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Posted to users@tapestry.apache.org by Borut Bolčina <bo...@gmail.com> on 2009/04/23 15:12:48 UTC
Dispatcher returning XML
Hello,
I have a dispatcher which matches some URL pattern like this:
public boolean dispatch(Request request, Response response) throws
IOException {
String path = request.getPath();
// just imagine this works ok
String uglyWord = request.getContextPath() == "" ?
StringUtils.substringAfterLast(path, "/") : path.substring(1);
if (uglyWordSet.contains(uglyWord)) {
// return some XML if url contains some ugly word
// WHAT IS THE BEST APPROACH TO RETURN XML (STREAM) ?
return true;
}
return false;
}
I know how to create a page which returns xml stream response (I
actually have one). Can I just reuse this page?
Using T 5.0.18.
Regards,
Borut
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Re: Dispatcher returning XML
Posted by Howard Lewis Ship <hl...@gmail.com>.
A dispatcher is even easier; just think of it as a servlet that
returns true if it "handles the request". Get a response stream and
write XML to it.
On Thu, Apr 23, 2009 at 3:05 PM, Borut Bolčina <bo...@gmail.com> wrote:
> Thanks, but I am not sure how to do that in a dispatcher.
>
> -Borut
>
> 2009/4/23 Howard Lewis Ship <hl...@gmail.com>:
>> You can return a StreamResponse whose job is to generate an
>> InputStream of XML to be sent to the client.
>>
>> On Thu, Apr 23, 2009 at 6:12 AM, Borut Bolčina <bo...@gmail.com> wrote:
>>> Hello,
>>>
>>> I have a dispatcher which matches some URL pattern like this:
>>>
>>> public boolean dispatch(Request request, Response response) throws
>>> IOException {
>>> String path = request.getPath();
>>> // just imagine this works ok
>>> String uglyWord = request.getContextPath() == "" ?
>>> StringUtils.substringAfterLast(path, "/") : path.substring(1);
>>>
>>> if (uglyWordSet.contains(uglyWord)) {
>>> // return some XML if url contains some ugly word
>>> // WHAT IS THE BEST APPROACH TO RETURN XML (STREAM) ?
>>> return true;
>>> }
>>>
>>> return false;
>>> }
>>>
>>> I know how to create a page which returns xml stream response (I
>>> actually have one). Can I just reuse this page?
>>>
>>> Using T 5.0.18.
>>>
>>> Regards,
>>> Borut
>>>
>>> ---------------------------------------------------------------------
>>> To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
>>> For additional commands, e-mail: users-help@tapestry.apache.org
>>>
>>>
>>
>>
>>
>> --
>> Howard M. Lewis Ship
>>
>> Creator of Apache Tapestry
>> Director of Open Source Technology at Formos
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
>> For additional commands, e-mail: users-help@tapestry.apache.org
>>
>>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
> For additional commands, e-mail: users-help@tapestry.apache.org
>
>
--
Howard M. Lewis Ship
Creator of Apache Tapestry
Director of Open Source Technology at Formos
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Re: Dispatcher returning XML
Posted by Borut Bolčina <bo...@gmail.com>.
Thanks, but I am not sure how to do that in a dispatcher.
-Borut
2009/4/23 Howard Lewis Ship <hl...@gmail.com>:
> You can return a StreamResponse whose job is to generate an
> InputStream of XML to be sent to the client.
>
> On Thu, Apr 23, 2009 at 6:12 AM, Borut Bolčina <bo...@gmail.com> wrote:
>> Hello,
>>
>> I have a dispatcher which matches some URL pattern like this:
>>
>> public boolean dispatch(Request request, Response response) throws
>> IOException {
>> String path = request.getPath();
>> // just imagine this works ok
>> String uglyWord = request.getContextPath() == "" ?
>> StringUtils.substringAfterLast(path, "/") : path.substring(1);
>>
>> if (uglyWordSet.contains(uglyWord)) {
>> // return some XML if url contains some ugly word
>> // WHAT IS THE BEST APPROACH TO RETURN XML (STREAM) ?
>> return true;
>> }
>>
>> return false;
>> }
>>
>> I know how to create a page which returns xml stream response (I
>> actually have one). Can I just reuse this page?
>>
>> Using T 5.0.18.
>>
>> Regards,
>> Borut
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
>> For additional commands, e-mail: users-help@tapestry.apache.org
>>
>>
>
>
>
> --
> Howard M. Lewis Ship
>
> Creator of Apache Tapestry
> Director of Open Source Technology at Formos
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
> For additional commands, e-mail: users-help@tapestry.apache.org
>
>
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
For additional commands, e-mail: users-help@tapestry.apache.org
Re: Dispatcher returning XML
Posted by Howard Lewis Ship <hl...@gmail.com>.
You can return a StreamResponse whose job is to generate an
InputStream of XML to be sent to the client.
On Thu, Apr 23, 2009 at 6:12 AM, Borut Bolčina <bo...@gmail.com> wrote:
> Hello,
>
> I have a dispatcher which matches some URL pattern like this:
>
> public boolean dispatch(Request request, Response response) throws
> IOException {
> String path = request.getPath();
> // just imagine this works ok
> String uglyWord = request.getContextPath() == "" ?
> StringUtils.substringAfterLast(path, "/") : path.substring(1);
>
> if (uglyWordSet.contains(uglyWord)) {
> // return some XML if url contains some ugly word
> // WHAT IS THE BEST APPROACH TO RETURN XML (STREAM) ?
> return true;
> }
>
> return false;
> }
>
> I know how to create a page which returns xml stream response (I
> actually have one). Can I just reuse this page?
>
> Using T 5.0.18.
>
> Regards,
> Borut
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
> For additional commands, e-mail: users-help@tapestry.apache.org
>
>
--
Howard M. Lewis Ship
Creator of Apache Tapestry
Director of Open Source Technology at Formos
---------------------------------------------------------------------
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