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Posted to issues@spark.apache.org by "Marco Gaido (JIRA)" <ji...@apache.org> on 2018/07/02 11:38:00 UTC

[jira] [Resolved] (SPARK-24712) TrainValidationSplit ignores label column name and forces to be "label"

     [ https://issues.apache.org/jira/browse/SPARK-24712?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Marco Gaido resolved SPARK-24712.
---------------------------------
    Resolution: Not A Problem

> TrainValidationSplit ignores label column name and forces to be "label"
> -----------------------------------------------------------------------
>
>                 Key: SPARK-24712
>                 URL: https://issues.apache.org/jira/browse/SPARK-24712
>             Project: Spark
>          Issue Type: Bug
>          Components: ML
>    Affects Versions: 2.2.0
>            Reporter: Pablo J. Villacorta
>            Priority: Major
>
> When a TrainValidationSplit is fit on a Pipeline containing a ML model, the labelCol property of the model is ignored, and the call to fit() will fail unless the labelCol equals "label". As an example, the following pyspark code only works when the variable labelColumnĀ is set to "label"
> {code:java}
> from pyspark.sql.functions import rand, randn
> from pyspark.ml.regression import LinearRegression
> labelColumn = "target"  # CHANGE THIS TO "label" AND THE CODE WORKS
> df = spark.range(0, 10).select(rand(seed=10).alias("uniform"), randn(seed=27).alias(labelColumn))
> vectorAssembler = VectorAssembler().setInputCols(["uniform"]).setOutputCol("features")
> lr = LinearRegression().setFeaturesCol("features").setLabelCol(labelColumn)
> mypipeline = Pipeline(stages = [vectorAssembler, lr])
> paramGrid = ParamGridBuilder()\
> .addGrid(lr.regParam, [0.01, 0.1])\
> .build()
> trainValidationSplit = TrainValidationSplit()\
> .setEstimator(mypipeline)\
> .setEvaluator(RegressionEvaluator())\
> .setEstimatorParamMaps(paramGrid)\
> .setTrainRatio(0.8)
> trainValidationSplit.fit(df)  # FAIL UNLESS labelColumn IS SET TO "label"
> {code}



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