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Posted to users@cocoon.apache.org by jantje <ja...@skynet.be> on 2006/09/14 14:33:30 UTC
cocoon.exit();
Hi there,
I think the cocoon.exit() function is not working? how can I check this?
My code is:
function registration() {
var varContinue = true;
while(varContinue) {
var registrationForm = new
Form("cocoon:/formDefinition/registration.xml");
var rModel = registrationForm.getModel();
rModel.date = new java.util.Date();
registrationForm.showForm("registration/"
+ cocoon.request.get("identificaton")
+ "-"
+ cocoon.request.get("password")
+ "-"
+ "SB"
+ "-"
+ "SB"
+ "-"
+ "SB"
+ "-"
+ "SB"
+ "-"
+ "SB"
+ ".display");
if(registrationForm.submitId == "logout") {
cocoon.request.setAttribute("form1", registrationForm.getWidget());
//cocoon.sendPage("form1-success-pipeline.xsp");
cocoon.sendPage("registration-success");
varContinue = false;
cocoon.exit();
}
}
}/*
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Re: initial value
Posted by Jason Johnston <co...@lojjic.net>.
Roel Croonenberghs wrote:
>
> Hello,
>
> i have a widget fiels that I would like to have a initial value. I have
> this code in mine define.xml file;
>
> <wd:form xmlns:wd="http://apache.org/cocoon/woody/definition/1.0"
> xmlns:i18n="http://apache.org/cocoon/i18n/2.1">
>
> <wd:field id="from" required="true">
> <wd:initial-value>
> test@test.com
> </fd:initial-value>
> <wd:datatype base="string">
> <wd:validation />
> </wd:datatype>
> <wd:label>
> <i18n:text>extranet.create_ticket.from</i18n:text>
> </wd:label>
>
> </wd:field>
>
>
> the form works good, validation is ok, but there is no initial value set
> . The fiels is always blank.
> What am I doing wrong?
Hi Roel,
Based on your namespace definition it looks like you're still using the
(long-since-deprecated) "woody" block rather than the "forms" block. If
I remember correctly, the fd:initial-value element was added long after
woody was abandoned. If you want to use it, as well as many other new
features, you should upgrade and convert to the forms block. Check out
http://wiki.apache.org/cocoon/Woody2CocoonForms for help on converting.
--Jason
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initial value
Posted by Roel Croonenberghs <Ro...@sofico.be>.
Hello,
i have a widget fiels that I would like to have a initial value. I have
this code in mine define.xml file;
<wd:form xmlns:wd="http://apache.org/cocoon/woody/definition/1.0"
xmlns:i18n="http://apache.org/cocoon/i18n/2.1">
<wd:field id="from" required="true">
<wd:initial-value>
test@test.com
</fd:initial-value>
<wd:datatype base="string">
<wd:validation />
</wd:datatype>
<wd:label>
<i18n:text>extranet.create_ticket.from</i18n:text>
</wd:label>
</wd:field>
the form works good, validation is ok, but there is no initial value set .
The fiels is always blank.
What am I doing wrong?
vriendelijke groeten,
Roel Croonenberghs
Re: cocoon.exit();
Posted by Joerg Heinicke <jo...@gmx.de>.
On 18.09.2006 15:20, jantje wrote:
> But, i don't want users to go back after a "logout".. beceause there is
> still private information visible..
> So, beside invalidating the continuations.. is it possible to avoid people
> using the "go back" button?
This is nothing anybody could ever expect being handled by a server side
framework as the framework has no influence on the browser itself. So
also continuations won't allow you to handle this.
But there are some things you can do to work around the limitation:
1. The most ugly one is to delete the browsers history using JavaScript.
As this is not possible directly you have to do some ugly hacks. Besides
this it patronizes the users and is bad from an usability point of view.
2. You can provide the user a window without a navigation bar. This
solution won't work for "qualified" users as they might be able to get
the nav bar back with shortcuts. Furthermore I'd still feel patronized
and the same summary applies as for option 1. If you want to control
exactly what the user is allowed to do, you just must not develop a webapp.
3. The best solution to secure your webapp is to provide private data
only after a post request. On going backwards to such a page the user
will get presented a dialog asking for resending the form (due to post
request) - which won't work as he is no longer authenticated. I only
don't know if all old browsers behave that way as well or if it is
possible to retrieve the form result (maybe also in offline mode).
Regards,
Jörg
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Re: cocoon.exit();
Posted by jantje <ja...@skynet.be>.
OK, the solution is:
ON EVERY form.showForm(....);
var cont = form.showForm();
cont.invalidate
At this point, when you "go back" in your browser: you can see all the
prvious windows.. but in these windows you can not click on for instance a
submit button!!! so OK, all the continuations are invalidated!!!
But, i don't want users to go back after a "logout".. beceause there is
still private information visible..
So, beside invalidating the continuations.. is it possible to avoid people
using the "go back" button?
thanks and greetings..
Jason Johnston-3 wrote:
>
> The cocoon.exit() function only stops the current script execution, it
> does not affect any continuations that have already been created. To do
> that you need to invalidate those continuations.
>
> It looks like you're trying to implement a logout process... is there
> any reason why you can't just invalidate the whole session? If you've
> got your continuations manager (see cocoon.xconf) configured to attach
> continuations to the session, then they will automatically be
> invalidated along with the session.
>
> If for some reason you can't invalidate the session, then I think you
> need to crawl up the continuation's ancestry and invalidate the oldest,
> which will then automatically invalidate all the descendants. Something
> like:
>
> var kont = registrationForm.showForm(...
> ...
> var oldest = kont;
> while(oldest.getParent() != null) {
> oldest = oldest.getParent();
> }
> oldest.invalidate();
>
> Hope that's on the right track.
> --Jason
>
>
> jantje wrote:
>> Hey! thanks for searching and thinking with me.. but no, i can still use
>> the
>> "back" option in my browser :-(
>>
>> thanks!
>>
>>
>> Dev at weitling wrote:
>>> Hi Jan!
>>>
>>> After I stumbled through the wood not seeing the wood for the trees, it
>>> now may be I can help :-)
>>>
>>> Try using cocoon.exit() to exit the flow PLUS
>>> WebContinuation.invalidate().
>>>
>>> Reijn made me look here:
>>> http://cocoon.apache.org/2.1/userdocs/flow/api.html#cocoon
>>>
>>> Greetings,
>>> Florian
>>>
>>> jantje wrote:
>>>> I think it is not working beceause i can still use the "back" button in
>>>> my
>>>> browser!!!
>>>>
>>>> OK, maybe no new continuation is created.. BUT, with the "BACK" -
>>>> button
>>>> I
>>>> can still enter a previously created continuation..
>>>>
>>>> Maybe there is no function to really STOP the flow, in a cocoon
>>>> flowscript?
>>>>
>>>> Does someone know the answer?
>>>>
>>>> Greetings, Jan from Belgium
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>> Jeroen Reijn wrote:
>>>>
>>>>> Hi Jantje,
>>>>>
>>>>> why do you think the cocoon.exit function is not working? Does it not
>>>>> exit
>>>>> the flowscript without creating a continuation?
>>>>>
>>>>> Regards,
>>>>>
>>>>> Jeroen Reijn
>>>>>
>>>>> -----Original Message-----
>>>>> From: jantje [mailto:janvanoppen@skynet.be]
>>>>> Posted At: Thursday, September 14, 2006 2:34 PM
>>>>> Posted To: Cocoon User List
>>>>> Conversation: cocoon.exit();
>>>>> Subject: cocoon.exit();
>>>>>
>>>>>
>>>>>
>>>>> Hi there,
>>>>>
>>>>> I think the cocoon.exit() function is not working? how can I check
>>>>> this?
>>>>>
>>>>> My code is:
>>>>>
>>>>> function registration() {
>>>>> var varContinue = true;
>>>>> while(varContinue) {
>>>>> var registrationForm = new
>>>>> Form("cocoon:/formDefinition/registration.xml");
>>>>> var rModel = registrationForm.getModel();
>>>>> rModel.date = new java.util.Date();
>>>>> registrationForm.showForm("registration/"
>>>>> + cocoon.request.get("identificaton")
>>>>> + "-"
>>>>> + cocoon.request.get("password")
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + ".display");
>>>>> if(registrationForm.submitId == "logout") {
>>>>> cocoon.request.setAttribute("form1",
>>>>> registrationForm.getWidget());
>>>>> //cocoon.sendPage("form1-success-pipeline.xsp");
>>>>> cocoon.sendPage("registration-success");
>>>>> varContinue = false;
>>>>> cocoon.exit();
>>>>> }
>>>>> }
>>>>>
>>>>> }/*
>
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Re: cocoon.exit();
Posted by Jason Johnston <co...@lojjic.net>.
The cocoon.exit() function only stops the current script execution, it
does not affect any continuations that have already been created. To do
that you need to invalidate those continuations.
It looks like you're trying to implement a logout process... is there
any reason why you can't just invalidate the whole session? If you've
got your continuations manager (see cocoon.xconf) configured to attach
continuations to the session, then they will automatically be
invalidated along with the session.
If for some reason you can't invalidate the session, then I think you
need to crawl up the continuation's ancestry and invalidate the oldest,
which will then automatically invalidate all the descendants. Something
like:
var kont = registrationForm.showForm(...
...
var oldest = kont;
while(oldest.getParent() != null) {
oldest = oldest.getParent();
}
oldest.invalidate();
Hope that's on the right track.
--Jason
jantje wrote:
> Hey! thanks for searching and thinking with me.. but no, i can still use the
> "back" option in my browser :-(
>
> thanks!
>
>
> Dev at weitling wrote:
>> Hi Jan!
>>
>> After I stumbled through the wood not seeing the wood for the trees, it
>> now may be I can help :-)
>>
>> Try using cocoon.exit() to exit the flow PLUS
>> WebContinuation.invalidate().
>>
>> Reijn made me look here:
>> http://cocoon.apache.org/2.1/userdocs/flow/api.html#cocoon
>>
>> Greetings,
>> Florian
>>
>> jantje wrote:
>>> I think it is not working beceause i can still use the "back" button in
>>> my
>>> browser!!!
>>>
>>> OK, maybe no new continuation is created.. BUT, with the "BACK" - button
>>> I
>>> can still enter a previously created continuation..
>>>
>>> Maybe there is no function to really STOP the flow, in a cocoon
>>> flowscript?
>>>
>>> Does someone know the answer?
>>>
>>> Greetings, Jan from Belgium
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>> Jeroen Reijn wrote:
>>>
>>>> Hi Jantje,
>>>>
>>>> why do you think the cocoon.exit function is not working? Does it not
>>>> exit
>>>> the flowscript without creating a continuation?
>>>>
>>>> Regards,
>>>>
>>>> Jeroen Reijn
>>>>
>>>> -----Original Message-----
>>>> From: jantje [mailto:janvanoppen@skynet.be]
>>>> Posted At: Thursday, September 14, 2006 2:34 PM
>>>> Posted To: Cocoon User List
>>>> Conversation: cocoon.exit();
>>>> Subject: cocoon.exit();
>>>>
>>>>
>>>>
>>>> Hi there,
>>>>
>>>> I think the cocoon.exit() function is not working? how can I check this?
>>>>
>>>> My code is:
>>>>
>>>> function registration() {
>>>> var varContinue = true;
>>>> while(varContinue) {
>>>> var registrationForm = new
>>>> Form("cocoon:/formDefinition/registration.xml");
>>>> var rModel = registrationForm.getModel();
>>>> rModel.date = new java.util.Date();
>>>> registrationForm.showForm("registration/"
>>>> + cocoon.request.get("identificaton")
>>>> + "-"
>>>> + cocoon.request.get("password")
>>>> + "-"
>>>> + "SB"
>>>> + "-"
>>>> + "SB"
>>>> + "-"
>>>> + "SB"
>>>> + "-"
>>>> + "SB"
>>>> + "-"
>>>> + "SB"
>>>> + ".display");
>>>> if(registrationForm.submitId == "logout") {
>>>> cocoon.request.setAttribute("form1",
>>>> registrationForm.getWidget());
>>>> //cocoon.sendPage("form1-success-pipeline.xsp");
>>>> cocoon.sendPage("registration-success");
>>>> varContinue = false;
>>>> cocoon.exit();
>>>> }
>>>> }
>>>>
>>>> }/*
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Re: cocoon.exit();
Posted by jantje <ja...@skynet.be>.
Hey! thanks for searching and thinking with me.. but no, i can still use the
"back" option in my browser :-(
thanks!
Dev at weitling wrote:
>
> Hi Jan!
>
> After I stumbled through the wood not seeing the wood for the trees, it
> now may be I can help :-)
>
> Try using cocoon.exit() to exit the flow PLUS
> WebContinuation.invalidate().
>
> Reijn made me look here:
> http://cocoon.apache.org/2.1/userdocs/flow/api.html#cocoon
>
> Greetings,
> Florian
>
> jantje wrote:
>> I think it is not working beceause i can still use the "back" button in
>> my
>> browser!!!
>>
>> OK, maybe no new continuation is created.. BUT, with the "BACK" - button
>> I
>> can still enter a previously created continuation..
>>
>> Maybe there is no function to really STOP the flow, in a cocoon
>> flowscript?
>>
>> Does someone know the answer?
>>
>> Greetings, Jan from Belgium
>>
>>
>>
>>
>>
>>
>>
>>
>> Jeroen Reijn wrote:
>>
>>> Hi Jantje,
>>>
>>> why do you think the cocoon.exit function is not working? Does it not
>>> exit
>>> the flowscript without creating a continuation?
>>>
>>> Regards,
>>>
>>> Jeroen Reijn
>>>
>>> -----Original Message-----
>>> From: jantje [mailto:janvanoppen@skynet.be]
>>> Posted At: Thursday, September 14, 2006 2:34 PM
>>> Posted To: Cocoon User List
>>> Conversation: cocoon.exit();
>>> Subject: cocoon.exit();
>>>
>>>
>>>
>>> Hi there,
>>>
>>> I think the cocoon.exit() function is not working? how can I check this?
>>>
>>> My code is:
>>>
>>> function registration() {
>>> var varContinue = true;
>>> while(varContinue) {
>>> var registrationForm = new
>>> Form("cocoon:/formDefinition/registration.xml");
>>> var rModel = registrationForm.getModel();
>>> rModel.date = new java.util.Date();
>>> registrationForm.showForm("registration/"
>>> + cocoon.request.get("identificaton")
>>> + "-"
>>> + cocoon.request.get("password")
>>> + "-"
>>> + "SB"
>>> + "-"
>>> + "SB"
>>> + "-"
>>> + "SB"
>>> + "-"
>>> + "SB"
>>> + "-"
>>> + "SB"
>>> + ".display");
>>> if(registrationForm.submitId == "logout") {
>>> cocoon.request.setAttribute("form1",
>>> registrationForm.getWidget());
>>> //cocoon.sendPage("form1-success-pipeline.xsp");
>>> cocoon.sendPage("registration-success");
>>> varContinue = false;
>>> cocoon.exit();
>>> }
>>> }
>>>
>>> }/*
>>> --
>>> View this message in context:
>>> http://www.nabble.com/cocoon.exit%28%29--tf2271324.html#a6304867
>>> Sent from the Cocoon - Users forum at Nabble.com.
>>>
>>>
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>>>
>>>
>>> ---------------------------------------------------------------------
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>>>
>>>
>>>
>>
>>
>
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Re: cocoon.exit();
Posted by Dev at weitling <de...@weitling.net>.
Hi Jan!
After I stumbled through the wood not seeing the wood for the trees, it
now may be I can help :-)
Try using cocoon.exit() to exit the flow PLUS WebContinuation.invalidate().
Reijn made me look here:
http://cocoon.apache.org/2.1/userdocs/flow/api.html#cocoon
Greetings,
Florian
jantje wrote:
> I think it is not working beceause i can still use the "back" button in my
> browser!!!
>
> OK, maybe no new continuation is created.. BUT, with the "BACK" - button I
> can still enter a previously created continuation..
>
> Maybe there is no function to really STOP the flow, in a cocoon flowscript?
>
> Does someone know the answer?
>
> Greetings, Jan from Belgium
>
>
>
>
>
>
>
>
> Jeroen Reijn wrote:
>
>> Hi Jantje,
>>
>> why do you think the cocoon.exit function is not working? Does it not exit
>> the flowscript without creating a continuation?
>>
>> Regards,
>>
>> Jeroen Reijn
>>
>> -----Original Message-----
>> From: jantje [mailto:janvanoppen@skynet.be]
>> Posted At: Thursday, September 14, 2006 2:34 PM
>> Posted To: Cocoon User List
>> Conversation: cocoon.exit();
>> Subject: cocoon.exit();
>>
>>
>>
>> Hi there,
>>
>> I think the cocoon.exit() function is not working? how can I check this?
>>
>> My code is:
>>
>> function registration() {
>> var varContinue = true;
>> while(varContinue) {
>> var registrationForm = new
>> Form("cocoon:/formDefinition/registration.xml");
>> var rModel = registrationForm.getModel();
>> rModel.date = new java.util.Date();
>> registrationForm.showForm("registration/"
>> + cocoon.request.get("identificaton")
>> + "-"
>> + cocoon.request.get("password")
>> + "-"
>> + "SB"
>> + "-"
>> + "SB"
>> + "-"
>> + "SB"
>> + "-"
>> + "SB"
>> + "-"
>> + "SB"
>> + ".display");
>> if(registrationForm.submitId == "logout") {
>> cocoon.request.setAttribute("form1",
>> registrationForm.getWidget());
>> //cocoon.sendPage("form1-success-pipeline.xsp");
>> cocoon.sendPage("registration-success");
>> varContinue = false;
>> cocoon.exit();
>> }
>> }
>>
>> }/*
>> --
>> View this message in context:
>> http://www.nabble.com/cocoon.exit%28%29--tf2271324.html#a6304867
>> Sent from the Cocoon - Users forum at Nabble.com.
>>
>>
>> ---------------------------------------------------------------------
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>>
>>
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>> For additional commands, e-mail: users-help@cocoon.apache.org
>>
>>
>>
>
>
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RE: cocoon.exit();
Posted by jantje <ja...@skynet.be>.
I think it is not working beceause i can still use the "back" button in my
browser!!!
OK, maybe no new continuation is created.. BUT, with the "BACK" - button I
can still enter a previously created continuation..
Maybe there is no function to really STOP the flow, in a cocoon flowscript?
Does someone know the answer?
Greetings, Jan from Belgium
Jeroen Reijn wrote:
>
> Hi Jantje,
>
> why do you think the cocoon.exit function is not working? Does it not exit
> the flowscript without creating a continuation?
>
> Regards,
>
> Jeroen Reijn
>
> -----Original Message-----
> From: jantje [mailto:janvanoppen@skynet.be]
> Posted At: Thursday, September 14, 2006 2:34 PM
> Posted To: Cocoon User List
> Conversation: cocoon.exit();
> Subject: cocoon.exit();
>
>
>
> Hi there,
>
> I think the cocoon.exit() function is not working? how can I check this?
>
> My code is:
>
> function registration() {
> var varContinue = true;
> while(varContinue) {
> var registrationForm = new
> Form("cocoon:/formDefinition/registration.xml");
> var rModel = registrationForm.getModel();
> rModel.date = new java.util.Date();
> registrationForm.showForm("registration/"
> + cocoon.request.get("identificaton")
> + "-"
> + cocoon.request.get("password")
> + "-"
> + "SB"
> + "-"
> + "SB"
> + "-"
> + "SB"
> + "-"
> + "SB"
> + "-"
> + "SB"
> + ".display");
> if(registrationForm.submitId == "logout") {
> cocoon.request.setAttribute("form1",
> registrationForm.getWidget());
> //cocoon.sendPage("form1-success-pipeline.xsp");
> cocoon.sendPage("registration-success");
> varContinue = false;
> cocoon.exit();
> }
> }
>
> }/*
> --
> View this message in context:
> http://www.nabble.com/cocoon.exit%28%29--tf2271324.html#a6304867
> Sent from the Cocoon - Users forum at Nabble.com.
>
>
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Re: cocoon.exit();
Posted by jantje <ja...@skynet.be>.
Well, this is just cocoon.exit() from the cocoon documentation!
http://cocoon.apache.org
greetings
Dev at weitling wrote:
>
> Slightly off-topic: Where do you find all the descriptions of all those
> javascript functions?
>
> Bye,
> Florian
>
> Jeroen Reijn wrote:
>> Hi Jantje,
>>
>> why do you think the cocoon.exit function is not working? Does it not
>> exit the flowscript without creating a continuation?
>>
>
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