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Posted to java-user@axis.apache.org by Praveen Kumar <pd...@gmail.com> on 2007/06/12 14:50:25 UTC
Need deply new web service in tomcat server.
Hi All,
I need to talk with other web application from my my application
They have given one hyperlink saying http///xxxx.com/hhhh/axis
and webservice name getMethodname and asked me to send XML string.
So i started working on this.First i deployed axis(1.4) dir to my
webapps/dir and started working on samples. means the /axis/XXXX at IE.
and i have read the documentation at axis web site.
pls help me how to code this one !!
Thanks
Praveen.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.
RE: Transport out has not been set
Posted by "Kang, Kamaljeet K." <Ka...@tellabs.com>.
I checked again, I have all the jar files from ActiveMQ and Axis2 in my
classpath.
Thanks
Kamal
-----Original Message-----
From: Deepal Jayasinghe [mailto:deepal@opensource.lk]
Sent: Wednesday, June 13, 2007 2:05 PM
To: axis-user@ws.apache.org
Subject: Re: Transport out has not been set
May be you have not added dependent jars which JMS required to the
classpath.
Thanks
Deepal
Kang, Kamaljeet K. wrote:
>
> Hi,
>
>
>
> I am trying to test axis2 with JMS transport. I followed the
> instructions as per 'jms-transport.html'. The server initializes fine
> and I see the JMS queue gets created on the JMS broker but when I try
> to call a method on stub I get the following exception.
>
>
>
> org.apache.axis2.AxisFault: Transport out has not been set
>
> at
> org.apache.axis2.engine.AxisEngine.send(AxisEngine.java:507)
>
> at
>
org.apache.axis2.description.OutInAxisOperationClient.send(OutInAxisOper
ation.java:309)
>
> at
>
org.apache.axis2.description.OutInAxisOperationClient.execute(OutInAxisO
peration.java:273)
>
> at org.hello.HelloStub.Hello(HelloStub.java:173)
>
> at org.hello.HelloStub.main(HelloStub.java:462)
>
>
>
> String url =
>
"jms:/Hello?transport.jms.ConnectionFactoryJNDIName=QueueConnectionFacto
ry&java.naming.factory.initial=org.apache.activemq.jndi.ActiveMQInitialC
ontextFactory&java.naming.provider.url=tcp://localhost:61616";
>
>
> HelloStub hStub = new HelloStub(url);
>
> HelloResponse hRes = hStub.Hello("Test");
>
> System.out.println("Response is " +
> hRes.getStringout());
>
>
>
> Can someone please help me with this?
>
>
>
>
>
> Thanks
>
>
>
> Kamal
>
> ============================================================
> The information contained in this message may be privileged
> and confidential and protected from disclosure. If the reader
> of this message is not the intended recipient, or an employee
> or agent responsible for delivering this message to the
> intended recipient, you are hereby notified that any reproduction,
> dissemination or distribution of this communication is strictly
> prohibited. If you have received this communication in error,
> please notify us immediately by replying to the message and
> deleting it from your computer. Thank you. Tellabs
> ============================================================
>
--
Thanks,
Deepal
................................................................
"The highest tower is built one brick at a time"
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============================================================
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and confidential and protected from disclosure. If the reader
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or agent responsible for delivering this message to the
intended recipient, you are hereby notified that any reproduction,
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prohibited. If you have received this communication in error,
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Re: Transport out has not been set
Posted by Martin Gainty <mg...@hotmail.com>.
Also you will want to check transport attribute in your for wsdl <binding
transport=
to quote the doc:
The value of the required transport attribute indicates which transport of
SOAP this binding corresponds to. The URI value
"http://schemas.xmlsoap.org/soap/http " corresponds to the HTTP binding in
the SOAP specification. Other URIs may be used here to indicate other
transports (such as SMTP, FTP, etc.).
HTH
Martin--
This email message and any files transmitted with it contain confidential
information intended only for the person(s) to whom this email message is
addressed. If you have received this email message in error, please notify
the sender immediately by telephone or email and destroy the original
message without making a copy. Thank you.
----- Original Message -----
From: "Deepal Jayasinghe" <de...@opensource.lk>
To: <ax...@ws.apache.org>
Sent: Wednesday, June 13, 2007 2:05 PM
Subject: Re: Transport out has not been set
> May be you have not added dependent jars which JMS required to the
> classpath.
>
> Thanks
> Deepal
>
> Kang, Kamaljeet K. wrote:
>>
>> Hi,
>>
>>
>>
>> I am trying to test axis2 with JMS transport. I followed the
>> instructions as per ‘jms-transport.html’. The server initializes fine
>> and I see the JMS queue gets created on the JMS broker but when I try
>> to call a method on stub I get the following exception.
>>
>>
>>
>> org.apache.axis2.AxisFault: Transport out has not been set
>>
>> at
>> org.apache.axis2.engine.AxisEngine.send(AxisEngine.java:507)
>>
>> at
>> org.apache.axis2.description.OutInAxisOperationClient.send(OutInAxisOperation.java:309)
>>
>> at
>> org.apache.axis2.description.OutInAxisOperationClient.execute(OutInAxisOperation.java:273)
>>
>> at org.hello.HelloStub.Hello(HelloStub.java:173)
>>
>> at org.hello.HelloStub.main(HelloStub.java:462)
>>
>>
>>
>> String url =
>> "jms:/Hello?transport.jms.ConnectionFactoryJNDIName=QueueConnectionFactory&java.naming.factory.initial=org.apache.activemq.jndi.ActiveMQInitialContextFactory&java.naming.provider.url=tcp://localhost:61616";
>>
>>
>> HelloStub hStub = new HelloStub(url);
>>
>> HelloResponse hRes = hStub.Hello("Test");
>>
>> System.out.println("Response is " +
>> hRes.getStringout());
>>
>>
>>
>> Can someone please help me with this?
>>
>>
>>
>>
>>
>> Thanks
>>
>>
>>
>> Kamal
>>
>> ============================================================
>> The information contained in this message may be privileged
>> and confidential and protected from disclosure. If the reader
>> of this message is not the intended recipient, or an employee
>> or agent responsible for delivering this message to the
>> intended recipient, you are hereby notified that any reproduction,
>> dissemination or distribution of this communication is strictly
>> prohibited. If you have received this communication in error,
>> please notify us immediately by replying to the message and
>> deleting it from your computer. Thank you. Tellabs
>> ============================================================
>>
>
> --
> Thanks,
> Deepal
> ................................................................
> "The highest tower is built one brick at a time"
>
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: axis-user-unsubscribe@ws.apache.org
> For additional commands, e-mail: axis-user-help@ws.apache.org
>
>
---------------------------------------------------------------------
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For additional commands, e-mail: axis-user-help@ws.apache.org
Re: Transport out has not been set
Posted by Deepal Jayasinghe <de...@opensource.lk>.
May be you have not added dependent jars which JMS required to the
classpath.
Thanks
Deepal
Kang, Kamaljeet K. wrote:
>
> Hi,
>
>
>
> I am trying to test axis2 with JMS transport. I followed the
> instructions as per ‘jms-transport.html’. The server initializes fine
> and I see the JMS queue gets created on the JMS broker but when I try
> to call a method on stub I get the following exception.
>
>
>
> org.apache.axis2.AxisFault: Transport out has not been set
>
> at
> org.apache.axis2.engine.AxisEngine.send(AxisEngine.java:507)
>
> at
> org.apache.axis2.description.OutInAxisOperationClient.send(OutInAxisOperation.java:309)
>
> at
> org.apache.axis2.description.OutInAxisOperationClient.execute(OutInAxisOperation.java:273)
>
> at org.hello.HelloStub.Hello(HelloStub.java:173)
>
> at org.hello.HelloStub.main(HelloStub.java:462)
>
>
>
> String url =
> "jms:/Hello?transport.jms.ConnectionFactoryJNDIName=QueueConnectionFactory&java.naming.factory.initial=org.apache.activemq.jndi.ActiveMQInitialContextFactory&java.naming.provider.url=tcp://localhost:61616";
>
>
> HelloStub hStub = new HelloStub(url);
>
> HelloResponse hRes = hStub.Hello("Test");
>
> System.out.println("Response is " +
> hRes.getStringout());
>
>
>
> Can someone please help me with this?
>
>
>
>
>
> Thanks
>
>
>
> Kamal
>
> ============================================================
> The information contained in this message may be privileged
> and confidential and protected from disclosure. If the reader
> of this message is not the intended recipient, or an employee
> or agent responsible for delivering this message to the
> intended recipient, you are hereby notified that any reproduction,
> dissemination or distribution of this communication is strictly
> prohibited. If you have received this communication in error,
> please notify us immediately by replying to the message and
> deleting it from your computer. Thank you. Tellabs
> ============================================================
>
--
Thanks,
Deepal
................................................................
"The highest tower is built one brick at a time"
---------------------------------------------------------------------
To unsubscribe, e-mail: axis-user-unsubscribe@ws.apache.org
For additional commands, e-mail: axis-user-help@ws.apache.org
Transport out has not been set
Posted by "Kang, Kamaljeet K." <Ka...@tellabs.com>.
Hi,
I am trying to test axis2 with JMS transport. I followed the
instructions as per 'jms-transport.html'. The server initializes fine
and I see the JMS queue gets created on the JMS broker but when I try to
call a method on stub I get the following exception.
org.apache.axis2.AxisFault: Transport out has not been set
at
org.apache.axis2.engine.AxisEngine.send(AxisEngine.java:507)
at
org.apache.axis2.description.OutInAxisOperationClient.send(OutInAxisOper
ation.java:309)
at
org.apache.axis2.description.OutInAxisOperationClient.execute(OutInAxisO
peration.java:273)
at org.hello.HelloStub.Hello(HelloStub.java:173)
at org.hello.HelloStub.main(HelloStub.java:462)
String url =
"jms:/Hello?transport.jms.ConnectionFactoryJNDIName=QueueConnectionFacto
ry&java.naming.factory.initial=org.apache.activemq.jndi.ActiveMQInitialC
ontextFactory&java.naming.provider.url=tcp://localhost:61616";
HelloStub hStub = new HelloStub(url);
HelloResponse hRes = hStub.Hello("Test");
System.out.println("Response is " +
hRes.getStringout());
Can someone please help me with this?
Thanks
Kamal
============================================================
The information contained in this message may be privileged
and confidential and protected from disclosure. If the reader
of this message is not the intended recipient, or an employee
or agent responsible for delivering this message to the
intended recipient, you are hereby notified that any reproduction,
dissemination or distribution of this communication is strictly
prohibited. If you have received this communication in error,
please notify us immediately by replying to the message and
deleting it from your computer. Thank you. Tellabs
============================================================
Re: Need deply new web service in tomcat server.
Posted by Praveen Kumar <pd...@gmail.com>.
Thanks for info.
On 6/13/07, Raghu Upadhyayula <ru...@responsys.com> wrote:
>
> Praveen,
>
>
>
> You can get the wsdl from the webservice URL. In your
> browser, type the webservices url followed by ?wsdl
>
>
>
> In your case, if the webservices URL is
> http://something.something.com/xxxxx/WebServiceName then type
> http://something.something.com/xxxxx/WebServiceName?wsdl in your browser
> to get to the wsdl.
>
>
>
> Thanks
>
> Raghu
>
>
> ------------------------------
>
> *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> *Sent:* Tuesday, June 12, 2007 7:20 AM
> *To:* axis-user@ws.apache.org
> *Subject:* Re: Need deply new web service in tomcat server.
>
>
>
> Hi ,
>
> I have gone the link.
>
> For that we need either wsdl or java file. but i don't have any wsdl
> file or java file.
>
> but i have only one url and web service name !!
>
> As i am new to this , am asking ,
>
> pls help me !!!
>
>
>
>
> On 6/12/07, *Praveen Kumar* <pd...@gmail.com> wrote:
>
> will work on this!!
>
> Thanks
> Praveen
>
>
>
> On 6/12/07, *Raghupathy, Gurumoorthy* <Gurumoorthy.Raghupathy@nielsen.com >
> wrote:
>
> Then why do you need to install axis into tomcat ?
>
>
>
> Have you tried to use http://ws.apache.org/axis/java/ant/ant.html tool ?
>
>
>
> This tool will generate the needful client classes so as to enable use
> remote webservices as plain java classes ….
>
>
>
> Then hey presto you can just use plain pojo to invoke your webservices
>
>
>
> Guru
> ------------------------------
>
> *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> *Sent:* 12 June 2007 14:10
> *To:* axis-user@ws.apache.org
> *Subject:* Re: Need deply new web service in tomcat server.
>
>
>
> They have given URL and web service name and input string format.
>
> That means i am client for that web application.
>
> On 6/12/07, *Raghupathy, Gurumoorthy *<Gu...@nielsen.com>
> wrote:
>
> Do you want to use a web service provided by another provider?
>
> That means you are the client ….
>
>
>
> Can you tell me if this is correct ?
>
>
>
>
> ------------------------------
>
> *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> *Sent:* 12 June 2007 13:50
> *To:* axis-user@ws.apache.org
> *Subject:* Need deply new web service in tomcat server.
>
>
>
> Hi All,
>
> I need to talk with other web application from my my application
>
> They have given one hyperlink saying http///xxxx.com/hhhh/axis
> and webservice name getMethodname and asked me to send XML string.
>
> So i started working on this.First i deployed axis(1.4) dir to my
> webapps/dir and started working on samples. means the /axis/XXXX at IE.
> and i have read the documentation at axis web site.
>
>
> pls help me how to code this one !!
>
> Thanks
> Praveen.
>
>
>
>
>
>
>
>
>
>
>
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
--
Thanks
Domma Raju Praveen Kumar.
RE: Need deply new web service in tomcat server.
Posted by Raghu Upadhyayula <ru...@responsys.com>.
Praveen,
You can get the wsdl from the webservice URL. In your
browser, type the webservices url followed by ?wsdl
In your case, if the webservices URL is
http://something.something.com/xxxxx/WebServiceName then type
http://something.something.com/xxxxx/WebServiceName?wsdl in your browser
to get to the wsdl.
Thanks
Raghu
________________________________
From: Praveen Kumar [mailto:pdommara@gmail.com]
Sent: Tuesday, June 12, 2007 7:20 AM
To: axis-user@ws.apache.org
Subject: Re: Need deply new web service in tomcat server.
Hi ,
I have gone the link.
For that we need either wsdl or java file. but i don't have any wsdl
file or java file.
but i have only one url and web service name !!
As i am new to this , am asking ,
pls help me !!!
On 6/12/07, Praveen Kumar <pd...@gmail.com> wrote:
will work on this!!
Thanks
Praveen
On 6/12/07, Raghupathy, Gurumoorthy <Gurumoorthy.Raghupathy@nielsen.com
> wrote:
Then why do you need to install axis into tomcat ?
Have you tried to use http://ws.apache.org/axis/java/ant/ant.html tool ?
This tool will generate the needful client classes so as to enable use
remote webservices as plain java classes ....
Then hey presto you can just use plain pojo to invoke your webservices
Guru
________________________________
From: Praveen Kumar [mailto:pdommara@gmail.com]
Sent: 12 June 2007 14:10
To: axis-user@ws.apache.org
Subject: Re: Need deply new web service in tomcat server.
They have given URL and web service name and input string format.
That means i am client for that web application.
On 6/12/07, Raghupathy, Gurumoorthy <Gu...@nielsen.com>
wrote:
Do you want to use a web service provided by another provider?
That means you are the client ....
Can you tell me if this is correct ?
________________________________
From: Praveen Kumar [mailto:pdommara@gmail.com]
Sent: 12 June 2007 13:50
To: axis-user@ws.apache.org
Subject: Need deply new web service in tomcat server.
Hi All,
I need to talk with other web application from my my application
They have given one hyperlink saying http///xxxx.com/hhhh/axis
and webservice name getMethodname and asked me to send XML string.
So i started working on this.First i deployed axis(1.4) dir to my
webapps/dir and started working on samples. means the /axis/XXXX at IE.
and i have read the documentation at axis web site.
pls help me how to code this one !!
Thanks
Praveen.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.
Re: Need deply new web service in tomcat server.
Posted by Praveen Kumar <pd...@gmail.com>.
Hi ,
I have gone the link.
For that we need either wsdl or java file. but i don't have any wsdl file
or java file.
but i have only one url and web service name !!
As i am new to this , am asking ,
pls help me !!!
On 6/12/07, Praveen Kumar <pd...@gmail.com> wrote:
>
> will work on this!!
>
> Thanks
> Praveen
>
> On 6/12/07, Raghupathy, Gurumoorthy <Gurumoorthy.Raghupathy@nielsen.com >
> wrote:
> >
> > Then why do you need to install axis into tomcat ?
> >
> >
> >
> > Have you tried to use http://ws.apache.org/axis/java/ant/ant.html tool ?
> >
> >
> >
> > This tool will generate the needful client classes so as to enable use
> > remote webservices as plain java classes ….
> >
> >
> >
> > Then hey presto you can just use plain pojo to invoke your webservices
> >
> >
> >
> > Guru
> > ------------------------------
> >
> > *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> > *Sent:* 12 June 2007 14:10
> > *To:* axis-user@ws.apache.org
> > *Subject:* Re: Need deply new web service in tomcat server.
> >
> >
> >
> > They have given URL and web service name and input string format.
> >
> > That means i am client for that web application.
> >
> >
> > On 6/12/07, *Raghupathy, Gurumoorthy *<
> > Gurumoorthy.Raghupathy@nielsen.com> wrote:
> >
> > Do you want to use a web service provided by another provider?
> >
> > That means you are the client ….
> >
> >
> >
> > Can you tell me if this is correct ?
> >
> >
> >
> >
> > ------------------------------
> >
> > *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> > *Sent:* 12 June 2007 13:50
> > *To:* axis-user@ws.apache.org
> > *Subject:* Need deply new web service in tomcat server.
> >
> >
> >
> > Hi All,
> >
> > I need to talk with other web application from my my application
> >
> > They have given one hyperlink saying http///xxxx.com/hhhh/axis
> > and webservice name getMethodname and asked me to send XML string.
> >
> > So i started working on this.First i deployed axis(1.4) dir to my
> > webapps/dir and started working on samples. means the /axis/XXXX at IE.
> > and i have read the documentation at axis web site.
> >
> >
> > pls help me how to code this one !!
> >
> > Thanks
> > Praveen.
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
> > --
> > Thanks
> > Domma Raju Praveen Kumar.
> >
> > --
> > Thanks
> > Domma Raju Praveen Kumar.
> >
> >
> >
> >
> > --
> > Thanks
> > Domma Raju Praveen Kumar.
> >
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
--
Thanks
Domma Raju Praveen Kumar.
Re: Need deply new web service in tomcat server.
Posted by Praveen Kumar <pd...@gmail.com>.
will work on this!!
Thanks
Praveen
On 6/12/07, Raghupathy, Gurumoorthy <Gu...@nielsen.com>
wrote:
>
> Then why do you need to install axis into tomcat ?
>
>
>
> Have you tried to use http://ws.apache.org/axis/java/ant/ant.html tool ?
>
>
>
> This tool will generate the needful client classes so as to enable use
> remote webservices as plain java classes ….
>
>
>
> Then hey presto you can just use plain pojo to invoke your webservices
>
>
>
> Guru
> ------------------------------
>
> *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> *Sent:* 12 June 2007 14:10
> *To:* axis-user@ws.apache.org
> *Subject:* Re: Need deply new web service in tomcat server.
>
>
>
> They have given URL and web service name and input string format.
>
> That means i am client for that web application.
>
>
> On 6/12/07, *Raghupathy, Gurumoorthy *<Gu...@nielsen.com>
> wrote:
>
> Do you want to use a web service provided by another provider?
>
> That means you are the client ….
>
>
>
> Can you tell me if this is correct ?
>
>
>
>
> ------------------------------
>
> *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> *Sent:* 12 June 2007 13:50
> *To:* axis-user@ws.apache.org
> *Subject:* Need deply new web service in tomcat server.
>
>
>
> Hi All,
>
> I need to talk with other web application from my my application
>
> They have given one hyperlink saying http///xxxx.com/hhhh/axis
> and webservice name getMethodname and asked me to send XML string.
>
> So i started working on this.First i deployed axis(1.4) dir to my
> webapps/dir and started working on samples. means the /axis/XXXX at IE.
> and i have read the documentation at axis web site.
>
>
> pls help me how to code this one !!
>
> Thanks
> Praveen.
>
>
>
>
>
>
>
>
>
>
>
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
--
Thanks
Domma Raju Praveen Kumar.
Re: Need deply new web service in tomcat server.
Posted by Duncan Thomson <du...@mitre.org>.
Praveen Kumar wrote:
> They have given URL and web service name and input string format.
>
> That means i am client for that web application.
If you are just trying to code a client, all you need is something to generate "stub" code that will build a SOAP message, send it for you, and then interpret the response.
There are a couple of ways to do this. One, as someone else has mentioned, is to use the Axis tools to generate your stub code. (You do NOT need to actually have axis deployed to a web server to do this, you just need to run the client code generation tools.)
Another way is to use an IDE that knows how to create web service clients. I have not had good luck with the Eclipse IDE and associated web service development packages.
I suggest you look into using the Netbeans IDE. If you haven't used Netbeans before, you will need to spend some time working through the tutorials and getting used to the tool. However, in my opinion, it's well worth it. The latest version is Netbeans 5.5.1. Also download and install the "Netbeans Enterprise Pack" - or have your sysadmin support do this for you. Then, assuming you're programming in Java, just create a new project, and tell Netbeans you want to add a web service client. It will ask you for the WSDL of the web service. This is probably the URL you have been given. It should be of the form http://bla.bla.com/ServiceName?WSDL. Just give that to the IDE and let it generate all the stub code for you. You'll then be able to drag and drop the web services operations into your java code, and it will generate for you all the details you need to invoke the web service operations.
Others will have different opinions regarding the best IDE to use, but I can tell you that when it comes to developing web services and web service clients, the latest Netbeans tools do a very good job. Depending on your level of experience, expect a few weeks of learning time, after which you should be able to crank out the code to access web services in, literally, about 2 minutes.
Good luck.
Duncan
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RE: Need deply new web service in tomcat server.
Posted by "Raghupathy, Gurumoorthy" <Gu...@nielsen.com>.
Then why do you need to install axis into tomcat ?
Have you tried to use http://ws.apache.org/axis/java/ant/ant.html tool ?
This tool will generate the needful client classes so as to enable use
remote webservices as plain java classes ....
Then hey presto you can just use plain pojo to invoke your webservices
Guru
________________________________
From: Praveen Kumar [mailto:pdommara@gmail.com]
Sent: 12 June 2007 14:10
To: axis-user@ws.apache.org
Subject: Re: Need deply new web service in tomcat server.
They have given URL and web service name and input string format.
That means i am client for that web application.
On 6/12/07, Raghupathy, Gurumoorthy <Gu...@nielsen.com>
wrote:
Do you want to use a web service provided by another provider?
That means you are the client ....
Can you tell me if this is correct ?
________________________________
From: Praveen Kumar [mailto:pdommara@gmail.com]
Sent: 12 June 2007 13:50
To: axis-user@ws.apache.org
Subject: Need deply new web service in tomcat server.
Hi All,
I need to talk with other web application from my my application
They have given one hyperlink saying http///xxxx.com/hhhh/axis
and webservice name getMethodname and asked me to send XML string.
So i started working on this.First i deployed axis(1.4) dir to my
webapps/dir and started working on samples. means the /axis/XXXX at IE.
and i have read the documentation at axis web site.
pls help me how to code this one !!
Thanks
Praveen.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.
Re: Need deply new web service in tomcat server.
Posted by Praveen Kumar <pd...@gmail.com>.
They have given URL and web service name and input string format.
That means i am client for that web application.
On 6/12/07, Raghupathy, Gurumoorthy <Gu...@nielsen.com>
wrote:
>
> Do you want to use a web service provided by another provider?
>
> That means you are the client ….
>
>
>
> Can you tell me if this is correct ?
>
>
>
>
> ------------------------------
>
> *From:* Praveen Kumar [mailto:pdommara@gmail.com]
> *Sent:* 12 June 2007 13:50
> *To:* axis-user@ws.apache.org
> *Subject:* Need deply new web service in tomcat server.
>
>
>
> Hi All,
>
> I need to talk with other web application from my my application
>
> They have given one hyperlink saying http///xxxx.com/hhhh/axis
> and webservice name getMethodname and asked me to send XML string.
>
> So i started working on this.First i deployed axis(1.4) dir to my
> webapps/dir and started working on samples. means the /axis/XXXX at IE.
> and i have read the documentation at axis web site.
>
>
> pls help me how to code this one !!
>
> Thanks
> Praveen.
>
>
>
>
>
>
>
>
>
>
>
>
>
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
> --
> Thanks
> Domma Raju Praveen Kumar.
>
--
Thanks
Domma Raju Praveen Kumar.
RE: Need deply new web service in tomcat server.
Posted by "Raghupathy, Gurumoorthy" <Gu...@nielsen.com>.
Do you want to use a web service provided by another provider?
That means you are the client ....
Can you tell me if this is correct ?
________________________________
From: Praveen Kumar [mailto:pdommara@gmail.com]
Sent: 12 June 2007 13:50
To: axis-user@ws.apache.org
Subject: Need deply new web service in tomcat server.
Hi All,
I need to talk with other web application from my my application
They have given one hyperlink saying http///xxxx.com/hhhh/axis
and webservice name getMethodname and asked me to send XML string.
So i started working on this.First i deployed axis(1.4) dir to my
webapps/dir and started working on samples. means the /axis/XXXX at IE.
and i have read the documentation at axis web site.
pls help me how to code this one !!
Thanks
Praveen.
--
Thanks
Domma Raju Praveen Kumar.
--
Thanks
Domma Raju Praveen Kumar.