Converting linebreak to
?

[Stephan Coboos <cr...@gmx.net>]

Hello,

I'am using a flowscript to retrieve text from a form's textarea. This 
text may contain some linebreaks \n. Now I want display the content with 
line breaks in a html view. So I need to convert \n to <br/>. For 
displaying the content of the textarea I'am using a JXTemplate. How I 
can I transform linebreaks \n into the element <br/>? If i replace all 
\n with <br/> in the html output I will get only &lt;br/&gt;. So I have 
to include the <br/> into the SAX pipeline, but how? Is there a easy way 
to do so (without building a new rome;-)?

Thank you.

Regards
Stephan



---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@cocoon.apache.org
For additional commands, e-mail: users-help@cocoon.apache.org

Re: Converting linebreak to
?

[Ugo Cei <ug...@apache.org>]

Il giorno 27/mag/04, alle 20:42, Stephan Coboos ha scritto:

> I'am using a flowscript to retrieve text from a form's textarea. This 
> text may contain some linebreaks \n. Now I want display the content 
> with line breaks in a html view. So I need to convert \n to <br/>. For 
> displaying the content of the textarea I'am using a JXTemplate. How I 
> can I transform linebreaks \n into the element <br/>? If i replace all 
> \n with <br/> in the html output I will get only &lt;br/&gt;. So I 
> have to include the <br/> into the SAX pipeline, but how? Is there a 
> easy way to do so (without building a new rome;-)?

   <!--+
       |  Replace newlines with <br>'s
       |  (Credits:  http://www.dpawson.co.uk/xsl/sect2/break.html)
       +-->
         <xsl:template name="substitute">
            <xsl:param name="string" />
            <xsl:param name="from" select="'&#xA;'" />
            <xsl:param name="to">
               <br />
            </xsl:param>
            <xsl:choose>
               <xsl:when test="contains($string, $from)">
                  <xsl:value-of select="substring-before($string, 
$from)" />
                  <xsl:copy-of select="$to" />
                  <xsl:call-template name="substitute">
                     <xsl:with-param name="string"
                                     select="substring-after($string, 
$from)" />
                     <xsl:with-param name="from" select="$from" />
                     <xsl:with-param name="to" select="$to" />
                  </xsl:call-template>
               </xsl:when>
               <xsl:otherwise>
                  <xsl:value-of select="$string" />
               </xsl:otherwise>
            </xsl:choose>
         </xsl:template>

-- 
Ugo Cei - http://beblogging.com/


---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@cocoon.apache.org
For additional commands, e-mail: users-help@cocoon.apache.org

Re: Converting linebreak to
?

[Tony Collen <co...@umn.edu>]

Stephan Coboos wrote:
> Hello,
> 
> I'am using a flowscript to retrieve text from a form's textarea. This 
> text may contain some linebreaks \n. Now I want display the content with 
> line breaks in a html view. So I need to convert \n to <br/>. For 
> displaying the content of the textarea I'am using a JXTemplate. How I 
> can I transform linebreaks \n into the element <br/>? If i replace all 
> \n with <br/> in the html output I will get only &lt;br/&gt;. So I have 
> to include the <br/> into the SAX pipeline, but how? Is there a easy way 
> to do so (without building a new rome;-)?

You could probably write a transformer to do it.

Tony


---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@cocoon.apache.org
For additional commands, e-mail: users-help@cocoon.apache.org

Re: Converting linebreak to
?

[Suzan Foster <su...@nerocmediaware.nl>]

Stephan Coboos wrote:

>I'am using a flowscript to retrieve text from a form's textarea. This 
>text may contain some linebreaks \n. Now I want display the content with 
>line breaks in a html view. So I need to convert \n to <br/>. For 
>displaying the content of the textarea I'am using a JXTemplate. How I 
>can I transform linebreaks \n into the element <br/>? If i replace all 
>\n with <br/> in the html output I will get only &lt;br/&gt;. So I have 
>to include the <br/> into the SAX pipeline, but how? Is there a easy way 
>to do so (without building a new rome;-)?
>  
>
If the text contains no markup which needs to be rendered why not wrap 
it  between pre tags? That would certainly save you from having to worry 
about  newlines.

groetjes, su.

---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@cocoon.apache.org
For additional commands, e-mail: users-help@cocoon.apache.org