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Posted to xmlrpc-dev@ws.apache.org by Jochen Wiedmann <jo...@gmail.com> on 2006/08/01 22:18:58 UTC
Re: Bug in xmlrpc-3.0b1
Stanislav Miklik wrote:
> Selected text seems to me like neverending cycle. I don't see the way out
> and also variable l is always l<=0.
You are right for the l<=0. Fixed.
As for the neverending cycle, I can't follow you:
for (int i = 1; ; i++) {
...
if (i == 10) {
throw e;
}
}
Jochen
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Re: Bug in xmlrpc-3.0b1
Posted by Jochen Wiedmann <jo...@gmail.com>.
On 8/2/06, Stanislav Miklik <st...@gmail.com> wrote:
> Current code is:
> } *catch* (BindException e) {
> * if* (i == 10) {
> * throw* e;
Throwing the exception here will leave the circle.
Jochen
--
My wife Mary and I have been married for forty-seven years and not
once have we had an argument serious enough to consider divorce;
murder, yes, but divorce, never.
(Jack Benny)
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Re: Bug in xmlrpc-3.0b1
Posted by Stanislav Miklik <st...@gmail.com>.
Current code is:
} *catch* (BindException e) {
* if* (i == 10) {
* throw* e;
} *else* {
* long* waitUntil = System.currentTimeMillis() + 1000;
* for* (;;) {
* long* l = waitUntil - System.currentTimeMillis();
* if* (l > 0) {
* try* {
Thread.sleep(l);
} *catch* (InterruptedException ex) {
}
}
Pls, can you describe me how will end this for(;;) cycle?
Shouldn't ne there something like
if(l>0){
//wait
} else break;
Bye
Stano
On 8/1/06, Jochen Wiedmann <jo...@gmail.com> wrote:
>
> Stanislav Miklik wrote:
>
> > Selected text seems to me like neverending cycle. I don't see the way
> out
> > and also variable l is always l<=0.
>
> You are right for the l<=0. Fixed.
>
> As for the neverending cycle, I can't follow you:
>
> for (int i = 1; ; i++) {
> ...
> if (i == 10) {
> throw e;
> }
> }
>
>
> Jochen
>
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> To unsubscribe, e-mail: xmlrpc-dev-unsubscribe@ws.apache.org
> For additional commands, e-mail: xmlrpc-dev-help@ws.apache.org
>
>