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Posted to dev@tomcat.apache.org by bu...@apache.org on 2008/07/17 17:02:54 UTC
DO NOT REPLY [Bug 45419] Return Accept-Ranges from DefaultServlet
https://issues.apache.org/bugzilla/show_bug.cgi?id=45419
--- Comment #1 from Will Rowe <wr...@apache.org> 2008-07-17 08:02:53 PST ---
We might have lost sight of the issue here; this issue is not whether or not
it's possible to encode utf-16-le, it's that the URI was not encoded in that
character set.
As I pointed out above, in the similar -be encoding, we need 16 bits to
transmit
each character, This particular browser sent 8 bit octets. That is not
utf-16.
Two escaped characters does not constitute a utf-16 request, it's a utf-16
fragment within an ASCII/ISO-8859/UTF-8/whatever bytestream. I would recommend
no change whatsoever in Tomcat's code on this issue.
As far as working around it, it might be nice if one could deploy a Valve that
was triggered based on User-Agent, that would probably be the most elegant hack
for this browser flaw.
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