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Posted to issues@ignite.apache.org by "Vladimir Ozerov (JIRA)" <ji...@apache.org> on 2018/04/18 13:20:00 UTC
[jira] [Updated] (IGNITE-7793) SQL does not work if value has index
filed which name equals to affinity key name
[ https://issues.apache.org/jira/browse/IGNITE-7793?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Vladimir Ozerov updated IGNITE-7793:
------------------------------------
Fix Version/s: (was: 2.5)
2.6
> SQL does not work if value has index filed which name equals to affinity key name
> ---------------------------------------------------------------------------------
>
> Key: IGNITE-7793
> URL: https://issues.apache.org/jira/browse/IGNITE-7793
> Project: Ignite
> Issue Type: Bug
> Components: sql
> Affects Versions: 2.3
> Reporter: Mikhail Cherkasov
> Priority: Blocker
> Fix For: 2.6
>
>
> SQL does not work if value has index filed which name equals to affinity key name:
> {code:java}
> public class AKey {
> @AffinityKeyMapped
> int a;
> public AKey(int a) {
> this.a = a;
> }
> }
> public class AVal {
> @QuerySqlField
> int a;
> public AVal(int a) {
> this.a = a;
> }
> }
> AKey aKey = new AKey(1);
> AVal aVal = new AVal(0);
> IgniteCache<Object, Object> cache = ignite.cache("Instrument");
> cache.put(aKey, aVal);
> SqlFieldsQuery query = new SqlFieldsQuery("select * from \"Instrument\".AVal it where it.a=?");
> List<List<?>> res = cache.query(query.setArgs(0)).getAll();
> if(res.isEmpty()) {
> System.out.println("!!!!!!!!! FAILED !!!!!!!!!!!");
> }
> {code}
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