
> and/or
>>> > legally privileged, and is intended solely for the use of the
>>> individual
>>> > or entity named in this message. If you are not the intended
> recipient,
>>> > and have received this message in error, please immediately return
> this
>>> by
>>> > email and then delete it.
>>> >
>>> >
> ---------------------------------------------------------------------
>>> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>>> >
>>> >
>>> >
>>>
>>>--
>>>View this message in context:
>>>http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a1360887
> 5
>>>Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>>
>>>
>>>---------------------------------------------------------------------
>>>To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>>>For additional commands, e-mail: user-help@xmlbeans.apache.org
>>
>>
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> For additional commands, e-mail: user-help@xmlbeans.apache.org
>>
>>
>>
>
> --
> View this message in context:
> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13609293
> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> For additional commands, e-mail: user-help@xmlbeans.apache.org
>
>
> Notice: This email message, together with any attachments, may contain
> information of BEA Systems, Inc., its subsidiaries and affiliated
> entities, that may be confidential, proprietary, copyrighted and/or
> legally privileged, and is intended solely for the use of the individual
> or entity named in this message. If you are not the intended recipient,
> and have received this message in error, please immediately return this
> by email and then delete it.
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> For additional commands, e-mail: user-help@xmlbeans.apache.org
>
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> For additional commands, e-mail: user-help@xmlbeans.apache.org
>
> ---------------------------------------------------------------------
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> For additional commands, e-mail: user-help@xmlbeans.apache.org
>
>
>
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RE: xmlbeans beginner - help
Posted by "Vinh Nguyen (vinguye2)" <vi...@cisco.com>.
Imorales,
I think what you want is to automatically convert a POJO into an XML string, right? That way, you can convert the XML string into an XmlObject?
Not sure why you need to do that if you can already work with the POJO directly.
Other than that, as Paul pointed out, you can use XStream to automatically deserialize your POJO to XML. Then, you should be able to convert the XML into an untyped XmlObject. But, you probably would only use the XmlObject for traversing the XML tree. You won't have methods like getB() and setB() since you aren't generating the XmlObject from a predefined schema.
-----Original Message-----
From: Paul French [mailto:paul.french@frenchiesystems.com]
Sent: Tuesday, November 06, 2007 11:53 AM
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help
XStream does exactly what you want.
Paul
-----Original Message-----
From: Wing Yew Poon [mailto:wpoon@bea.com]
Sent: 06 November 2007 19:34
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help
imorales,
I think you're looking for something that XMLBeans is not designed for.
It sounds like you want to start with a POJO class and somehow automagically get something like an XmlObject out of it. There is no mechanism to do that.
What Cezar wrote about is the capability of XMLBeans to parse xml without a schema to get an untyped XmlObject. So if you are getting xml from somewhere, you can turn that xml into an XmlObject. But it sounds like you're looking for something else.
- Wing Yew
-----Original Message-----
From: imorales [mailto:imorales@ignos.com]
Sent: Tuesday, November 06, 2007 7:41 AM
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help
Yes I know but, can I convert a simple java class A to a XmlObject
without
schema ?
Albert Bupp wrote:
>
> He means the XmlObject class which you'll find in the XmlBeans
library.
>
> -Albert
>
> At 10:27 AM 11/6/2007, you wrote:
>
>>That sounds good but, I don´t have a XmlObject, I have a simple pojo
(class
>>A) and i want to convert it to XmlObject, my class A have to
implements
>>XmlObject ? How can I do this ??
>>
>>Cezar Andrei wrote:
>> >
>> > It is possible, but a little less forward that using schema. Just
use
>> > XmlObject, it handles all un-typed XML in XMLBeans.
>> >
>> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
>> into
>> > XmlObject.
>> > And String xmlText = xo.xmlText() to get back to xml.
>> >
>> > To navigate/read/modify the XmlObject without a schema, you have to
use
>> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
>> >
>> > Cezar
>> >
>> >> -----Original Message-----
>> >> From: imorales [mailto:imorales@ignos.com]
>> >> Sent: Tuesday, November 06, 2007 8:50 AM
>> >> To: user@xmlbeans.apache.org
>> >> Subject: RE: xmlbeans beginner - help
>> >>
>> >>
>> >> Is there any way to get from Java classes without XML schema and
vice
>> >> versa?
>> >>
>> >> Thanks.
>> >>
>> >> Schalk Neethling-4 wrote:
>> >> >
>> >> > You will more then likely have to start with a schema. So define
>> your
>> >> > schema and the from this generate your XMLBean which will give
you
>> >> object
>> >> > A, you can then populate object A using the set methods that
will be
>> >> > generated and once you have the completed object you can invert
it
>> into
>> >> a
>> >> > XML string with one step by calling A.xmlText();
>> >> >
>> >> > HTH!
>> >> >
>> >> > Regards,
>> >> > Schalk Neethling
>> >> >
>> >> > -----Original Message-----
>> >> > From: imorales [mailto:imorales@ignos.com]
>> >> > Sent: 06 November 2007 11:29 AM
>> >> > To: user@xmlbeans.apache.org
>> >> > Subject: xmlbeans beginner - help
>> >> >
>> >> >
>> >> > Hi is my first time using xmlbeans and I hava a couple of
question,
>> I
>> >> > explain
>> >> > my scenario and I would like someone to resolve my ignorance
about
>> >> > xmlbeans.
>> >> >
>> >> > Well I hava a pojo class:
>> >> >
>> >> > ------------------------------------------
>> >> > public class A{
>> >> > private String b;
>> >> >
>> >> > public A(){}
>> >> >
>> >> > public String getB(){ return b;}
>> >> > public void setB(String b){this.b = b;}
>> >> > }
>> >> > ------------------------------------------
>> >> >
>> >> > I´m using a web service that takes one parameter (String), this
>> >> parameter
>> >> > is
>> >> > the XML associated to the class A. My question is how I can
using
>> >> xmlbeans
>> >> > conver one object A to a XML and then to String. I have no
schema to
>> do
>> >> > this
>> >> > and I don´t know if is necessary.
>> >> >
>> >> > Thanks in advance.
>> >> >
>> >> > --
>> >> > View this message in context:
>> >> >
>>
http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>> >> > Sent from the Xml Beans - User mailing list archive at
Nabble.com.
>> >> >
>> >> >
>> >> >
>> ---------------------------------------------------------------------
>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >> >
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>> >> >
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>> >> >
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>> >> >
>> >> >
>> >> >
>> >>
>> >> --
>> >> View this message in context:
>> http://www.nabble.com/xmlbeans-beginner---
>> >> help-tf4756991.html#a13608035
>> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >>
>> >>
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>> > entities, that may be confidential, proprietary, copyrighted
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>> > legally privileged, and is intended solely for the use of the
>> individual
>> > or entity named in this message. If you are not the intended
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>> > and have received this message in error, please immediately return
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>> by
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RE: xmlbeans beginner - help
Posted by Paul French <pa...@frenchiesystems.com>.
XStream does exactly what you want.
Paul
-----Original Message-----
From: Wing Yew Poon [mailto:wpoon@bea.com]
Sent: 06 November 2007 19:34
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help
imorales,
I think you're looking for something that XMLBeans is not designed for.
It sounds like you want to start with a POJO class and somehow
automagically
get something like an XmlObject out of it. There is no mechanism to do
that.
What Cezar wrote about is the capability of XMLBeans to parse xml
without
a schema to get an untyped XmlObject. So if you are getting xml from
somewhere,
you can turn that xml into an XmlObject. But it sounds like you're
looking
for something else.
- Wing Yew
-----Original Message-----
From: imorales [mailto:imorales@ignos.com]
Sent: Tuesday, November 06, 2007 7:41 AM
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help
Yes I know but, can I convert a simple java class A to a XmlObject
without
schema ?
Albert Bupp wrote:
>
> He means the XmlObject class which you'll find in the XmlBeans
library.
>
> -Albert
>
> At 10:27 AM 11/6/2007, you wrote:
>
>>That sounds good but, I don´t have a XmlObject, I have a simple pojo
(class
>>A) and i want to convert it to XmlObject, my class A have to
implements
>>XmlObject ? How can I do this ??
>>
>>Cezar Andrei wrote:
>> >
>> > It is possible, but a little less forward that using schema. Just
use
>> > XmlObject, it handles all un-typed XML in XMLBeans.
>> >
>> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
>> into
>> > XmlObject.
>> > And String xmlText = xo.xmlText() to get back to xml.
>> >
>> > To navigate/read/modify the XmlObject without a schema, you have to
use
>> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
>> >
>> > Cezar
>> >
>> >> -----Original Message-----
>> >> From: imorales [mailto:imorales@ignos.com]
>> >> Sent: Tuesday, November 06, 2007 8:50 AM
>> >> To: user@xmlbeans.apache.org
>> >> Subject: RE: xmlbeans beginner - help
>> >>
>> >>
>> >> Is there any way to get from Java classes without XML schema and
vice
>> >> versa?
>> >>
>> >> Thanks.
>> >>
>> >> Schalk Neethling-4 wrote:
>> >> >
>> >> > You will more then likely have to start with a schema. So define
>> your
>> >> > schema and the from this generate your XMLBean which will give
you
>> >> object
>> >> > A, you can then populate object A using the set methods that
will be
>> >> > generated and once you have the completed object you can invert
it
>> into
>> >> a
>> >> > XML string with one step by calling A.xmlText();
>> >> >
>> >> > HTH!
>> >> >
>> >> > Regards,
>> >> > Schalk Neethling
>> >> >
>> >> > -----Original Message-----
>> >> > From: imorales [mailto:imorales@ignos.com]
>> >> > Sent: 06 November 2007 11:29 AM
>> >> > To: user@xmlbeans.apache.org
>> >> > Subject: xmlbeans beginner - help
>> >> >
>> >> >
>> >> > Hi is my first time using xmlbeans and I hava a couple of
question,
>> I
>> >> > explain
>> >> > my scenario and I would like someone to resolve my ignorance
about
>> >> > xmlbeans.
>> >> >
>> >> > Well I hava a pojo class:
>> >> >
>> >> > ------------------------------------------
>> >> > public class A{
>> >> > private String b;
>> >> >
>> >> > public A(){}
>> >> >
>> >> > public String getB(){ return b;}
>> >> > public void setB(String b){this.b = b;}
>> >> > }
>> >> > ------------------------------------------
>> >> >
>> >> > I´m using a web service that takes one parameter (String), this
>> >> parameter
>> >> > is
>> >> > the XML associated to the class A. My question is how I can
using
>> >> xmlbeans
>> >> > conver one object A to a XML and then to String. I have no
schema to
>> do
>> >> > this
>> >> > and I don´t know if is necessary.
>> >> >
>> >> > Thanks in advance.
>> >> >
>> >> > --
>> >> > View this message in context:
>> >> >
>>
http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>> >> > Sent from the Xml Beans - User mailing list archive at
Nabble.com.
>> >> >
>> >> >
>> >> >
>> ---------------------------------------------------------------------
>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >> >
>> >> >
>> >> > This email and all content are subject to the following
disclaimer:
>> >> >
>> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
>> >> >
>> >> >
>> >> >
>> >> >
>> ---------------------------------------------------------------------
>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >> >
>> >> >
>> >> >
>> >>
>> >> --
>> >> View this message in context:
>> http://www.nabble.com/xmlbeans-beginner---
>> >> help-tf4756991.html#a13608035
>> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >>
>> >>
>> >>
---------------------------------------------------------------------
>> >> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >
>> >
>> > Notice: This email message, together with any attachments, may
contain
>> > information of BEA Systems, Inc., its subsidiaries and
affiliated
>> > entities, that may be confidential, proprietary, copyrighted
and/or
>> > legally privileged, and is intended solely for the use of the
>> individual
>> > or entity named in this message. If you are not the intended
recipient,
>> > and have received this message in error, please immediately return
this
>> by
>> > email and then delete it.
>> >
>> >
---------------------------------------------------------------------
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>> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >
>> >
>> >
>>
>>--
>>View this message in context:
>>http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a1360887
5
>>Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>
>>
>>---------------------------------------------------------------------
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>
>
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RE: xmlbeans beginner - help
Posted by Wing Yew Poon <wp...@bea.com>.
imorales,
I think you're looking for something that XMLBeans is not designed for.
It sounds like you want to start with a POJO class and somehow automagically
get something like an XmlObject out of it. There is no mechanism to do that.
What Cezar wrote about is the capability of XMLBeans to parse xml without
a schema to get an untyped XmlObject. So if you are getting xml from somewhere,
you can turn that xml into an XmlObject. But it sounds like you're looking
for something else.
- Wing Yew
-----Original Message-----
From: imorales [mailto:imorales@ignos.com]
Sent: Tuesday, November 06, 2007 7:41 AM
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help
Yes I know but, can I convert a simple java class A to a XmlObject without
schema ?
Albert Bupp wrote:
>
> He means the XmlObject class which you'll find in the XmlBeans library.
>
> -Albert
>
> At 10:27 AM 11/6/2007, you wrote:
>
>>That sounds good but, I don´t have a XmlObject, I have a simple pojo
(class
>>A) and i want to convert it to XmlObject, my class A have to implements
>>XmlObject ? How can I do this ??
>>
>>Cezar Andrei wrote:
>> >
>> > It is possible, but a little less forward that using schema. Just use
>> > XmlObject, it handles all un-typed XML in XMLBeans.
>> >
>> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
>> into
>> > XmlObject.
>> > And String xmlText = xo.xmlText() to get back to xml.
>> >
>> > To navigate/read/modify the XmlObject without a schema, you have to use
>> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
>> >
>> > Cezar
>> >
>> >> -----Original Message-----
>> >> From: imorales [mailto:imorales@ignos.com]
>> >> Sent: Tuesday, November 06, 2007 8:50 AM
>> >> To: user@xmlbeans.apache.org
>> >> Subject: RE: xmlbeans beginner - help
>> >>
>> >>
>> >> Is there any way to get from Java classes without XML schema and vice
>> >> versa?
>> >>
>> >> Thanks.
>> >>
>> >> Schalk Neethling-4 wrote:
>> >> >
>> >> > You will more then likely have to start with a schema. So define
>> your
>> >> > schema and the from this generate your XMLBean which will give you
>> >> object
>> >> > A, you can then populate object A using the set methods that will be
>> >> > generated and once you have the completed object you can invert it
>> into
>> >> a
>> >> > XML string with one step by calling A.xmlText();
>> >> >
>> >> > HTH!
>> >> >
>> >> > Regards,
>> >> > Schalk Neethling
>> >> >
>> >> > -----Original Message-----
>> >> > From: imorales [mailto:imorales@ignos.com]
>> >> > Sent: 06 November 2007 11:29 AM
>> >> > To: user@xmlbeans.apache.org
>> >> > Subject: xmlbeans beginner - help
>> >> >
>> >> >
>> >> > Hi is my first time using xmlbeans and I hava a couple of question,
>> I
>> >> > explain
>> >> > my scenario and I would like someone to resolve my ignorance about
>> >> > xmlbeans.
>> >> >
>> >> > Well I hava a pojo class:
>> >> >
>> >> > ------------------------------------------
>> >> > public class A{
>> >> > private String b;
>> >> >
>> >> > public A(){}
>> >> >
>> >> > public String getB(){ return b;}
>> >> > public void setB(String b){this.b = b;}
>> >> > }
>> >> > ------------------------------------------
>> >> >
>> >> > I´m using a web service that takes one parameter (String), this
>> >> parameter
>> >> > is
>> >> > the XML associated to the class A. My question is how I can using
>> >> xmlbeans
>> >> > conver one object A to a XML and then to String. I have no schema to
>> do
>> >> > this
>> >> > and I don´t know if is necessary.
>> >> >
>> >> > Thanks in advance.
>> >> >
>> >> > --
>> >> > View this message in context:
>> >> >
>> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>> >> > Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >> >
>> >> >
>> >> >
>> ---------------------------------------------------------------------
>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >> >
>> >> >
>> >> > This email and all content are subject to the following disclaimer:
>> >> >
>> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
>> >> >
>> >> >
>> >> >
>> >> >
>> ---------------------------------------------------------------------
>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >> >
>> >> >
>> >> >
>> >>
>> >> --
>> >> View this message in context:
>> http://www.nabble.com/xmlbeans-beginner---
>> >> help-tf4756991.html#a13608035
>> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >>
>> >>
>> >> ---------------------------------------------------------------------
>> >> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >
>> >
>> > Notice: This email message, together with any attachments, may contain
>> > information of BEA Systems, Inc., its subsidiaries and affiliated
>> > entities, that may be confidential, proprietary, copyrighted and/or
>> > legally privileged, and is intended solely for the use of the
>> individual
>> > or entity named in this message. If you are not the intended recipient,
>> > and have received this message in error, please immediately return this
>> by
>> > email and then delete it.
>> >
>> > ---------------------------------------------------------------------
>> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >
>> >
>> >
>>
>>--
>>View this message in context:
>>http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13608875
>>Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>
>>
>>---------------------------------------------------------------------
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RE: xmlbeans beginner - help
Posted by Albert Bupp <ab...@pipelinesoftware.com>.
Check out the XmlObject.Factory class in the java
docs. I've never used it, but it appears to have
several methods which return either XmlObject or
DomImplementation instances. It seems that you
then have to create an XMLInputStream instance to feed in your XML.
-Albert
At 10:40 AM 11/6/2007, you wrote:
>Yes I know but, can I convert a simple java class A to a XmlObject without
>schema ?
>
>Albert Bupp wrote:
> >
> > He means the XmlObject class which you'll find in the XmlBeans library.
> >
> > -Albert
> >
> > At 10:27 AM 11/6/2007, you wrote:
> >
> >>That sounds good but, I donôt have a XmlObject, I have a simple pojo
>(class
> >>A) and i want to convert it to XmlObject, my class A have to implements
> >>XmlObject ? How can I do this ??
> >>
> >>Cezar Andrei wrote:
> >> >
> >> > It is possible, but a little less forward that using schema. Just use
> >> > XmlObject, it handles all un-typed XML in XMLBeans.
> >> >
> >> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
> >> into
> >> > XmlObject.
> >> > And String xmlText = xo.xmlText() to get back to xml.
> >> >
> >> > To navigate/read/modify the XmlObject without a schema, you have to use
> >> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
> >> >
> >> > Cezar
> >> >
> >> >> -----Original Message-----
> >> >> From: imorales [mailto:imorales@ignos.com]
> >> >> Sent: Tuesday, November 06, 2007 8:50 AM
> >> >> To: user@xmlbeans.apache.org
> >> >> Subject: RE: xmlbeans beginner - help
> >> >>
> >> >>
> >> >> Is there any way to get from Java classes without XML schema and vice
> >> >> versa?
> >> >>
> >> >> Thanks.
> >> >>
> >> >> Schalk Neethling-4 wrote:
> >> >> >
> >> >> > You will more then likely have to start with a schema. So define
> >> your
> >> >> > schema and the from this generate your XMLBean which will give you
> >> >> object
> >> >> > A, you can then populate object A using the set methods that will be
> >> >> > generated and once you have the completed object you can invert it
> >> into
> >> >> a
> >> >> > XML string with one step by calling A.xmlText();
> >> >> >
> >> >> > HTH!
> >> >> >
> >> >> > Regards,
> >> >> > Schalk Neethling
> >> >> >
> >> >> > -----Original Message-----
> >> >> > From: imorales [mailto:imorales@ignos.com]
> >> >> > Sent: 06 November 2007 11:29 AM
> >> >> > To: user@xmlbeans.apache.org
> >> >> > Subject: xmlbeans beginner - help
> >> >> >
> >> >> >
> >> >> > Hi is my first time using xmlbeans and I hava a couple of question,
> >> I
> >> >> > explain
> >> >> > my scenario and I would like someone to resolve my ignorance about
> >> >> > xmlbeans.
> >> >> >
> >> >> > Well I hava a pojo class:
> >> >> >
> >> >> > ------------------------------------------
> >> >> > public class A{
> >> >> > private String b;
> >> >> >
> >> >> > public A(){}
> >> >> >
> >> >> > public String getB(){ return b;}
> >> >> > public void setB(String b){this.b = b;}
> >> >> > }
> >> >> > ------------------------------------------
> >> >> >
> >> >> > Iôm using a web service that takes one parameter (String), this
> >> >> parameter
> >> >> > is
> >> >> > the XML associated to the class A. My question is how I can using
> >> >> xmlbeans
> >> >> > conver one object A to a XML and then to String. I have no schema to
> >> do
> >> >> > this
> >> >> > and I donôt know if is necessary.
> >> >> >
> >> >> > Thanks in advance.
> >> >> >
> >> >> > --
> >> >> > View this message in context:
> >> >> >
> >> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
> >> >> > Sent from the Xml Beans - User mailing list archive at Nabble.com.
> >> >> >
> >> >> >
> >> >> >
> >> ---------------------------------------------------------------------
> >> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> >> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
> >> >> >
> >> >> >
> >> >> > This email and all content are subject to the following disclaimer:
> >> >> >
> >> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
> >> >> >
> >> >> >
> >> >> >
> >> >> >
> >> ---------------------------------------------------------------------
> >> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> >> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
> >> >> >
> >> >> >
> >> >> >
> >> >>
> >> >> --
> >> >> View this message in context:
> >> http://www.nabble.com/xmlbeans-beginner---
> >> >> help-tf4756991.html#a13608035
> >> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
> >> >>
> >> >>
> >> >> ---------------------------------------------------------------------
> >> >> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> >> >> For additional commands, e-mail: user-help@xmlbeans.apache.org
> >> >
> >> >
> >> > Notice: This email message, together with any attachments, may contain
> >> > information of BEA Systems, Inc., its subsidiaries and affiliated
> >> > entities, that may be confidential, proprietary, copyrighted and/or
> >> > legally privileged, and is intended solely for the use of the
> >> individual
> >> > or entity named in this message. If you are not the intended recipient,
> >> > and have received this message in error, please immediately return this
> >> by
> >> > email and then delete it.
> >> >
> >> > ---------------------------------------------------------------------
> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
> >> >
> >> >
> >> >
> >>
> >>--
> >>View this message in context:
> >>http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13608875
> >>Sent from the Xml Beans - User mailing list archive at Nabble.com.
> >>
> >>
> >>---------------------------------------------------------------------
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> >
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RE: xmlbeans beginner - help
Posted by imorales <im...@ignos.com>.
Yes I know but, can I convert a simple java class A to a XmlObject without
schema ?
Albert Bupp wrote:
>
> He means the XmlObject class which you'll find in the XmlBeans library.
>
> -Albert
>
> At 10:27 AM 11/6/2007, you wrote:
>
>>That sounds good but, I don´t have a XmlObject, I have a simple pojo
(class
>>A) and i want to convert it to XmlObject, my class A have to implements
>>XmlObject ? How can I do this ??
>>
>>Cezar Andrei wrote:
>> >
>> > It is possible, but a little less forward that using schema. Just use
>> > XmlObject, it handles all un-typed XML in XMLBeans.
>> >
>> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
>> into
>> > XmlObject.
>> > And String xmlText = xo.xmlText() to get back to xml.
>> >
>> > To navigate/read/modify the XmlObject without a schema, you have to use
>> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
>> >
>> > Cezar
>> >
>> >> -----Original Message-----
>> >> From: imorales [mailto:imorales@ignos.com]
>> >> Sent: Tuesday, November 06, 2007 8:50 AM
>> >> To: user@xmlbeans.apache.org
>> >> Subject: RE: xmlbeans beginner - help
>> >>
>> >>
>> >> Is there any way to get from Java classes without XML schema and vice
>> >> versa?
>> >>
>> >> Thanks.
>> >>
>> >> Schalk Neethling-4 wrote:
>> >> >
>> >> > You will more then likely have to start with a schema. So define
>> your
>> >> > schema and the from this generate your XMLBean which will give you
>> >> object
>> >> > A, you can then populate object A using the set methods that will be
>> >> > generated and once you have the completed object you can invert it
>> into
>> >> a
>> >> > XML string with one step by calling A.xmlText();
>> >> >
>> >> > HTH!
>> >> >
>> >> > Regards,
>> >> > Schalk Neethling
>> >> >
>> >> > -----Original Message-----
>> >> > From: imorales [mailto:imorales@ignos.com]
>> >> > Sent: 06 November 2007 11:29 AM
>> >> > To: user@xmlbeans.apache.org
>> >> > Subject: xmlbeans beginner - help
>> >> >
>> >> >
>> >> > Hi is my first time using xmlbeans and I hava a couple of question,
>> I
>> >> > explain
>> >> > my scenario and I would like someone to resolve my ignorance about
>> >> > xmlbeans.
>> >> >
>> >> > Well I hava a pojo class:
>> >> >
>> >> > ------------------------------------------
>> >> > public class A{
>> >> > private String b;
>> >> >
>> >> > public A(){}
>> >> >
>> >> > public String getB(){ return b;}
>> >> > public void setB(String b){this.b = b;}
>> >> > }
>> >> > ------------------------------------------
>> >> >
>> >> > I´m using a web service that takes one parameter (String), this
>> >> parameter
>> >> > is
>> >> > the XML associated to the class A. My question is how I can using
>> >> xmlbeans
>> >> > conver one object A to a XML and then to String. I have no schema to
>> do
>> >> > this
>> >> > and I don´t know if is necessary.
>> >> >
>> >> > Thanks in advance.
>> >> >
>> >> > --
>> >> > View this message in context:
>> >> >
>> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>> >> > Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >> >
>> >> >
>> >> >
>> ---------------------------------------------------------------------
>> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >> >
>> >> >
>> >> > This email and all content are subject to the following disclaimer:
>> >> >
>> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
>> >> >
>> >> >
>> >> >
>> >> >
>> ---------------------------------------------------------------------
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>> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >> >
>> >> >
>> >> >
>> >>
>> >> --
>> >> View this message in context:
>> http://www.nabble.com/xmlbeans-beginner---
>> >> help-tf4756991.html#a13608035
>> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >>
>> >>
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>> >
>> >
>> > Notice: This email message, together with any attachments, may contain
>> > information of BEA Systems, Inc., its subsidiaries and affiliated
>> > entities, that may be confidential, proprietary, copyrighted and/or
>> > legally privileged, and is intended solely for the use of the
>> individual
>> > or entity named in this message. If you are not the intended recipient,
>> > and have received this message in error, please immediately return this
>> by
>> > email and then delete it.
>> >
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RE: xmlbeans beginner - help
Posted by Albert Bupp <ab...@pipelinesoftware.com>.
He means the XmlObject class which you'll find in the XmlBeans library.
-Albert
At 10:27 AM 11/6/2007, you wrote:
>That sounds good but, I don´t have a XmlObject, I have a simple pojo (class
>A) and i want to convert it to XmlObject, my class A have to implements
>XmlObject ? How can I do this ??
>
>Cezar Andrei wrote:
> >
> > It is possible, but a little less forward that using schema. Just use
> > XmlObject, it handles all un-typed XML in XMLBeans.
> >
> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml into
> > XmlObject.
> > And String xmlText = xo.xmlText() to get back to xml.
> >
> > To navigate/read/modify the XmlObject without a schema, you have to use
> > either the cursor xo.newCursor() or the DOM xo.newDomNode().
> >
> > Cezar
> >
> >> -----Original Message-----
> >> From: imorales [mailto:imorales@ignos.com]
> >> Sent: Tuesday, November 06, 2007 8:50 AM
> >> To: user@xmlbeans.apache.org
> >> Subject: RE: xmlbeans beginner - help
> >>
> >>
> >> Is there any way to get from Java classes without XML schema and vice
> >> versa?
> >>
> >> Thanks.
> >>
> >> Schalk Neethling-4 wrote:
> >> >
> >> > You will more then likely have to start with a schema. So define your
> >> > schema and the from this generate your XMLBean which will give you
> >> object
> >> > A, you can then populate object A using the set methods that will be
> >> > generated and once you have the completed object you can invert it into
> >> a
> >> > XML string with one step by calling A.xmlText();
> >> >
> >> > HTH!
> >> >
> >> > Regards,
> >> > Schalk Neethling
> >> >
> >> > -----Original Message-----
> >> > From: imorales [mailto:imorales@ignos.com]
> >> > Sent: 06 November 2007 11:29 AM
> >> > To: user@xmlbeans.apache.org
> >> > Subject: xmlbeans beginner - help
> >> >
> >> >
> >> > Hi is my first time using xmlbeans and I hava a couple of question, I
> >> > explain
> >> > my scenario and I would like someone to resolve my ignorance about
> >> > xmlbeans.
> >> >
> >> > Well I hava a pojo class:
> >> >
> >> > ------------------------------------------
> >> > public class A{
> >> > private String b;
> >> >
> >> > public A(){}
> >> >
> >> > public String getB(){ return b;}
> >> > public void setB(String b){this.b = b;}
> >> > }
> >> > ------------------------------------------
> >> >
> >> > I´m using a web service that takes one parameter (String), this
> >> parameter
> >> > is
> >> > the XML associated to the class A. My question is how I can using
> >> xmlbeans
> >> > conver one object A to a XML and then to String. I have no schema to do
> >> > this
> >> > and I don´t know if is necessary.
> >> >
> >> > Thanks in advance.
> >> >
> >> > --
> >> > View this message in context:
> >> > http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
> >> > Sent from the Xml Beans - User mailing list archive at Nabble.com.
> >> >
> >> >
> >> > ---------------------------------------------------------------------
> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
> >> >
> >> >
> >> > This email and all content are subject to the following disclaimer:
> >> >
> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
> >> >
> >> >
> >> >
> >> > ---------------------------------------------------------------------
> >> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> >> > For additional commands, e-mail: user-help@xmlbeans.apache.org
> >> >
> >> >
> >> >
> >>
> >> --
> >> View this message in context: http://www.nabble.com/xmlbeans-beginner---
> >> help-tf4756991.html#a13608035
> >> Sent from the Xml Beans - User mailing list archive at Nabble.com.
> >>
> >>
> >> ---------------------------------------------------------------------
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> >> For additional commands, e-mail: user-help@xmlbeans.apache.org
> >
> >
> > Notice: This email message, together with any attachments, may contain
> > information of BEA Systems, Inc., its subsidiaries and affiliated
> > entities, that may be confidential, proprietary, copyrighted and/or
> > legally privileged, and is intended solely for the use of the individual
> > or entity named in this message. If you are not the intended recipient,
> > and have received this message in error, please immediately return this by
> > email and then delete it.
> >
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>--
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RE: xmlbeans beginner - help
Posted by imorales <im...@ignos.com>.
That sounds good but, I don´t have a XmlObject, I have a simple pojo (class
A) and i want to convert it to XmlObject, my class A have to implements
XmlObject ? How can I do this ??
Cezar Andrei wrote:
>
> It is possible, but a little less forward that using schema. Just use
> XmlObject, it handles all un-typed XML in XMLBeans.
>
> Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml into
> XmlObject.
> And String xmlText = xo.xmlText() to get back to xml.
>
> To navigate/read/modify the XmlObject without a schema, you have to use
> either the cursor xo.newCursor() or the DOM xo.newDomNode().
>
> Cezar
>
>> -----Original Message-----
>> From: imorales [mailto:imorales@ignos.com]
>> Sent: Tuesday, November 06, 2007 8:50 AM
>> To: user@xmlbeans.apache.org
>> Subject: RE: xmlbeans beginner - help
>>
>>
>> Is there any way to get from Java classes without XML schema and vice
>> versa?
>>
>> Thanks.
>>
>> Schalk Neethling-4 wrote:
>> >
>> > You will more then likely have to start with a schema. So define your
>> > schema and the from this generate your XMLBean which will give you
>> object
>> > A, you can then populate object A using the set methods that will be
>> > generated and once you have the completed object you can invert it into
>> a
>> > XML string with one step by calling A.xmlText();
>> >
>> > HTH!
>> >
>> > Regards,
>> > Schalk Neethling
>> >
>> > -----Original Message-----
>> > From: imorales [mailto:imorales@ignos.com]
>> > Sent: 06 November 2007 11:29 AM
>> > To: user@xmlbeans.apache.org
>> > Subject: xmlbeans beginner - help
>> >
>> >
>> > Hi is my first time using xmlbeans and I hava a couple of question, I
>> > explain
>> > my scenario and I would like someone to resolve my ignorance about
>> > xmlbeans.
>> >
>> > Well I hava a pojo class:
>> >
>> > ------------------------------------------
>> > public class A{
>> > private String b;
>> >
>> > public A(){}
>> >
>> > public String getB(){ return b;}
>> > public void setB(String b){this.b = b;}
>> > }
>> > ------------------------------------------
>> >
>> > I´m using a web service that takes one parameter (String), this
>> parameter
>> > is
>> > the XML associated to the class A. My question is how I can using
>> xmlbeans
>> > conver one object A to a XML and then to String. I have no schema to do
>> > this
>> > and I don´t know if is necessary.
>> >
>> > Thanks in advance.
>> >
>> > --
>> > View this message in context:
>> > http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>> > Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >
>> >
>> > ---------------------------------------------------------------------
>> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >
>> >
>> > This email and all content are subject to the following disclaimer:
>> >
>> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
>> >
>> >
>> >
>> > ---------------------------------------------------------------------
>> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> > For additional commands, e-mail: user-help@xmlbeans.apache.org
>> >
>> >
>> >
>>
>> --
>> View this message in context: http://www.nabble.com/xmlbeans-beginner---
>> help-tf4756991.html#a13608035
>> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>>
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
>> For additional commands, e-mail: user-help@xmlbeans.apache.org
>
>
> Notice: This email message, together with any attachments, may contain
> information of BEA Systems, Inc., its subsidiaries and affiliated
> entities, that may be confidential, proprietary, copyrighted and/or
> legally privileged, and is intended solely for the use of the individual
> or entity named in this message. If you are not the intended recipient,
> and have received this message in error, please immediately return this by
> email and then delete it.
>
> ---------------------------------------------------------------------
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RE: xmlbeans beginner - help
Posted by Cezar Andrei <ce...@bea.com>.
It is possible, but a little less forward that using schema. Just use XmlObject, it handles all un-typed XML in XMLBeans.
Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml into XmlObject.
And String xmlText = xo.xmlText() to get back to xml.
To navigate/read/modify the XmlObject without a schema, you have to use either the cursor xo.newCursor() or the DOM xo.newDomNode().
Cezar
> -----Original Message-----
> From: imorales [mailto:imorales@ignos.com]
> Sent: Tuesday, November 06, 2007 8:50 AM
> To: user@xmlbeans.apache.org
> Subject: RE: xmlbeans beginner - help
>
>
> Is there any way to get from Java classes without XML schema and vice
> versa?
>
> Thanks.
>
> Schalk Neethling-4 wrote:
> >
> > You will more then likely have to start with a schema. So define your
> > schema and the from this generate your XMLBean which will give you
> object
> > A, you can then populate object A using the set methods that will be
> > generated and once you have the completed object you can invert it into
> a
> > XML string with one step by calling A.xmlText();
> >
> > HTH!
> >
> > Regards,
> > Schalk Neethling
> >
> > -----Original Message-----
> > From: imorales [mailto:imorales@ignos.com]
> > Sent: 06 November 2007 11:29 AM
> > To: user@xmlbeans.apache.org
> > Subject: xmlbeans beginner - help
> >
> >
> > Hi is my first time using xmlbeans and I hava a couple of question, I
> > explain
> > my scenario and I would like someone to resolve my ignorance about
> > xmlbeans.
> >
> > Well I hava a pojo class:
> >
> > ------------------------------------------
> > public class A{
> > private String b;
> >
> > public A(){}
> >
> > public String getB(){ return b;}
> > public void setB(String b){this.b = b;}
> > }
> > ------------------------------------------
> >
> > I´m using a web service that takes one parameter (String), this
> parameter
> > is
> > the XML associated to the class A. My question is how I can using
> xmlbeans
> > conver one object A to a XML and then to String. I have no schema to do
> > this
> > and I don´t know if is necessary.
> >
> > Thanks in advance.
> >
> > --
> > View this message in context:
> > http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
> > Sent from the Xml Beans - User mailing list archive at Nabble.com.
> >
> >
> > ---------------------------------------------------------------------
> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> > For additional commands, e-mail: user-help@xmlbeans.apache.org
> >
> >
> > This email and all content are subject to the following disclaimer:
> >
> > http://content.momentum.co.za/content/legal/disclaimer_email.htm
> >
> >
> >
> > ---------------------------------------------------------------------
> > To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
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> >
> >
> >
>
> --
> View this message in context: http://www.nabble.com/xmlbeans-beginner---
> help-tf4756991.html#a13608035
> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>
>
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Notice: This email message, together with any attachments, may contain information of BEA Systems, Inc., its subsidiaries and affiliated entities, that may be confidential, proprietary, copyrighted and/or legally privileged, and is intended solely for the use of the individual or entity named in this message. If you are not the intended recipient, and have received this message in error, please immediately return this by email and then delete it.
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RE: xmlbeans beginner - help
Posted by imorales <im...@ignos.com>.
Is there any way to get from Java classes without XML schema and vice versa?
Thanks.
Schalk Neethling-4 wrote:
>
> You will more then likely have to start with a schema. So define your
> schema and the from this generate your XMLBean which will give you object
> A, you can then populate object A using the set methods that will be
> generated and once you have the completed object you can invert it into a
> XML string with one step by calling A.xmlText();
>
> HTH!
>
> Regards,
> Schalk Neethling
>
> -----Original Message-----
> From: imorales [mailto:imorales@ignos.com]
> Sent: 06 November 2007 11:29 AM
> To: user@xmlbeans.apache.org
> Subject: xmlbeans beginner - help
>
>
> Hi is my first time using xmlbeans and I hava a couple of question, I
> explain
> my scenario and I would like someone to resolve my ignorance about
> xmlbeans.
>
> Well I hava a pojo class:
>
> ------------------------------------------
> public class A{
> private String b;
>
> public A(){}
>
> public String getB(){ return b;}
> public void setB(String b){this.b = b;}
> }
> ------------------------------------------
>
> I´m using a web service that takes one parameter (String), this parameter
> is
> the XML associated to the class A. My question is how I can using xmlbeans
> conver one object A to a XML and then to String. I have no schema to do
> this
> and I don´t know if is necessary.
>
> Thanks in advance.
>
> --
> View this message in context:
> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
> Sent from the Xml Beans - User mailing list archive at Nabble.com.
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: user-unsubscribe@xmlbeans.apache.org
> For additional commands, e-mail: user-help@xmlbeans.apache.org
>
>
> This email and all content are subject to the following disclaimer:
>
> http://content.momentum.co.za/content/legal/disclaimer_email.htm
>
>
>
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RE: xmlbeans beginner - help
Posted by Schalk Neethling <Sc...@momentum.co.za>.
You will more then likely have to start with a schema. So define your schema and the from this generate your XMLBean which will give you object A, you can then populate object A using the set methods that will be generated and once you have the completed object you can invert it into a XML string with one step by calling A.xmlText();
HTH!
Regards,
Schalk Neethling
-----Original Message-----
From: imorales [mailto:imorales@ignos.com]
Sent: 06 November 2007 11:29 AM
To: user@xmlbeans.apache.org
Subject: xmlbeans beginner - help
Hi is my first time using xmlbeans and I hava a couple of question, I explain
my scenario and I would like someone to resolve my ignorance about xmlbeans.
Well I hava a pojo class:
------------------------------------------
public class A{
private String b;
public A(){}
public String getB(){ return b;}
public void setB(String b){this.b = b;}
}
------------------------------------------
I´m using a web service that takes one parameter (String), this parameter is
the XML associated to the class A. My question is how I can using xmlbeans
conver one object A to a XML and then to String. I have no schema to do this
and I don´t know if is necessary.
Thanks in advance.
--
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