Re: Exception? Root element of SOAP message must be:? Confused... Help!

[Ian Snead <is...@ezgov.com>]

Scott Merritt wrote:
> 
> You don't by any chance know how to get Apache SOAP 2.2 to print the
> request?  I'm looking in the API docs now...

Interesting request; I had that thought myself, but
have not seen it done or seen an obvious method in
the API. Does Axis have this functionality?

Most folk seem to use a proxy to capture the contents
of a request / response.

Here are two that I have found useful :

http://www.pocketsoap.com/tcptrace/pt.asp
http://www.lanw.com/books/javasoap/default.htm

You will need the following code in your client to
direct an HTTP request to the proxy :

---
import org.apache.soap.transport.http.SOAPHTTPConnection;
    
SOAPHTTPConnection scxn = null; // transport object
          
if( debug )
{
     // proxy code
     scxn = new SOAPHTTPConnection();
     scxn.setProxyHost("localhost"); // proxy machine
     scxn.setProxyPort(proxyPort); // int
} // if

// Build the call.
Call call = new Call();
         
if( debug )
{
      call.setSOAPTransport(scxn); // HTTP
} // if
---

...sans the debug probably, and of course you 
still need the rest of what you are doing.

> 
> I do know that I'm doing a...
> 
> call.setEncodingStyleURI(Constants.NS_URI_SOAP_ENC);
> 

That call, as is, seems to set the encodingStyle
element to "http://schemas.xmlsoap.org/soap/encoding/"

Run the request through a proxy and you will see what
I mean. :)

Hope this helps!

> And they're expecting...
> 
> <?xml version="1.0" encoding="UTF-8" ?>
> <SOAP-ENV:Envelope
> xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
> xmlns:xsi="http://www.w3.org/1999/XMLSchema-instance"
> xmlns:xsd="http://www.w3.org/1999/XMLSchema">
> <SOAP-ENV:Body>
> <ns1:findProperties xmlns:ns1="urn:RealEstate"
> SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
>   <sell xsi:type="xsd:string">Sell</sell> ...
> 
> -----Original Message-----
> From: Ian Snead [mailto:isnead@ezgov.com]
> Sent: Tuesday, November 06, 2001 11:09 AM
> To: soap-user@xml.apache.org
> Subject: Re: Exception? Root element of SOAP message must be:?
> Confused... Help!
> 
> Hello Scott,
> 
> Which SOAP implementations are you using
> on the client and the server sides? Could you
> post the full text of the request you sent?
> 
> I'm not sure how, but it looks as if you have
> the element 'Client' in the first node of your
> SOAP XML document. The exception is telling you
> that, as defined in the namespace
> 
> Scott Merritt wrote:
> >
> > What does this exception mean?  I've used web services before but this one
> > popped up and I'm not sure where I'm going wrong.
> >
> > SOAPException= SOAP-ENV:Client, Root element of a SOAP message must be:
> > 'http://schemas.xmlsoap.org/soap/envelope/:Envelope'.
> >
> > Code snippet...
> >
> >      URL url = new URL(
> > "http://tamino.demozone.softwareag.com/demozone/realEstate/findProperties"
> > );
> >      String urn = "urn:RealEstate";
> >
> >      Call call = new Call(); // prepare the service invocation
> >      call.setTargetObjectURI( urn );
> >      call.setMethodName( "findProperties" );
> >      call.setEncodingStyleURI( Constants.NS_URI_SOAP_ENC );
> >      Vector params = new Vector();
> >      params.addElement( new Parameter( "sell", String.class, "Sell", null
> )
> > );
> >      params.addElement( new Parameter( "propertyType", String.class,
> > "House", null ) );
> >      params.addElement( new Parameter( "city", String.class, "Union City",
> > null ) );
> >      params.addElement( new Parameter( "lessPrice", String.class, "", null
> )
> > );
> >      call.setParams( params );
> >
> >      try
> >        {
> >        System.out.println( "invoke service\n" + "  URL= " + url + "\n  URN
> > =" +
> >           urn );
> >        Response response = call.invoke( url, "urn:RealEstate" ); // invoke
> > the service
> >
> > ...
> 
> --
> Ian Snead
> Software Developer
> EzGov
> Work : 404 836 7957
> 
> "Return a buffered reader to receive
>  back the response to whatever was sent to whatever."
> 
>  - from the Apache SOAP documentation

--
Ian Snead
Software Developer
EzGov
Work : 404 836 7957

"Return a buffered reader to receive 
 back the response to whatever was sent to whatever."
 
 - from the Apache SOAP documentation