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Posted to notifications@dubbo.apache.org by GitBox <gi...@apache.org> on 2022/11/22 07:40:36 UTC
[GitHub] [dubbo] mz0113 opened a new issue, #10987: ReferenceConfig在API编程时不可以每个方法单独一份config实例吗
mz0113 opened a new issue, #10987:
URL: https://github.com/apache/dubbo/issues/10987
`
//根据参数进行hash,各项参数一致的使用同一个referenceConfig 否则new一个新的config实例
ReferenceWrapper referenceWrapper = referenceConfigMap.computeIfAbsent(referenceModel, key -> new ReferenceWrapper(referenceModel, createReference(referenceModel)));
ReferenceConfig<GenericService> reference = new ReferenceConfig<>();
reference.setInterface(dubboInvokeParamModel.getServiceName());
reference.setGroup(dubboInvokeParamModel.getGroup());
reference.setVersion(dubboInvokeParamModel.getVersion());
reference.setRetries(0);
//例如这里,其他参数都一致，但是同一个method调用我可能因为需求不同而需要一会儿泛化，一会儿不泛化等情况。所以会new2个不同的referenceConfig实例
reference.setGeneric(dubboInvokeParamModel.getGson() ? CommonConstants.GENERIC_SERIALIZATION_GSON : CommonConstants.GENERIC_SERIALIZATION_DEFAULT);
reference.setAsync(dubboInvokeParamModel.getAsync());
reference.setCheck(false);
reference.setTimeout(dubboInvokeParamModel.getTimeoutMills());
`
如上 ，当interfaceName和group和version都一致 我会有不同超时时间，是否异步，不同泛化调用类型的需求。我希望能对于每一种调用维度维护不同的referenceConfig实例。
然后问题就出现啦：假如我现在interfaceName,group和version都一致。然后下面有2个method 。 method1对应的实例的timeout是3000，method2对应的referenceConfig实例的timeout=4000 ，然后呢我再new一个新的method2的referenceConfig实例，超时时间改成5000.
但其实测试下来并不能正常工作，超时检测报错出来显示timeout还是4000而不是修改后的5000.即便我很确定拿到的referenceConfig实例里面显示的timeout变量已经是5000了
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[GitHub] [dubbo] mz0113 closed issue #10987: ReferenceConfig在API编程时不可以每个方法单独一份config实例吗
Posted by GitBox <gi...@apache.org>.
mz0113 closed issue #10987: ReferenceConfig在API编程时不可以每个方法单独一份config实例吗
URL: https://github.com/apache/dubbo/issues/10987
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