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Posted to dev@rocketmq.apache.org by ShannonDing <di...@apache.org> on 2019/07/01 02:05:56 UTC
[ANNOUNCE] New committer Kevin Wang
Hi Apache RocketMQ Community,
The Project Management Committee (PMC) for Apache RocketMQ has invited Kevin Wang(apache id: walking98) to become a committer and we are pleased to announce that he has accepted. Congrats, guy :-)
Notice: Being a committer enables easier contribution to the project since there is no need to go via the patch submission process. This should enable better productivity. and being a PMC member enables assistance with the management and to guide the direction of the project.
Best Wishes,
Shannon
Re: [ANNOUNCE] New committer Kevin Wang
Posted by heng du <du...@gmail.com>.
Congrats. @walking98
ShannonDing <di...@apache.org> 于2019年7月1日周一 上午10:06写道:
> Hi Apache RocketMQ Community,
>
> The Project Management Committee (PMC) for Apache RocketMQ has invited
> Kevin Wang(apache id: walking98) to become a committer and we are pleased
> to announce that he has accepted. Congrats, guy :-)
> Notice: Being a committer enables easier contribution to the project since
> there is no need to go via the patch submission process. This should enable
> better productivity. and being a PMC member enables assistance with the
> management and to guide the direction of the project.
>
> Best Wishes,
> Shannon
>
Re: [ANNOUNCE] New committer Kevin Wang
Posted by heng du <du...@gmail.com>.
Congrats. @walking98
ShannonDing <di...@apache.org> 于2019年7月1日周一 上午10:06写道:
> Hi Apache RocketMQ Community,
>
> The Project Management Committee (PMC) for Apache RocketMQ has invited
> Kevin Wang(apache id: walking98) to become a committer and we are pleased
> to announce that he has accepted. Congrats, guy :-)
> Notice: Being a committer enables easier contribution to the project since
> there is no need to go via the patch submission process. This should enable
> better productivity. and being a PMC member enables assistance with the
> management and to guide the direction of the project.
>
> Best Wishes,
> Shannon
>