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Posted to users@camel.apache.org by Zoran Regvart <zo...@regvart.com> on 2018/11/20 10:46:34 UTC

Re: Camel spring DSL validaiton

Hi Vineet,
you could gather all `RouteDefinition` objects from that
`RoutesDefinition` you get from `CamelContext::loadRoutesDefinition`,
use `RouteDefinitionHelper::gatherAllEndpointUris` to fetch all
endpoint URIs of that `RouteDefinition` and then try to resolve those
endpoints via `CamelContextHelper::getMandatoryEndpoint`.

Not sure if there is a more straightforward way of doing that,

zoran
On Tue, Nov 20, 2018 at 10:51 AM Gandhi, Vineet <vi...@optum.com> wrote:
>
> Hi,
>
> I have a use case where clients can send route xml files to my service which I add to camelContext
>
> Code for adding route looks like :
>
> public void createRoute(InputStream xmlRouteDefinition) throws Exception {
>
>
>
>               RoutesDefinition routesDefinition = camelContext.loadRoutesDefinition(xmlRouteDefinition);
>
>               camelContext.addRouteDefinitions(routesDefinition.getRoutes());
>
>        }
>
> Client can pass the following routes too –
>
> <?xml version="1.0" encoding="UTF-8"?>
> <routes xmlns="http://camel.apache.org/schema/spring">
> <route id="route13" autoStartup="false">
>     <from uri="anystring:start13"/>
>     <to uri="aaaaaaaaaaa:result13"/>
> </route>
> </routes>
>
> Is there any way of validating whether the components and their corresponding URI’s are correctly passed without calling the startRoute API in DefaultCamelContext?
>
> Regards,
> Vineet
>
>
> This e-mail, including attachments, may include confidential and/or
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-- 
Zoran Regvart

Re: Camel spring DSL validaiton

Posted by "Gandhi, Vineet" <vi...@optum.com>.
Hi Zoran,

Thanks for prompt reply.
This works for me.

Regards,
Vineet

On 20/11/18, 4:17 PM, "Zoran Regvart" <zo...@regvart.com> wrote:

    Hi Vineet,
    you could gather all `RouteDefinition` objects from that
    `RoutesDefinition` you get from `CamelContext::loadRoutesDefinition`,
    use `RouteDefinitionHelper::gatherAllEndpointUris` to fetch all
    endpoint URIs of that `RouteDefinition` and then try to resolve those
    endpoints via `CamelContextHelper::getMandatoryEndpoint`.
    
    Not sure if there is a more straightforward way of doing that,
    
    zoran
    On Tue, Nov 20, 2018 at 10:51 AM Gandhi, Vineet <vi...@optum.com> wrote:
    >
    > Hi,
    >
    > I have a use case where clients can send route xml files to my service which I add to camelContext
    >
    > Code for adding route looks like :
    >
    > public void createRoute(InputStream xmlRouteDefinition) throws Exception {
    >
    >
    >
    >               RoutesDefinition routesDefinition = camelContext.loadRoutesDefinition(xmlRouteDefinition);
    >
    >               camelContext.addRouteDefinitions(routesDefinition.getRoutes());
    >
    >        }
    >
    > Client can pass the following routes too –
    >
    > <?xml version="1.0" encoding="UTF-8"?>
    > <routes xmlns="http://camel.apache.org/schema/spring">
    > <route id="route13" autoStartup="false">
    >     <from uri="anystring:start13"/>
    >     <to uri="aaaaaaaaaaa:result13"/>
    > </route>
    > </routes>
    >
    > Is there any way of validating whether the components and their corresponding URI’s are correctly passed without calling the startRoute API in DefaultCamelContext?
    >
    > Regards,
    > Vineet
    >
    >
    > This e-mail, including attachments, may include confidential and/or
    > proprietary information, and may be used only by the person or entity
    > to which it is addressed. If the reader of this e-mail is not the intended
    > recipient or his or her authorized agent, the reader is hereby notified
    > that any dissemination, distribution or copying of this e-mail is
    > prohibited. If you have received this e-mail in error, please notify the
    > sender by replying to this message and delete this e-mail immediately.
    
    
    
    -- 
    Zoran Regvart
    


This e-mail, including attachments, may include confidential and/or
proprietary information, and may be used only by the person or entity
to which it is addressed. If the reader of this e-mail is not the intended
recipient or his or her authorized agent, the reader is hereby notified
that any dissemination, distribution or copying of this e-mail is
prohibited. If you have received this e-mail in error, please notify the
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