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Posted to dev@lucene.apache.org by "Karl von Randow (JIRA)" <ji...@apache.org> on 2016/10/27 05:14:58 UTC
[jira] [Created] (LUCENE-7525) ASCIIFoldingFilter.foldToASCII
performance issue due to large compiled method size
Karl von Randow created LUCENE-7525:
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Summary: ASCIIFoldingFilter.foldToASCII performance issue due to large compiled method size
Key: LUCENE-7525
URL: https://issues.apache.org/jira/browse/LUCENE-7525
Project: Lucene - Core
Issue Type: Improvement
Components: modules/analysis
Affects Versions: 6.2.1
Reporter: Karl von Randow
The {{ASCIIFoldingFilter.foldToASCII}} method has an enormous switch statement and is too large for the HotSpot compiler to compile; causing a performance problem.
The method is about 13K compiled, versus the 8KB HotSpot limit. So splitting the method in half works around the problem.
In my tests splitting the method in half resulted in a 5X performance increase.
In the test code below you can see how slow the fold method is, even when it is using the shortcut when the character is less than 0x80, compared to an inline implementation of the same shortcut.
So a workaround is to split the method. I'm happy to provide a patch. It's a hack, of course. Perhaps using the {{MappingCharFilterFactory}} with an input file as per SOLR-2013 would be a better replacement for this method in this class?
{code:java}
public class ASCIIFoldingFilterPerformanceTest {
private static final int ITERATIONS = 1_000_000;
@Test
public void testFoldShortString() {
char[] input = "testing".toCharArray();
char[] output = new char[input.length * 4];
for (int i = 0; i < ITERATIONS; i++) {
ASCIIFoldingFilter.foldToASCII(input, 0, output, 0, input.length);
}
}
@Test
public void testFoldShortAccentedString() {
char[] input = "éúéúøßüäéúéúøßüä".toCharArray();
char[] output = new char[input.length * 4];
for (int i = 0; i < ITERATIONS; i++) {
ASCIIFoldingFilter.foldToASCII(input, 0, output, 0, input.length);
}
}
@Test
public void testManualFoldTinyString() {
char[] input = "t".toCharArray();
char[] output = new char[input.length * 4];
for (int i = 0; i < ITERATIONS; i++) {
int k = 0;
for (int j = 0; j < 1; ++j) {
final char c = input[j];
if (c < '\u0080') {
output[k++] = c;
} else {
Assert.assertTrue(false);
}
}
}
}
}
{code}
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