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Posted to user@hivemind.apache.org by Ovidiu Hurducas <ov...@artsoft-consult.ro> on 2006/03/20 08:31:39 UTC
Accessing registry from a servlet without recreating a new instance
Greetings,
I’m using Hivemind+Tapestry+Hibernate to build a site. I have a
javax.servlet.Filter object where I need to do some operations with a
Hivemind service that uses Hibernate.
To access the registry from the filter I’m using the example from the
Hivemind documentation:
Registry registry = RegistryBuilder.constructDefaultRegistry();
MyService service = (MyService) registry.getService("com.mypackage.MyService", MyService.class);
However this is not good. The registry is recreated and the Hibernate
configuration is read again.
There is a way to access an existing registry that is already
initialized? I don’t want to recreate the registry twice.
Thank you,
Ovidiu
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Re: Accessing registry from a servlet without recreating a new instance
Posted by Norbert Sándor <de...@erinors.com>.
Override ApplicationServlet.constructRegistry() and store the registry
somewhere which is accessible from the filter, eg. the servletcontext.
@Override
protected Registry constructRegistry(ServletConfig config)
{
registry = super.constructRegistry(config);
config.getServletContext().setAttribute("SomeAttributeName",
registry);
return registry;
}
Regards,
Norbi
Ovidiu Hurducas wrote:
> Greetings,
>
> I’m using Hivemind+Tapestry+Hibernate to build a site. I have a
> javax.servlet.Filter object where I need to do some operations with a
> Hivemind service that uses Hibernate.
>
> To access the registry from the filter I’m using the example from the
> Hivemind documentation:
>
> Registry registry = RegistryBuilder.constructDefaultRegistry();
>
> MyService service = (MyService)
> registry.getService("com.mypackage.MyService", MyService.class);
>
>
>
> However this is not good. The registry is recreated and the Hibernate
> configuration is read again.
>
> There is a way to access an existing registry that is already
> initialized? I don’t want to recreate the registry twice.
>
> Thank you,
>
> Ovidiu
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: hivemind-user-unsubscribe@jakarta.apache.org
> For additional commands, e-mail: hivemind-user-help@jakarta.apache.org
>
>
>
>
>
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Re: Accessing registry from a servlet without recreating a new instance
Posted by Nick Faiz <ni...@q9software.com>.
The ApplicationServlet stores the created registry as an attribute in
the servlet context.
After it's initialized you can simply ask for it back and store it
wherever you want.
public void init(ServletConfig config) throws ServletException {
super.init(config);
String name = config.getServletName();
String registryKey = "org.apache.tapestry.Registry:" + name;
Registry registry = (Registry) config.getServletContext
().getAttribute(registryKey);
HiveAccess hiveAccess = HiveAccessor.getInstance();
hiveAccess.initialize(registry);
log.debug("Portal initialized.");
}
This works for Tapestry 4.0, at least. The HiveAccessor is a
convenience singleton which holds a reference to the registry for me.
Nick
On 20/03/2006, at 6:31 PM, Ovidiu Hurducas wrote:
> Greetings,
>
> I’m using Hivemind+Tapestry+Hibernate to build a site. I have a
> javax.servlet.Filter object where I need to do some operations with
> a Hivemind service that uses Hibernate.
>
> To access the registry from the filter I’m using the example from
> the Hivemind documentation:
>
> Registry registry = RegistryBuilder.constructDefaultRegistry();
>
> MyService service = (MyService) registry.getService
> ("com.mypackage.MyService", MyService.class);
>
>
> However this is not good. The registry is recreated and the
> Hibernate configuration is read again.
>
> There is a way to access an existing registry that is already
> initialized? I don’t want to recreate the registry twice.
>
> Thank you,
>
> Ovidiu
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: hivemind-user-unsubscribe@jakarta.apache.org
> For additional commands, e-mail: hivemind-user-help@jakarta.apache.org
>
Nick Faiz,
Developer
www.q9software.com
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