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Posted to issues@spark.apache.org by "Shawn Lavelle (JIRA)" <ji...@apache.org> on 2017/06/26 14:55:00 UTC

[jira] [Created] (SPARK-21212) Can't use Count(*) with Order Clause

Shawn Lavelle created SPARK-21212:
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             Summary: Can't use Count(*) with Order Clause
                 Key: SPARK-21212
                 URL: https://issues.apache.org/jira/browse/SPARK-21212
             Project: Spark
          Issue Type: Bug
          Components: SQL
    Affects Versions: 2.1.0
         Environment: Windows; external data provided through data source api
            Reporter: Shawn Lavelle
            Priority: Minor


I don't think this should fail the query:

{code}jdbc:hive2://user:port/> select count(*) from table where value between 1498240079000 and cast(now() as bigint)*1000 order by value;
{code}


{code}
Error: org.apache.spark.sql.AnalysisException: cannot resolve '`value`' given input columns: [count(1)]; line 1 pos 113;
'Sort ['value ASC NULLS FIRST], true
+- Aggregate [count(1) AS count(1)#718L]
   +- Filter ((value#413L >= 1498240079000) && (value#413L <= (cast(current_timestamp() as bigint) * cast(1000 as bigint))))
      +- SubqueryAlias table
         +- Relation[field1#411L,field2#412,value#413L,field3#414,field4#415,field5#416,field6#417,field7#418,field8#419,field9#420] com.redacted@16004579 (state=,code=0)
{code}

Arguably, the optimizer could ignore the "order by" clause, but I leave that to more informed minds than my own.




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