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Posted to dev@flex.apache.org by Pawan Yadav <pa...@gmail.com> on 2015/03/05 07:47:41 UTC
mx tree itemrenderer
Hi - How can we reload mx tree itemrenderer.
When I am trying tree.invalidateProperties() or
tree.invalidateDisplayList(), it is not calling tree itemrenderer. But with
tree.refresh I am getting call inside itemrenderer.
So is there any way to reload itemrenderer without refreshing tree. Or can
I just update display fo single node in tree.
Best Regards
Pawan
Re: mx tree itemrenderer
Posted by Pawan Yadav <pa...@gmail.com>.
Thanks, It worked!
Best Regards
Pawan
On Thu, Mar 5, 2015 at 2:09 PM, Deepak MS <me...@gmail.com> wrote:
> You can try to re assign the itemrenderer itself:
> var cf:ClassFactory = new ClassFactory(YourTreeRenderer);
> cf.properties = {property1:"somevalue",
> property2:"somevalueagain"};
> yourTree.itemRenderer = cf;
>
> On Thu, Mar 5, 2015 at 12:17 PM, Pawan Yadav <pa...@gmail.com>
> wrote:
>
> > Hi - How can we reload mx tree itemrenderer.
> >
> > When I am trying tree.invalidateProperties() or
> > tree.invalidateDisplayList(), it is not calling tree itemrenderer. But
> with
> > tree.refresh I am getting call inside itemrenderer.
> >
> >
> > So is there any way to reload itemrenderer without refreshing tree. Or
> can
> > I just update display fo single node in tree.
> >
> >
> >
> > Best Regards
> > Pawan
> >
>
Re: mx tree itemrenderer
Posted by Deepak MS <me...@gmail.com>.
You can try to re assign the itemrenderer itself:
var cf:ClassFactory = new ClassFactory(YourTreeRenderer);
cf.properties = {property1:"somevalue",
property2:"somevalueagain"};
yourTree.itemRenderer = cf;
On Thu, Mar 5, 2015 at 12:17 PM, Pawan Yadav <pa...@gmail.com> wrote:
> Hi - How can we reload mx tree itemrenderer.
>
> When I am trying tree.invalidateProperties() or
> tree.invalidateDisplayList(), it is not calling tree itemrenderer. But with
> tree.refresh I am getting call inside itemrenderer.
>
>
> So is there any way to reload itemrenderer without refreshing tree. Or can
> I just update display fo single node in tree.
>
>
>
> Best Regards
> Pawan
>