You are viewing a plain text version of this content. The canonical link for it is here.
Posted to dev@cayenne.apache.org by "Andrus Adamchik (JIRA)" <de...@cayenne.apache.org> on 2008/06/09 10:55:52 UTC
[jira] Created: (CAY-1069) EJBQL: support paths across flattened
relationships
EJBQL: support paths across flattened relationships
---------------------------------------------------
Key: CAY-1069
URL: https://issues.apache.org/cayenne/browse/CAY-1069
Project: Cayenne
Issue Type: Task
Components: Cayenne Core Library
Affects Versions: 3.0
Reporter: Andrus Adamchik
Assignee: Andrus Adamchik
Fix For: 3.0
Flattened relationships are not parsed properly by EJBQL yet. E.g.:
String ejbql = "SELECT f FROM FlattenedTest3 f, FlattenedTest1 ft "
+ "WHERE f MEMBER OF ft.ft3Array AND ft = :ft";
SELECT t0.FT2_ID AS ec0_0, t0.NAME AS ec0_1, t0.FT3_ID AS ec0_2
FROM FLATTENED_TEST_3 t0, FLATTENED_TEST_1 t1
WHERE EXISTS (SELECT 1 FROM FLATTENED_TEST_3 t2 WHERE t2.FT1_ID = t1.FT1_ID AND t2.FT3_ID = t0.FT3_ID) AND t1.FT1_ID = ? [bind: 1:1]
java.sql.SQLException: Column not found: T2.FT1_ID in statement [SELECT t0.FT2_ID AS ec0_0, t0.NAME AS ec0_1, t0.FT3_ID AS ec0_2 FROM FLATTENED_TEST_3 t0, FLATTENED_TEST_1 t1 WHERE EXISTS (SELECT 1 FROM FLATTENED_TEST_3 t2 WHERE t2.FT1_ID = t1.FT1_ID AND t2.FT3_ID = t0.FT3_ID) AND t1.FT1_ID = ?]
--
This message is automatically generated by JIRA.
-
You can reply to this email to add a comment to the issue online.