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Posted to issues@iceberg.apache.org by GitBox <gi...@apache.org> on 2021/05/10 01:08:37 UTC
[GitHub] [iceberg] openinx opened a new issue #2572: Support creating flink table without creating an explicit hive/hadoop catalog
openinx opened a new issue #2572:
URL: https://github.com/apache/iceberg/issues/2572
After collecting some feedback from our flink users, now we have to create a `catalog` firstly, then switch to the `catalog` and `database` , finally we could create the apache iceberg table under the `catalog`. ( see https://iceberg.apache.org/flink/).
In fact, for most of the flink sql users, the [straightforward way](https://ci.apache.org/projects/flink/flink-docs-release-1.13/docs/connectors/table/overview/#how-to-use-connectors) is : creating a iceberg table with `connector=iceberg` options and catalog properties as the iceberg table properties.
For example if we want to create an iceberg table under a given hive catalog, we could execute:
```sql
CREATE TABLE iceberg_sample (
id BIGINT,
data STRING
) WITH (
'connector'='iceberg',
'catalog-type'='hive',
'uri'='thrift://localhost:9083',
'clients'='5',
'property-version'='1',
'warehouse'='hdfs://nn:8020/warehouse/path'
);
```
If we want to create an iceberg table under a given hadoop catalog, then we could execute:
```sql
CREATE TABLE iceberg_sample(
id BIGINT,
data STRING
) WITH (
'connector'='iceberg',
'catalog-type'='hadoop',
'warehouse'='hdfs://nn:8020/warehouse/path'
);
```
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[GitHub] [iceberg] RussellSpitzer commented on issue #2572: Support creating flink table without creating an explicit hive/hadoop catalog
Posted by GitBox <gi...@apache.org>.
RussellSpitzer commented on issue #2572:
URL: https://github.com/apache/iceberg/issues/2572#issuecomment-836837836
Looks reasonable to me, how does the database work in this situation? Is there just a default database for each catalog?
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