laxly schema valid

[tr...@katamail.com]

HI ALL,
 I think I understand what lax  means in the w3c schema spec, i' am able to
 strict schema validate, but I'm not sure which features i need to laxly 
 validate
 an element . I set ( in a DOMParser)
 parser.setFeature("http://xml.org/sax/features/namespaces",true);
 parser.setFeature("http://xml.org/sax/features/validation",true);
 parser.setFeature("http://apache.org/xml/features/validation/dynamic",true);
 parser.setFeature("http://apache.org/xml/features/validation/schema",true);
 parser.setFeature("http://apache.org/xml/features/validation/schema-full-checking",true);

 // it dosen't seem to work for xerces 1.4.x nor 2.0.x
 parser.setFeature("http://apache.org/xml/features/validation/warn-on-undeclared-elemdef",true);
 // it "throws" an error always not a warning

 parser.setProperty("http://apache.org/xml/properties/schema/external-schemaLocation",
 "http://www.w3.org/2000/09/xmldsig# xmldsig-core-schema.xsd" );

 When a parse a file with a not shema-defined element a take a wonderful
 SAXPARSException, by the way how to bind this exception with the element ? Or
 more general, I'm not sure if I have to write the app that check the element 
 or if this task is perfomed by the parser simply setting some features that I miss ?

 Thanks in advance ! - Bob Trasverso

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