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Posted to jira@arrow.apache.org by "Eduardo Ponce (Jira)" <ji...@apache.org> on 2022/04/02 00:49:00 UTC
[jira] [Comment Edited] (ARROW-13530) [C++] Implement cumulative sum compute function
[ https://issues.apache.org/jira/browse/ARROW-13530?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=17516180#comment-17516180 ]
Eduardo Ponce edited comment on ARROW-13530 at 4/2/22 12:48 AM:
----------------------------------------------------------------
Different cumsum implementations have different behaviors wrt to nested inputs.
# Which one should Arrow's cumsum follow?
# Should a ChunkedArray input output a ChunkedArray of same shape or output a flattened Array?
* *Pandas*
{code:python}
# Performs a "cumulative concatenate" operation for all nested lists
>>> d = pd.Series([[1,2],[3,4]])
>>> d.cumsum()
0 [1, 2]
1 [1, 2, 3, 4]
dtype: object
>>> d = pd.Series([[1,2,[3,4]],[[5,6],7],[8,9]])
>>> d.cumsum(axis=0)
0 [1, 2, [3, 4]]
1 [1, 2, [3, 4], [5, 6], 7]
2 [1, 2, [3, 4], [5, 6], 7, 8, 9]
dtype: object
{code}
* *Numpy*
{code:python}
# Case 1: If all of the array elements have the same nested depth, then it flattens the array and applies cumsum.
>>> d = np.array([[1,2],[3,4]])
>>> d.cumsum()
array([ 1, 3, 6, 10])
# Case 2: If array contains different nested depths, then cumsum represents a "cumulative concatenate" operation
>>> d = np.array([[1,2,[3,4]],[[5,6],7],[8,9]])
>>> d.cumsum()
array([list([1, 2, [3, 4]]), list([1, 2, [3, 4], [5, 6], 7]),
list([1, 2, [3, 4], [5, 6], 7, 8, 9])], dtype=object)
{code}
* *R*
#
{code:r}
# Flattens the nested list, then applies a cumsum
> cumsum(c(c(1,2),c(3,4)))
[1] 1 3 6 10
> cumsum(c(c(1,2,c(3,4)),c(c(5,6),7),c(8,9)))
[1] 1 3 6 10 15 21 28 36 45
{code}
was (Author: edponce):
Different cumsum implementations have different behaviors wrt to nested inputs. Which one should Arrow's cumsum follow?
* *Pandas*
{code:python}
# Performs a "cumulative concatenate" operation for all nested lists
>>> d = pd.Series([[1,2],[3,4]])
>>> d.cumsum()
0 [1, 2]
1 [1, 2, 3, 4]
dtype: object
>>> d = pd.Series([[1,2,[3,4]],[[5,6],7],[8,9]])
>>> d.cumsum(axis=0)
0 [1, 2, [3, 4]]
1 [1, 2, [3, 4], [5, 6], 7]
2 [1, 2, [3, 4], [5, 6], 7, 8, 9]
dtype: object
{code}
* *Numpy*
{code:python}
# Case 1: If all of the array elements have the same nested depth, then it flattens the array and applies cumsum.
>>> d = np.array([[1,2],[3,4]])
>>> d.cumsum()
array([ 1, 3, 6, 10])
# Case 2: If array contains different nested depths, then cumsum represents a "cumulative concatenate" operation
>>> d = np.array([[1,2,[3,4]],[[5,6],7],[8,9]])
>>> d.cumsum()
array([list([1, 2, [3, 4]]), list([1, 2, [3, 4], [5, 6], 7]),
list([1, 2, [3, 4], [5, 6], 7, 8, 9])], dtype=object)
{code}
* *R*
# {code:r}
# Flattens the nested list, then applies a cumsum
> cumsum(c(c(1,2),c(3,4)))
[1] 1 3 6 10
> cumsum(c(c(1,2,c(3,4)),c(c(5,6),7),c(8,9)))
[1] 1 3 6 10 15 21 28 36 45
{code}
> [C++] Implement cumulative sum compute function
> -----------------------------------------------
>
> Key: ARROW-13530
> URL: https://issues.apache.org/jira/browse/ARROW-13530
> Project: Apache Arrow
> Issue Type: Improvement
> Components: C++
> Reporter: Antoine Pitrou
> Assignee: Jabari Booker
> Priority: Major
> Labels: good-first-issue, good-second-issue, kernel, pull-request-available
> Fix For: 8.0.0
>
> Time Spent: 10h 40m
> Remaining Estimate: 0h
>
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