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Posted to users@camel.apache.org by sekaijin <je...@sap.aphp.fr> on 2012/03/26 15:06:19 UTC
How to register a datasource, on configure() method or constructor
of a RoutBuilder ?
Hello,
I can not run camel-jdbc in java.
I defines a route with camel-blueprint, via a road builder (not in XML)
because I know the road to be built when bundle start.
when starting the bundle, I read a database that contains definitions of
endpoints. with there informations, I build the road. where in the database
I have a record defining an endpoint jdbc datasource I create a datasource
"myDataSourceName" and the uri "jdbc:myDataSourceName"
in the documentation I've read, I had to do
JndiRegistry reg = super.createRegistry();
reg.bind("testdb", db);
return reg;
but I'm in the configure method or in constructor of route builder
I can not call super.createRegistry(); the register already exists
I tried context.getRegistry (); who gets a JndiRegistry but getRegistry()
return a simple Registry.
The bind method does not exist on Registry.
I tried (JndiRegistry) context.getRegistry();
but I get a CastException.
public RouteBuilder()
super();
inUrl = getParameter("input.url");
//... read configuration datas
DataSourceName = "myDataSourceName";
DataSource DS = DataSourceFactory.create(DataSourceName, ....); //using
pooled datasource factory (c3p0)
JndiRegistry reg = (JndiRegistry) getContext().getRegistry();
//CastException
reg.bind("myDataSourceName", reg);//
//Or
Registry reg = getContext().getRegistry();
reg.bind("myDataSourceName", reg);//compil error bind is not method of
Registry
dsUri = "jdbc:" DataSourceName;
}
public void configure() {
RouteDefinition r = from(inUrl);
if ("sommeValue".equals(sommeParameter) {}
r.bean(MyBean.class);
//...
r.to("dsUri)
I have a similar problem in JUnit
CamelTestSupport created a camelContext and a Registry
then create the RouteBuilder (calls constructor)
and calls the configure() method
I've created an object datasource but inpossible to put it in the registry.
can you help me ?
A JYT
PS: Sorry for my approximative english
--
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Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by Christian Müller <ch...@gmail.com>.
It depends on your runtime environment, which Registry is used:
- org.apache.camel.spring.spi.ApplicationContextRegistry
- org.apache.camel.blueprint.BlueprintContainerRegistry
- org.apache.camel.impl.CompositeRegistry
- org.apache.camel.impl.JndiRegistry
- org.apache.camel.core.osgi.OsgiServiceRegistry
- org.apache.camel.impl.PropertyPlaceholderDelegateRegistry
- org.apache.camel.impl.SimpleRegistry
Best,
Christian
On Thu, May 17, 2012 at 3:56 PM, sekaijin <je...@sap.aphp.fr>wrote:
> the response is in my first post
>
>
> ==>CastException
>
> when you define your camel context Camel create a new Jndi resgisty or un
> osgi get de osgi jndiRegistry
>
> but when you call getContext().getRegistry(); camel do not return this
> registry but an registryProxy
> that not permit to get the real registry and not have bind method
>
> A+JYT
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-method-or-constructor-of-a-RoutBuilder-tp5595165p5711404.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
>
Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by sekaijin <je...@sap.aphp.fr>.
the response is in my first post
==>CastException
when you define your camel context Camel create a new Jndi resgisty or un
osgi get de osgi jndiRegistry
but when you call getContext().getRegistry(); camel do not return this
registry but an registryProxy
that not permit to get the real registry and not have bind method
A+JYT
--
View this message in context: http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-method-or-constructor-of-a-RoutBuilder-tp5595165p5711404.html
Sent from the Camel - Users mailing list archive at Nabble.com.
Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by Bilgin Ibryam <bi...@gmail.com>.
> if I did
> getContext().getRegistry();
> I can not use "bind" because it is not a method of Registry (but of
> JndiRegistry).
>
Why don't you do getContext().getRegistry() and then cast the Registry to
JndiRegistry
Then you can bind to the registry used I think
Bilgin
RE: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by sekaijin <je...@sap.aphp.fr>.
Hello,
My problem is I do not know the name of the datasource at design time.
I use blueprint to create an OSGi bundle which start a RouteBuilder
<camelContext id="hermes-journal" trace="false"
xmlns="http://camel.apache.org/schema/blueprint">
<package>fr.foo</package>
</camelContext>
when the routebuilder starts it queries a config database and reads the
name of the datasource to use.
if the datasource is already defined (by another bundle),
the routebuilder creates an endpoint "jdbc:" + datasSourceName.
otherwise it creates the datasource, register it on JNDI and creates the
endpoint.
the problem is to test this algorithm.
I can actually with camelTestSuport, before creating the route builder, add
a dataSource in the camel registry [1]. it allows me, to test the first case
(the datasource already exists)
but I can not test the second case that is to say: create the datasource
after starting the routebuilder and register it in the registry.
in this case before the creation of routebuilder, the datasource does not
exist, (I do not know his name).
the road builder starts, reads the configuration, Creates the dataSource and
saves it inJNDI
if I did
getContext().getRegistry();
I can not use "bind" because it is not a method of Registry (but of
JndiRegistry).
if I use
NamingContext InitialContext = new InitialContext();
I can register the datasource. but in JUnit, it creates another JndiRegistry
and does not use one created by CamelTestSupport
when creating the endpoint, the camel can not find datasource in its
registry.
This makes sense because InitialContext (); in JUnit, does not retrieved the
camel registry. but creates another.
While under OSGI InitialContext (); retrieves the registry JNDI and OSGI
camel uses it.
A + JYT
PS: Sorry for my approximative english
_____
De : Christian Mueller [via Camel]
[mailto:ml-node+s465427n5595849h55@n5.nabble.com]
Envoyé : lundi 26 mars 2012 18:59
À : sekaijin
Objet : Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
If you are talking about unit testing, simply override the
"createRegistry()" method as in [1].
If you are talking about the real application, simply define the datasource
in your spring xml and use the endpoint uri
"jdbc:<spring_bean_id_of_your_datasource_bean>". Look at [2] and [3] for an
example.
[1]
https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/
java/org/apache/camel/component/jdbc/AbstractJdbcTestSupport.java
[2]
https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/
java/org/apache/camel/component/jdbc/JdbcSpringAnotherRouteTest.java
[3]
https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/
resources/org/apache/camel/component/jdbc/camelContext.xml
Best,
Christian
On Mon, Mar 26, 2012 at 3:06 PM, sekaijin <[hidden email]>wrote:
> Hello,
> I can not run camel-jdbc in java.
>
> I defines a route with camel-blueprint, via a road builder (not in XML)
> because I know the road to be built when bundle start.
>
> when starting the bundle, I read a database that contains definitions of
> endpoints. with there informations, I build the road. where in the
database
> I have a record defining an endpoint jdbc datasource I create a datasource
> "myDataSourceName" and the uri "jdbc:myDataSourceName"
>
> in the documentation I've read, I had to do
> JndiRegistry reg = super.createRegistry();
> reg.bind("testdb", db);
> return reg;
>
> but I'm in the configure method or in constructor of route builder
> I can not call super.createRegistry(); the register already exists
> I tried context.getRegistry (); who gets a JndiRegistry but getRegistry()
> return a simple Registry.
> The bind method does not exist on Registry.
> I tried (JndiRegistry) context.getRegistry();
> but I get a CastException.
>
> public RouteBuilder()
> super();
> inUrl = getParameter("input.url");
> //... read configuration datas
> DataSourceName = "myDataSourceName";
>
> DataSource DS = DataSourceFactory.create(DataSourceName, ....); //using
> pooled datasource factory (c3p0)
>
> JndiRegistry reg = (JndiRegistry) getContext().getRegistry();
> //CastException
> reg.bind("myDataSourceName", reg);//
> //Or
> Registry reg = getContext().getRegistry();
> reg.bind("myDataSourceName", reg);//compil error bind is not method of
> Registry
>
> dsUri = "jdbc:" DataSourceName;
> }
>
> public void configure() {
> RouteDefinition r = from(inUrl);
> if ("sommeValue".equals(sommeParameter) {}
> r.bean(MyBean.class);
> //...
> r.to("dsUri)
>
>
>
> I have a similar problem in JUnit
> CamelTestSupport created a camelContext and a Registry
> then create the RouteBuilder (calls constructor)
> and calls the configure() method
>
> I've created an object datasource but inpossible to put it in the
registry.
>
> can you help me ?
> A JYT
> PS: Sorry for my approximative english
>
> --
> View this message in context:
>
http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-
method-or-constructor-of-a-RoutBuilder-tp5595165p5595165.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
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Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by Christian Müller <ch...@gmail.com>.
If you are talking about unit testing, simply override the
"createRegistry()" method as in [1].
If you are talking about the real application, simply define the datasource
in your spring xml and use the endpoint uri
"jdbc:<spring_bean_id_of_your_datasource_bean>". Look at [2] and [3] for an
example.
[1]
https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/java/org/apache/camel/component/jdbc/AbstractJdbcTestSupport.java
[2]
https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/java/org/apache/camel/component/jdbc/JdbcSpringAnotherRouteTest.java
[3]
https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/resources/org/apache/camel/component/jdbc/camelContext.xml
Best,
Christian
On Mon, Mar 26, 2012 at 3:06 PM, sekaijin <je...@sap.aphp.fr>wrote:
> Hello,
> I can not run camel-jdbc in java.
>
> I defines a route with camel-blueprint, via a road builder (not in XML)
> because I know the road to be built when bundle start.
>
> when starting the bundle, I read a database that contains definitions of
> endpoints. with there informations, I build the road. where in the database
> I have a record defining an endpoint jdbc datasource I create a datasource
> "myDataSourceName" and the uri "jdbc:myDataSourceName"
>
> in the documentation I've read, I had to do
> JndiRegistry reg = super.createRegistry();
> reg.bind("testdb", db);
> return reg;
>
> but I'm in the configure method or in constructor of route builder
> I can not call super.createRegistry(); the register already exists
> I tried context.getRegistry (); who gets a JndiRegistry but getRegistry()
> return a simple Registry.
> The bind method does not exist on Registry.
> I tried (JndiRegistry) context.getRegistry();
> but I get a CastException.
>
> public RouteBuilder()
> super();
> inUrl = getParameter("input.url");
> //... read configuration datas
> DataSourceName = "myDataSourceName";
>
> DataSource DS = DataSourceFactory.create(DataSourceName, ....); //using
> pooled datasource factory (c3p0)
>
> JndiRegistry reg = (JndiRegistry) getContext().getRegistry();
> //CastException
> reg.bind("myDataSourceName", reg);//
> //Or
> Registry reg = getContext().getRegistry();
> reg.bind("myDataSourceName", reg);//compil error bind is not method of
> Registry
>
> dsUri = "jdbc:" DataSourceName;
> }
>
> public void configure() {
> RouteDefinition r = from(inUrl);
> if ("sommeValue".equals(sommeParameter) {}
> r.bean(MyBean.class);
> //...
> r.to("dsUri)
>
>
>
> I have a similar problem in JUnit
> CamelTestSupport created a camelContext and a Registry
> then create the RouteBuilder (calls constructor)
> and calls the configure() method
>
> I've created an object datasource but inpossible to put it in the registry.
>
> can you help me ?
> A JYT
> PS: Sorry for my approximative english
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-method-or-constructor-of-a-RoutBuilder-tp5595165p5595165.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by Christian Müller <ch...@gmail.com>.
Could you solve your problem?
If not, feel free to raise a JIRA (and attach a test if possible) so we can
work on this.
Best,
Christian
On Fri, May 18, 2012 at 11:22 AM, sekaijin <je...@sap.aphp.fr>wrote:
> So
>
> Christian Mueller wrote
> >
> > It depends on your runtime environment, which Registry is used:
> > - org.apache.camel.spring.spi.ApplicationContextRegistry
> > - org.apache.camel.blueprint.BlueprintContainerRegistry
> > - org.apache.camel.impl.CompositeRegistry
> > - org.apache.camel.impl.JndiRegistry
> > - org.apache.camel.core.osgi.OsgiServiceRegistry
> > - org.apache.camel.impl.PropertyPlaceholderDelegateRegistry
> > - org.apache.camel.impl.SimpleRegistry
> >
> > Best,
> > Christian
> > ...
>
> In my first post
>
> "Hello,
> I can not run camel-jdbc in java.
>
> I defines a route with *camel-blueprint* via routebuilder in java""
>
> the problem is how i can get the registry in java to bind an objet
>
> blueprint automaticly creates the camel context and registry, and does not
> allow access in java.
>
> in route builder the camel context does not allow acces to the registry. it
> allow access to a proxy to the registry that does not allow to bind an
> object
>
> if I do as you said for junit,
> I do not have the expected behavior. namely
> when the bundle starts he has no knowledge of the database.
> It queries a service that provided the datasource to use
>
> A+JYT
>
>
>
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-method-or-constructor-of-a-RoutBuilder-tp5595165p5711798.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
>
Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by sekaijin <je...@sap.aphp.fr>.
So
Christian Mueller wrote
>
> It depends on your runtime environment, which Registry is used:
> - org.apache.camel.spring.spi.ApplicationContextRegistry
> - org.apache.camel.blueprint.BlueprintContainerRegistry
> - org.apache.camel.impl.CompositeRegistry
> - org.apache.camel.impl.JndiRegistry
> - org.apache.camel.core.osgi.OsgiServiceRegistry
> - org.apache.camel.impl.PropertyPlaceholderDelegateRegistry
> - org.apache.camel.impl.SimpleRegistry
>
> Best,
> Christian
> ...
In my first post
"Hello,
I can not run camel-jdbc in java.
I defines a route with *camel-blueprint* via routebuilder in java""
the problem is how i can get the registry in java to bind an objet
blueprint automaticly creates the camel context and registry, and does not
allow access in java.
in route builder the camel context does not allow acces to the registry. it
allow access to a proxy to the registry that does not allow to bind an
object
if I do as you said for junit,
I do not have the expected behavior. namely
when the bundle starts he has no knowledge of the database.
It queries a service that provided the datasource to use
A+JYT
--
View this message in context: http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-method-or-constructor-of-a-RoutBuilder-tp5595165p5711798.html
Sent from the Camel - Users mailing list archive at Nabble.com.
Re: How to register a datasource, on configure() method or
constructor of a RoutBuilder ?
Posted by Christian Müller <ch...@gmail.com>.
If you use CamelTestSupport, you are able to bind your objects to the
registry in this way:
@Override
protected JndiRegistry createRegistry() throws Exception {
JndiRegistry registry = super.createRegistry();
registry.bind("ds", ds);
return registry;
}
Best,
Christian
On Mon, Mar 26, 2012 at 3:06 PM, sekaijin <je...@sap.aphp.fr>wrote:
> Hello,
> I can not run camel-jdbc in java.
>
> I defines a route with camel-blueprint, via a road builder (not in XML)
> because I know the road to be built when bundle start.
>
> when starting the bundle, I read a database that contains definitions of
> endpoints. with there informations, I build the road. where in the database
> I have a record defining an endpoint jdbc datasource I create a datasource
> "myDataSourceName" and the uri "jdbc:myDataSourceName"
>
> in the documentation I've read, I had to do
> JndiRegistry reg = super.createRegistry();
> reg.bind("testdb", db);
> return reg;
>
> but I'm in the configure method or in constructor of route builder
> I can not call super.createRegistry(); the register already exists
> I tried context.getRegistry (); who gets a JndiRegistry but getRegistry()
> return a simple Registry.
> The bind method does not exist on Registry.
> I tried (JndiRegistry) context.getRegistry();
> but I get a CastException.
>
> public RouteBuilder()
> super();
> inUrl = getParameter("input.url");
> //... read configuration datas
> DataSourceName = "myDataSourceName";
>
> DataSource DS = DataSourceFactory.create(DataSourceName, ....); //using
> pooled datasource factory (c3p0)
>
> JndiRegistry reg = (JndiRegistry) getContext().getRegistry();
> //CastException
> reg.bind("myDataSourceName", reg);//
> //Or
> Registry reg = getContext().getRegistry();
> reg.bind("myDataSourceName", reg);//compil error bind is not method of
> Registry
>
> dsUri = "jdbc:" DataSourceName;
> }
>
> public void configure() {
> RouteDefinition r = from(inUrl);
> if ("sommeValue".equals(sommeParameter) {}
> r.bean(MyBean.class);
> //...
> r.to("dsUri)
>
>
>
> I have a similar problem in JUnit
> CamelTestSupport created a camelContext and a Registry
> then create the RouteBuilder (calls constructor)
> and calls the configure() method
>
> I've created an object datasource but inpossible to put it in the registry.
>
> can you help me ?
> A JYT
> PS: Sorry for my approximative english
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-method-or-constructor-of-a-RoutBuilder-tp5595165p5595165.html
> Sent from the Camel - Users mailing list archive at Nabble.com.